Trevor has 3 baseball cards and 2 football cards. He randomly picks a
card. He then randomly picks a second card from the cards that remain.
What is the probability that Trevor selects only football cards?

Answer:

32

Step-by-step explanation:

We first solve everything in the parenthesis. So: (7 -5) = 2 and (20 - 19) = 1. Now we change the equation:

3[(2)2 +(1)2] + 14

Then we multiply inside the brackets: 2 x 2 = 4 and 1 x 2 = 2. So the equation now looks like this:

3[ 4 + 2] + 14

Now we add:

3{6} + 14:

We multiply:

18 + 14

Finaly we add again:

18 + 14 = 32

Answer:

[tex]1590.6cm {}^{3} [/tex]

Step-by-step explanation:

[tex]volume \: of \: a \: cone \: v = \frac{1}{3}\pi \: r {}^{2} h \\ radius = \frac{diameter}{2} = \frac{15}{2} = 7.5 \\ v = \frac{1}{3} \times 3.42 \times (7.5) {}^{2} \times 27 \\ v = \frac{3.142 \times 7.5 \times 7.5 \times 27}{3} \\ v = \frac{4771.9125}{3} = 1590.6375 \\ v = 1590.6cm {}^{3} (approximatly) \\ please \: rate \: and \: mark \: brainliest[/tex]

The expression that returns the probability that a data value in a normal distribution is between a z- score of -0.18 and a z-score of 1.99 is (d) normalcdf(-0.18, 1.99)

To calculate the probability between two z-scores is to calculate the area between the z-scores.

This is done using the following syntax:

normalcdf(lower bound, upper bound)

From the question, the lower and the upper z-scores are -0.18 and 1.99

So, the formula would be normalcdf(-0.18, 1.99)

Hence, the expression is (d)

Read more about normal distribution at:

https://brainly.com/question/25991460

Here's your Question →

____________________________________

Que → The hieght of The statue of Liberty is 93m. This is about 27% of the Hancove building in Chicago. What is approximate Hieght of Hancove Building?

Answer → Let height of Hancove Building be H.

Now according to question, 27% of H = 93m

27 / 100 (H) = 93m

H = 93 x 100 ÷ 27

H = 344.44m

Therefore, the approximate Hieght of Hancove Building is around 344.4m

Answer:

Step-by-step explanation:

Let the missing height is h.

We have 93 m is 27% of h, need to find the value of h

27% of h is 0.27h, the equation we need is below

Answer:

4

Step-by-step explanation:

12*2=24 would be one for each so multiply 2*2

Answer:

Here is you annswer can you please give brainlist

Step-by-step explanation:

Answer:

that is right

Step-by-step explanation:

yes I can do it

Answer:

D

Step-by-step explanation:

Since  the cost of making backpack is $10 They have a pprfit of $30 for each  one(30x)

But they also have $12,000 operaing expenses (-12,000)

And all that should be 980 or more than that      (≥)

30x-12,000 ≥ 980

Answer:

800 in squared

Step-by-step explanation:

16*16+4*0.5*17*16

First term, a = 6

Common difference, d = 4

Using the formula :

an = a + (n - 1) d

an = 6 + (n - 1) 4

an = 6 + 4n - 4

an = 2 + 4n

nth term = 2+4n

Answer:

C:

1/64

Step-by-step explanation:

Answer:

(7x+5) is the length of the square

Step-by-step explanation:

(a+b)^2

= a^2 + 2ab + B^2

Substituite values in and you will find this

Answer:

360

Step-by-step explanation:

9x4=36 add the zero you didn't use

Answer:

10

Step-by-step explanation:

here it is

the explanation is in the photo

Answer:

1/10

Step-by-step explanation:

Because there are 10 markers and only one is yellow. so you have a one in ten chance to pull a yellow marker.

Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Also remember to rate answers to help other students, While leaving thanks to answers that help you. Have a great day!

Answer:

1/10

Step-by-step explanation:

because there is 10 markers total and 1 of them is yellow

Answer:

a. probability of 5/9
b. probability of 3/9

Step-by-step explanation:

All possible outcomes:

1 x 1 = 1
1 x 2 = 2
1 x 3 = 3
2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
3 x 1 = 3
3 x 2 = 6
3 x 3 = 9

All outcomes with an even number:

1 x 2 = 2
2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
3 x 2 = 6

All outcomes with a number greater than 5

2 x 3 = 6
3 x 2 = 6
3 x 3 = 9

Answer: 44 degrees

Step-by-step explanation:

Answer:

[tex]\tan(X)=\dfrac{77}{36}[/tex]

Step-by-step explanation:

First we need to find the length of side WX.

To do this, use Pythagoras' Theorem:  [tex]a^2+b^2=c^2[/tex]

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

[tex]\implies WX^2+77^2=85^2[/tex]

[tex]\implies WX^2=85^2-77^2[/tex]

[tex]\implies WX=\sqrt{85^2-77^2}[/tex]

[tex]\implies WX=36[/tex]

Now use the Tan trig ratio:

[tex]\tan(x)=\sf \dfrac{O}{A}[/tex]

where:

From inspection of the triangle,

Substituting these values into the tan trig formula:

[tex]\implies \tan(X)=\dfrac{77}{36}[/tex]

Therefore, the tangent of ∠X is [tex]\dfrac{77}{36}[/tex]

Answer:

77 / 36

Step-by-step explanation:

Finding the adjacent side

Tangent of ∠X

Answer:

No.

Step-by-step explanation:

You are trying to solve for x. Note the equal sign, what you do to one side, you do to the other. Add 4 to both sides of the equation to isolate the variable, x:

-4 + x = 10

-4 (+4) + x = 10 (+4)

x = 10 +4

x = 14

x = 14, x ≠ 13, ∴ 13 is not a solution.

~

Answer:

$5.25

Step-by-step explanation:

here,

4pounds off apple cost $7

3 pounds of apple will cost 3×7/4= 21/4=$5.25

Answer:

[tex]2x(x+3)(x + 4)[/tex]

Step-by-step explanation:

To factor [tex]2x^3+14x^2+24x[/tex]

First, factor out the common term [tex]2x[/tex]:

[tex]\implies 2x(x^2+7x+12)[/tex]

Now factor the expression in the parantheses:  [tex]x^2+7x+12[/tex]

Find two numbers that multiply to 12 and sum to 7:  3 and 4

Rewrite [tex]7x[/tex] as the sum of these 2 numbers:

[tex]\implies x^2+3x + 4x+12[/tex]

Factorize the first two terms and the last two terms separately:

[tex]\implies x(x+3) + 4(x+3)[/tex]

Factor out the common term [tex](x+3)[/tex]:

[tex]\implies (x+3)(x + 4)[/tex]

Therefore, the final factorization of the polynomial is:

[tex]\implies 2x (x+3)(x + 4)[/tex]

Let's factor up

So

[Can be interchanged]

Answer:

6,4 or A

Step-by-step explanation:

Its basic 2,6 is 64,  4,3 is 64, and 8,2 is 64

Brainliest?

Answer:

6,4

Step-by-step explanation:

6*6*6*6= 1296

6 to the fourth power does not equal 64.

Answer:

It shows a deficit of $261

Step-by-step explanation:

$32,508/12 = $2709 per month

$2709 - ($1860 + $860 + $259) = -$270

I'm assuming you put a typo somewhere, but the closest answer is the deficit of $261

Reason:

Triangles A, B and E all have the angles 68 and 79 with a 3 unit side sandwiched between them. We can use the angle side angle (ASA) congruence theorem to prove those three triangles are identical copies of each other. They are rotated, reflected and shifted versions of one another. These tranformations are known as rigid transformations or isometries.

On the other hand, we can rule out choice C because the side between the angles is not 3 units long (even though the angles do match up). The same goes for choice D.

Answer:

the answer is $388.125 using the formula I=PRT/100

it is up to you to find to the nearest cent

Answer:

1,005cm²

Step-by-step explanation:

First, you need to know the area of a cylinder and also the value of pi.

Area = 2πrh

pi = π = 3.14

r = radius = 80cm

h = height of cylinder = 20

now let's substitute

[tex]2 \times 3.14 \times 80 \times 20 = 1004.9{cm}^{2} [/tex]

but to the nearest square centimetre is.

1005cm²

because the number after the point is more than 4 so we add one to the last number before the point.

Answer:

B Building = 865 feet,   A Building = 665 feet.

Step-by-step explanation:

If you divide 1530 by 2 you get 765, if you add 100 to 765, and subtract 100 from 865, there is a 200 feet difference from each of the buildings.

Answer:

1.28!

Step-by-step explanation:

hope this helps, let me know if you need an explination! :)

Recall that

[tex]\dfrac{d}{dx}\left[\cot(x)\right] = -\csc^2(x)[/tex]

so that

[tex]\displaystyle \int \frac{dx}{\sin^2\left(\frac{x-2}3\right)} = \int \csc^2\left(\frac{x-2}3\right) \, dx = \boxed{-3 \cot\left(\frac{x-2}3\right) + C}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \bf{Your \ exercise \ is \to\int\limits \frac{1}{sin^2\left(\dfrac{x-2}{3}\right) }dx } \end{gathered}$}[/tex]

             [tex]\boldsymbol{Replaces \ u=\dfrac{x-2}{3} \longmapsto \dfrac{du}{dx}=\dfrac{1}{3} \longmapsto \ dx=3 \ du }[/tex]

                                               [tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{=\int\limits \frac{3}{Sin^2(u) }du } \end{gathered}$}[/tex]

                                                    [tex]\boldsymbol{\sf{Simplify }}[/tex]

                                              [tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{=3\int\limits csc^2(u)du } \end{gathered}$}[/tex]

                                                    [tex]\boldsymbol{\sf{Solving \ now }}[/tex]

                                                    [tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{\int\limits csc^2(u)du } \end{gathered}$}[/tex]

                                            [tex]\boldsymbol{\sf{This\:is\:a\:standard\:integral. }}[/tex]

                                                     [tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{=-cot(u)} \end{gathered}$}[/tex]

                                       [tex]\boldsymbol{\sf{We\:replace\:the\:integrals\:already\:solved. }}[/tex]

                                                   [tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{=\int\limits \frac{3}{Sin^2(u) }du } \end{gathered}$}[/tex]

                                                      [tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{=-cot(u)} \end{gathered}$}[/tex]

                                      [tex]\boldsymbol{The\:substitution\:is\:undone\: u=\dfrac{x-2}{3} ;}[/tex]

                                                      [tex]\large\displaystyle\text{$\begin{gathered}\sf \boldsymbol{=-3cot\left(\frac{x-2}{3}\right) } \end{gathered}$}[/tex]

       [tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf Answer \longmapsto \bf{\int\limits \dfrac{1}{sin^2\left(\dfrac{x-2}{3}\right) }dx }=\boldsymbol{ -3cot\left(\frac{x-2}{3}\right)+C } \end{gathered}$}}[/tex]

[tex]\large\displaystyle\text{$\begin{gathered}\sf \underline{\bf{\green{I\:hope \ it \ helps \ you..... Regards }}} \end{gathered}$}[/tex]