Answer:
False
Step-by-step explanation:
Graphing tells you where the solution of the system, or graph intersection occurs no matter what. You can have a quadratic and exponential function -- graphing will always show you where they intersect (or don't!)
BRAINLIEST please if this helped!Answer:
false
Step-by-step explanation:
hope this helps
How many times larger is 8 x 10^9 than 4 x 10^3
Answer:
600
Step-by-step explanation:
10x9 =90
10x3=30
8x90=720
4x30=120
720-120= 600
3. The math exam scores for a class are shown below.
a
Make a data display. What percent of the scores are 90
and greater?
24, 68, 83, 75, 81, 99, 98, 80, 85, 70, 89, 92, 77, 96,
180, 64, 88, 96, 76, 88
Answer:
30 percent of the scores are 90 and greater
Which choice is the solution to the inequality below?
8x < 24
O A. x< 24
O B. x> 24
C. x>3
O D. x<3
Answer:
D
Step-by-step explanation:
8x < 24
divide both sides by the coefficient of x
8x/8 < 24/8
x < 3
Look at this rectangle. Find the value of u.
Answer:
1 inch
Step-by-step explanation:
We know that opposite sides of a rectangle are equal to each other.
Given that,
Perimeter = 30 in
Therefore,
u + u + 14 + 14 = 30
2u + 28 = 30
2u = 30 - 28
2u = 2
Divide both sides by 2.
u = 1 in
Sketch advertising firm charges $150 to design a full-color flyer and 12 cents per flyer to print the flyer. Rose's Sweet Shop spent $192 on the flyers for the grand opening. How many Flyers did she buy?
Answer:
210
Step-by-step explanation:
First, we keep $150 on the back of our minds(or our paper).
Second, we would assume that Rose's would've designed the flyer at $150, making us determine how much flyers they bought for the remaining $42.
($192 - $150 = $42)
Now that we know all of this, we can begin.
12 x 5 is 60, so 60 cents makes 1 dollar.
So for every dollar, they can make 5 flyers.
If we do 5 x 42, we'll get the answer of 210, which is the amount of flyers she bought!
a 8 1/2 foot board Is cut Into 2 1/2 foot lengths. how many sections will you have
Answer:
3 whole but 3.4 as a decimal
Step-by-step explanation:
Which real-world scenario involves a right triangle?
Answer:
There are a few different scenarios
Step-by-step explanation:
Bathroom Tiles,Kitchen flooringTriangle Backsplash ( tile behind your sink in kitchenDrywall work if you need right edges, you will need a right triangleFinally any sort of contracting and Deck workFROM- THE GENIUS ANSWERER
Find the arc length of the partial circle.
Either enter an exact answer in terms of π or use 3.14 for π and enter your answer as a decimal.
Explanation:
A full circle of radius r has a circumference of 2pi*r which is the perimeter aka distance around the circle's edge.
We divide that by 4 to get the arc length of the quarter circle and we'd get to (2pi*r)/4 = 0.5pi*r
Plug in r = 1 and pi = 3.14
0.5*pi*r = 0.5*3.14*1 = 1.57
Solve the system of equations.
Answer:
3x+2y=24
Y=3
Substitute in the equation
3x+2(3)=24
3x+6=24
3x=24-6
3x=18
X=18/3
X=6
Ellie left her house and drove to the store. She stopped and went inside. From
there, she drove in the same direction until she got to the bank. She stopped
and went inside the bank. Then she drove home. The graph below shows the
number of blocks away from home Ellie is x minutes after she left her house,
until she got back home.
Answer:
Ellie spent 21 minutes after she left her house until she got back home
Evaluate this:
[tex]\displaystyle\rm\int_0^\frac{\pi}{2}\sqrt{\sin x}\ dx \times \int_0^\frac{\pi}{2}\frac{1}{\sqrt{\sin x}}\ dx[/tex]
Only elementary methods are allowed.
The first integral has a well-known beta function representation, so the second one should too. The beta function itself is defined as
[tex]B(x,y) = \displaystyle \int_0^1 t^{x-1} (1-t)^{y-1} \, dt[/tex]
and satisfies the identity
[tex]\displaystyle B(x,y) = \frac{\Gamma(x) \Gamma(y)}{\Gamma(x+y)}[/tex]
Later on, we'll also use the so-called reflection formula for the gamma function; for non-integer z,
[tex]\Gamma(z) \Gamma(1-z) = \dfrac{\pi}{\sin(\pi z)}[/tex]
as well as the identity
[tex]\dfrac{\Gamma(z+1)}{\Gamma(z)} = z[/tex]
Replace [tex]x\to\sin^{-1}(x)[/tex] in both integrals, so that
[tex]\displaystyle \int_0^{\frac\pi2} \sqrt{\sin(x)} \, dx = \int_0^1 \frac{\sqrt x}{\sqrt{1-x^2}} \, dx[/tex]
[tex]\displaystyle \int_0^{\frac\pi2} \frac{dx}{\sqrt{\sin(x)}} = \int_0^1 \frac{dx}{\sqrt x \sqrt{1-x^2}}[/tex]
Now replace [tex]x\to\sqrt x[/tex] :
[tex]\displaystyle \int_0^1 \frac{\sqrt x}{\sqrt{1-x^2}} \, dx = \frac12 \int_0^1 x^{-\frac14} (1-x)^{-\frac12} \, dx = \frac12 B\left(\frac34, \frac12\right) [/tex]
[tex]\displaystyle \int_0^1 \frac{dx}{\sqrt x \sqrt{1-x^2}} = \frac12 \int_0^1 x^{-\frac34} (1-x)^{-\frac12} \, dx = \frac12 B\left(\frac14, \frac12\right)[/tex]
So, the original integral (which I condense here to a double integral) is
[tex]\displaystyle \int_0^{\frac\pi2} \int_0^{\frac\pi2} \sqrt{\frac{\sin(x)}{\sin(y)}} \, dx \, dy = \frac14 B\left(\frac34, \frac12\right) B\left(\frac14, \frac12\right)[/tex]
[tex]\displaystyle = \frac14 \frac{\Gamma\left(\frac14\right) \Gamma\left(\frac34\right) \Gamma\left(\frac12\right)^2}{\Gamma\left(\frac54\right) \Gamma\left(\frac34\right)}[/tex]
[tex]\displaystyle = \frac14 \frac{\Gamma\left(\frac14\right) \Gamma\left(\frac34\right) \Gamma\left(\frac12\right)^2}{\frac14 \Gamma\left(\frac14\right) \Gamma\left(\frac34\right)}[/tex]
[tex]\displaystyle = \Gamma\left(\frac12\right)^2 = \frac{\pi}{\sin\left(\frac\pi2\right)} = \boxed{\pi}[/tex]
What is the area of this trapezoid?
Answer:
The area is [tex]80[/tex]
Step-by-step explanation:
rectangle in the middle; 24
both triangles on the side; 56
In total; 80
Which expression is equivalent to 2(5z+3)?
Answer:
D
Step-by-step explanation:
That expression equals :
10z+6
So, now we need to find one of the expressions that ALSO gives us 10z+6
D
This is because:
2*3z=6z
2*2z=4z
----------------------
6z+4z=10z, so we got that one so far.
NEXT
2*3=6.
We got the 6 too!
it is d
what is the inverse of f(x)=2(3^x)
If [tex]f^{-1}(x)[/tex] is the inverse of [tex]f(x)[/tex], then by definition
[tex]f\left(f^{-1}(x)\right) = x[/tex]
so that
[tex]2 \times 3^{f^{-1}(x)} = x[/tex]
Solve for [tex]f^{-1}(x)[/tex] :
[tex]3^{f^{-1}(x)} = \dfrac x2[/tex]
[tex]\log_3\left(3^{f^{-1}(x)}\right) = \log_3\left(\dfrac x2\right)[/tex]
[tex]f^{-1}(x) \log_3(3) = \log_3\left(\dfrac x2\right)[/tex]
[tex]\boxed{f^{-1}(x) = \log_3\left(\dfrac x2\right)}[/tex]
What formula can we use to find the surface area of a rectangular prism?
Answer:
○ [tex]\displaystyle SA = 2lw + 2lh + 2wh[/tex]
Explanation:
A rectangle has four right angles, including two pairs of congruent edges, only containing two dimensions – height and length. Therefore, going three-dimensional, a rectangular prism has three dimensions – width, height, length. With this information, you should know what the answer is.
I am joyous to assist you at any time.
what is this number? 1,010,020,030,040,050,060,070,080,090,010,020,030,040,050,060,070,080,090,010,020,030,040,050,060,070,080,090,010,020,030,040,050 WILL MARK BRAINLIEST
Answer:
that isn't a number
Step-by-step explanation:
How to graph the equation y=-x^2+6x-5 on the accompanying set of axes?
Answer: See attached
Step-by-step explanation:
Given:
y = -x² + 6x - 5
Since this is a quadratic function, we will have a parabola.
Because our x² value is negative, this parabola will be a "frowny face" instead of a "smiley face" like the parent function.
The - 5 means we shift the function 5 units to the right from the parent function.
See attached for our graph.
What parent function am I mentioning?
The parent function of y = -x² + 6x - 5 is y = x²
1
N
3
5
6
B
10
56:0
What is the range of the function on the graph?
5
14
O all real numbers
O all real numbers less than or equal to -1
all real numbers less than or equal to 3
© all real numbers less than or equal to 0
-5-4-3-2-14
1 2 3 4 5 X
I
-2
-3
-4
-5
Answer:
pack you
pa brainliwa po
Which graph of f(x) satisfies the conditions Limit of f (x) as x approaches 2 minus = –4 and Limit of f (x) as x approaches 2 plus = 0? HURRY WILL GIVE BRAINLIEST FOR CORRECT ANSWER!!
The graph of f(x) that satisfies the condition of f(x)'s left sided limit at 2 being -4 and right sided limit at x = 2 being 0 is given by the first graph.
What is one-sided limit for function of single variable?In rough terminologies, the limit from one side is when we only use one side of the function with respect to the considered point of interest (in input) to predict the value of the function at that point.
For this case, we need to find the graph of the function f(x) from the considered 4 graphs for which:
[tex]\lim_{x\rightarrow 2^{-}}f(x) = -4\\\\\lim_{x\rightarrow 2^{+}}f(x) = 0\\[/tex]
For the first graph, for the point x=2, on left from the point x = 2 lies a ray. If thats the function, we can hope that the function will continue having the same line to the right too, so the prediction for value of function on x = 2 is the value that line gives for y.
That is -4.
Thus, prediction of function from left of x = 2 is -4, or
[tex]\lim_{x\rightarrow 2^{-}}f(x) = -4[/tex]
Similar to that, from the right of the point 2, there is some yellow curve. That predicts that the function's value at point x = 2 should be 0 (the yellow curve seems like touching the x-axis where y = 0 at the point x=2.
Thus, we have:
[tex]\lim_{x\rightarrow 2^{+}}f(x) = 0\\[/tex]
So graph first is correctly pertaining such function f(x).
Second graph when refered, we see that if we predict value at x =2 from left, the yellow curve in the left will make us predict that the function would be 0, so: [tex]\lim_{x\rightarrow 2^{-}}f(x) = 0[/tex]
Thus, its wrong graph.
Third graph when refered, we see that if we predict value at x =2 from left, the green line in the left will make us predict that the function would be -2 at x = 2 (see the green point in the third graph), so: [tex]\lim_{x\rightarrow 2^{-}}f(x) = -2[/tex]
Thus, its wrong graph.
Similarly, for the fourth graph, we see that if we predict value at x =2 from left, the yellow curve in the left will make us predict that the function would be 0, so: [tex]\lim_{x\rightarrow 2^{-}}f(x) = 0[/tex]
Thus, its wrong graph.
Thus, the graph of f(x) that satisfies the condition of f(x)'s left sided limit at 2 being -4 and right sided limit at x = 2 being 0 is given by the first graph.
Learn more about one-sided limits here:
https://brainly.com/question/23625942
#SPJ1
Answer:answer a
Step-by-step explanation: got right on edge 2023
On Monday the postman brought two checks, one for $56.00 and one for $10.00. Assuming you
have no other money in the world, what is your financial situation after this delivery?
Answer: $66.00
Step-by-step explanation:
56 + 10 = 66
Looking for the best answer
Answer:
4x - 5 - 3
Step-by-step explanation:
the 3rd is the best answer i think
Find the greatest common factor of 8 and 24.
Answer:
8
Step-by-step explanation:
Factors of 8: 1, 2, 4, 8
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
They do share a few factors but the greatest one shared between the two is 8
A college student takes the same number of credits each semester. She had 8 credits when she started, and after 7 semesters, she had 92 credits.
Which of these expresses the rate at which she is earning credits
Answer:
12 credits per semester
Step-by-step explanation:
she has 92 in the end but she started off with 8 so your first step is to subtract 8 from 92 which gives you 84 once you get 84 you divide that by 12 you get 7 which means she got 12 credits in each of her 7 semeters
please show your work, tysm :D
~giving brainliest!~
Answer:
1/16th
Step-by-step explanation:
You can write this problem as a function of time.
Let x be the amount of acetaminophen that you start off with.
Let n be the amount of 2.5 hour intervals that have passed
x*0.5^n
The reason this function works is because with each 2.5 hour interval, you multiply the total product by another 1/2.
Plugging in 4(because 4 2.5 hour intervals in 10 hours), you get:
x*0.5^4,
which is x/16.
This shows that 1/16th of the acetaminophen is left in the body after 10 hours.
Find the mean of the data in the dot plot below. Make sure to show your work and explain the steps you took in solving the problem. please help I took a picture I just need the problem to be explained
Answer: 6.
Step-by-step explanation: To find the mean, the first step is to add all the data together. Here's how it should look:
2 + 3 + 6 + 6 + 7 + 8 + 8 + 8 = 48.
Next, you need to divide whatever you get after adding the data by how many numbers there are for your data. In this case, 48 was the answer when we added all the data. In total, you have 8 numbers in your data, so you need to divide 8 from 48. It should look like this:
48 / 8 = 6.
Therefore, the mean for this data set is 6.
Have a great day! :)
Solve for 2. Round to the nearest tenth, if necessary.
B
U
67
T
x
142°
Tan(angle) = opposite/ adjacent
tan(42) = 67/x
x =67/tan(42)
X = 74.411
rounded to nearest tenth : x = 74.4
50 points+ Brainliest PLEASE SHOW WORK!!!!
(i can only give brainliest if at least 2 people answer)
Answer:
here
Step-by-step explanation:
we can do it by using the formula like
mean; efx÷n
median =n+1÷2
mode =which is more
range=highest-smallest
Answer:
Step-by-stwe can do it by using the formula like
mean; efx÷n
median =n+1÷2
mode =which is more
range=highest-smallestep explanation:
0.7 is equivalent to what fraction
Answer:
7/10
Step-by-step explanation:
Fractional form of 0.7 is 7/10.
i would really like some help, factoring trinomials if you want an extra 50-100 points you could help with a previous question on my profile lol
Answer:
[tex]g) \left(5x-2\right)\left(3x+2\right)[/tex]
[tex]h)2\left(8a-9\right)\left(a-2\right)[/tex]
[tex]i)3\left(21n^2+42n+16\right)[/tex]
Step-by-step explanation:
Starting with g) [tex]15^2+4x-4[/tex]
Break the expression into group
[tex]=\left(15x^2-6x\right)+\left(10x-4\right)[/tex]
Now, Factor out [tex]3x[/tex] from [tex]15x^2-6x[/tex] which is now is [tex]3x(5x-2)[/tex]
Next, Facotr out [tex]2[/tex] from [tex]10x-4[/tex] which is now is [tex]2(5x-2)[/tex]
Thus,
[tex]=3x\left(5x-2\right)+2\left(5x-2\right)[/tex]
Factor common term 5x -2
[tex]\left(5x-2\right)\left(3x+2\right)[/tex]
-------------------------------------------------------------------------------------------------------------
Next we have [tex]h)16a^2-50a+36[/tex]
Factor out common term thus we have [tex]2(8a^2-25a+18)[/tex]
Factor again: [tex]8a^2-25a+18[/tex] now turn into [tex](8a-9)(a-2)[/tex]
[tex]=2\left(8a-9\right)\left(a-2\right)[/tex]
-------------------------------------------------------------------------------------------------------------
Lastly we have [tex]i)63n^2+126n+48[/tex]
Rewrite the following:
63 as 3 * 21
126 as 2 * 42
48 as 3 * 16
[tex]63n^2+126n+48[/tex]
Now cut out common term:
[tex]=3\left(21n^2+42n+16\right)[/tex]
-------------------------------------------------------------------------------------------------------------
~lenvy~
Answer:
(g) [tex](5x-2)(3x+2)[/tex]
(h) [tex](16a-18)(a-2)[/tex]
(i) [tex]3(21n^2+42n+16)[/tex]
Step-by-step explanation:
To factor a quadratic in the form [tex]ax^2+bx+c[/tex]
Find 2 two numbers ([tex]d[/tex] and [tex]e[/tex]) that multiply to [tex]ac[/tex] and sum to [tex]b[/tex]Rewrite [tex]b[/tex] as the sum of these 2 numbers: [tex]d + e = b[/tex]Factorize the first two terms and the last two terms separately, then factor out the comment term.Question (g)
[tex]15x^2+4x-4[/tex]
[tex]\implies ac=15 \cdot -4=-60[/tex]
[tex]\implies d+e=4[/tex]
Factors of 60: 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60
Therefore, the two numbers (d and e) that multiply to -60 and sum to 4 are:
10 and -6
Rewrite [tex]4x[/tex] as [tex]+10x-6x[/tex]:
[tex]\implies 15x^2+10x-6x-4[/tex]
Factories first two terms and last two terms separately:
[tex]\implies 5x(3x+2)-2(3x+2)[/tex]
Factor out common term [tex](3x+2)[/tex]:
[tex]\implies (5x-2)(3x+2)[/tex]
Question (h)
[tex]16a^2-50a+36[/tex]
[tex]\implies ac=16 \cdot 36=576[/tex]
[tex]\implies d+e=-50[/tex]
Factors of 576: 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 32, 36, 48, 64, 72, 96, 144, 192, 288, 576
Therefore, the two numbers that multiply to 576 and sum to -50 are:
-32 and -18
Rewrite [tex]-50a[/tex] as [tex]-32a-18a[/tex]:
[tex]\implies 16a^2-32a-18a+36[/tex]
Factories first two terms and last two terms separately:
[tex]\implies 16a(a-2)-18(a-2)[/tex]
Factor out common term [tex](a-2)[/tex]:
[tex]\implies (16a-18)(a-2)[/tex]
Question (i)
[tex]63n^2+126n+48[/tex]
Factor out common term 3:
[tex]\implies 3(21n^2+42n+16)[/tex]
This cannot be factored any further.
Find the value of X.
Answer: 23
Step-by-step explanation: