B
How many degrees must
Figure A be rotated
counterclockwise around
the origin in order to line
up with Figure B?
A
A 90
B. 180
C. 270
D. 360

Answer:

12 -16. 19

4. 8. 22

3. -9. -4

Step-by-step explanation:

13-1 = 12

-10-6= -16

12 - -7 = 12+7=19

6-2 = 4

Keep subtracting

Step-by-step explanation:

1) let number=a

six times a number=6a

Condition:

6a+4=22

2) eleven times a number=11a

Condition:

11a-5=50

3) 9 times a number=9a

Condition:

9a-7=-16

Note:if you need to ask any question please let me know.

Try this option:

only periodical functions have many zeros, that is why y=sinx and y=cosx are the correct answer.

The functions y = x and y = x³ have infinitely many zeros. These functions pass through the origin and have a unique property that allows them to intersect the x-axis an infinite number of times.

The two functions with infinitely many zeros from the given list of twelve basic functions are y = x and y = x³

The function y = x has infinitely many zeros because any value of x that equals zero will result in y also being zero.

In other words, for every x value of 0, the corresponding y value is also 0.

This makes the function pass through the origin (0, 0) and have an infinite number of zeros.

2. The function y = x³ also has infinitely many zeros because the cube of any real number is zero if and only if the number itself is zero.

This means that for every x value of 0, the corresponding y value is also 0. Hence, the function y = x³ passes through the origin (0, 0) and has an infinite number of zeros.

In summary, the functions y = x and y = x³ have infinitely many zeros. These functions pass through the origin and have a unique property that allows them to intersect the x-axis an infinite number of times.

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Answer:

LCD = 60

BRAINLIEST, PLEASE!

Step-by-step explanation:

All of the denominator numbers are multiples of 60, and since 60 is also equal to the largest denominator number, it's the LCD.

9514 1404 393

Answer:

  (-2, 1.5)

Step-by-step explanation:

The coordinates of the midpoint are the average of the end point coordinates:

  ((-7, -4) +(3, 7))/2 = (-7+3, -4+7)/2 = (-4, 3)/2 = (-2, 1.5)

The coordinates of the midpoint are (-2, 1.5).

Answer:

$175

Step-by-step explanation:

$60÷3÷4 =5

$5 is the cost of one adult's food for one day.

$5×7×5

=$175

$175 is the cost of food consumed by 7 adults for 5 days.

Answer:

Step-by-step explanation:

14 1⁄16

The answer is B Geologist

Answer:

geologist

Step-by-step explanation:

they work with the earths surface and natural land that changes

Answer:

i dont get what youre asking

Step-by-step explanation:

Answer:

2n + 3

Step-by-step explanation:

n = number

Sum of twice a number (2n) and (3)

-> 2n + 3

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Answer:

 B.  25 people

Step-by-step explanation:

The remainders tell you the number will be 1 more than some multiple of the least common multiple (LCM) of 2, 3, and 4. The LCM is 3·4 = 12, so we want some multiple (n) of that such that 12n+1 is a multiple of 5. We know this is the case for n=2.

The least number of people who could be in the club is 2·12+1 = 25.

Hi ;-)

This angle is

Answer:

This is an obtuse angle

Step-by-step explanation:

Anything over 90 degrees is obtuse

Answer:

x = - |y| - 3

Step-by-step explanation:

Step-by-step explanation:

f(10)=10

f(-2)=-2

f(a)=a

f(a+b)=a+b

g(10)=5×10-12=3

g(-2)=5×(-2)-12=-10-12=-22

g(a)=5×a-12=5a-12

g(a+b)=5×(a+b)-12=5a+5b-12

h(10)=(10)^2 +4(10)-7=100+40-7=133

h(-2)=(-2)^2 +4(-2)-7=4-8-7=-11

h(a)=a^2 +4a -7

h(a+b)=(a+b)^2 +4a+4b-7=a^2+2ab+b^2+4b-7

Answer:

a=2 and b=2...............

Answer:

keyboard and mouse are two examples of input device

Answer:

keyboard and mouse

Step-by-step explanation:

If you like my answer than please mark me brainliest

Answer:

[tex]ax + bx = 10 \\ \\ x(a + b) = 10 \\ \\ x = \frac{10}{a + b} [/tex]

I hope I helped you^_^

Its must be a rectangle

Perimeter:-

[tex]\\ \sf\longmapsto 2(L+B)[/tex]

[tex]\\ \sf\longmapsto 2(3+7)[/tex]

[tex]\\ \sf\longmapsto 2(10)[/tex]

[tex]\\ \sf\longmapsto 20cm[/tex]

Area:-

[tex]\\ \sf\longmapsto Length\times Breadth[/tex]

[tex]\\ \sf\longmapsto 3(7)[/tex]

[tex]\\ \sf\longmapsto 21cm^2[/tex]

Answer:

Length=3cm

breadth=7cm

Area(A)=?

we know that,

Area of rectangle (A)=l*b

=3cm*7cm

= 21cm^2

Now,

Perimeter (P)= 2(l+b)

=2(3cm+7cm)

=2*10cm

=20cm Ans.

Answer:

Option(c) 34m

Step-by-step explanation:

Perimeter of a rectangle = 2(length + breadth)

length = 12m

breadth/width = 5m

Perimeter = 2(12 + 5)

                = 2(17)

                = 34m

Answer:

34

you just add, 12+5+12+5 to get 34

Answer:

C

Step-by-step explanation:

If you add up the length of two sides, the sum must be greater than the third side of the triangle.

If you add 1 and 2, it equals 3

But that means it will be equal to the length of the third side, 3

It will be impossible to make a triangle with those lengths of sides no matter how the sides or angles are set.

It's sort of difficult to explain this without any visual

You can look up "triangle inequality" to find out more about this

Step-by-step explanation:

A

this is the combination of a 4×6 rectangle and a 2×2 square. nothing is excluded.

so, the area is

(6-2)×6 + 2×2 = 4×6 + 4 = 24 + 4 = 28 cm²

B

this is the area of the large 8×5 rectangle minus the area of the small 2×3 rectangle.

so the area is

8×5 - 3×2 = 40 - 6 = 34 cm²

C

Basically the same thing as for B. large rectangle minus smaller rectangle.

so, the area is

15×10 - 9×6 = 150 - 54 = 96 cm²

D

the area of a triangle is

baseline × height / 2

or baseline here is 2×8, and the height is 5

so we get the area

2×8 × 5 / 2 = 8×5 = 40 cm²

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Answer:

  A

Step-by-step explanation:

If you read your own question, you find that it answers itself.

The problem statement tells you that speed ...

  ... increasing its speed, constant speed, then decreases

And it tells you the graphs show ...

  (a) begins at 0, goes up, is steady for a while, and then goes down

  (b) begins in the middle, goes down, is steady, and then goes up

  (c) begins at 0, goes up, goes down, and then is steady

___

The first graph has the increasing, steady, decreasing pattern you're looking for.

9514 1404 393

Answer:

  yes

Step-by-step explanation:

Solve for y. You can do this by subtracting 3x+y from both sides of the equation.

  y -(3x+y) = 3x +2y -(3x +y)

  -3x = y

Or ...

  y = -3x

Each value of x maps to a single value of y, so this relation is a function.

_____

This equation is a first-degree polynomial in x. Any polynomial relation y=p(x) is a function, so this is a function.

Answer:

B. Find the area of the triangle PQR.

Answer:

8/3 or 2.6667

Step-by-step explanation:

when you divide fractions you use a technique called KCF

K = keep

C = change

F = flip

You write the equation [tex]\frac{2}{3}[/tex] ÷ [tex]\frac{1}{4}[/tex]

you keep [tex]\frac{2}{3}[/tex]

you change the symbol, so from ÷ you change it to x

and flip the last fraction, so you would have  [tex]\frac{4}{1}[/tex]

then you solve it

[tex]\frac{2}{3}[/tex] x  [tex]\frac{4}{1}[/tex] = [tex]\frac{8}{3}[/tex]

The result of 2/3 divided by 1/4 in simplest form is 8/3 .

Division: It is one of the four basic mathematical operation, the other three being addition, subtraction, multiplication.

Given, division of [tex]\frac{2}{3}[/tex] by [tex]\frac{1}{4}[/tex].

Division of fractional terms:

[tex]=\dfrac{\frac{a}{b}}{\frac{c}{d}}\\= (a)\times(d)/(b)\times(c)[/tex]

Apply, division process of fractional terms.

[tex]=\dfrac{\frac{2}{4}}{\frac{1}{3}}\\ = (2)\times(4)/(1)\times(3)[/tex]

[tex]= \frac{8}{3}[/tex]

Know more about division,

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9514 1404 393

Answer:

  15 in, 30 in, 30 in

Step-by-step explanation:

Let x represent the length of the smallest side. Then the other two sides are (x+15) and (2x). The perimeter is the sum of the side lengths:

  x +(x +15) +2x = 75

  4x = 60

  x = 15 . . . . . . . . . . . shortest side

  (x+15) = 30 . . . . . . second side

  (2x) = 30 . . . . . . . third side

The shortest side is 15 inches, the second side is 30 inches, and the third side is 30 inches.

Answer:

x=950

Step-by-step explanation:

550+400=x

It looks like the limit you want to compute is

[tex]\displaystyle L = \lim_{x\to0}\left(\frac x{\tan(x)}\right)^{\cot^2(x)}[/tex]

Rewrite the limand with an exponential and logarithm:

[tex]\left(\dfrac{x}{\tan(x)}\right)^{\cot^2(x)} = \exp\left(\cot^2(x) \ln\left(\dfrac{x}{\tan(x)}\right)\right) = \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Now, since the exponential function is continuous at 0, we can write

[tex]\displaystyle L = \lim_{x\to0} \exp\left(\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right) = \exp\left(\lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)}\right)[/tex]

Let M denote the remaining limit.

We have [tex]\dfrac x{\tan(x)}\to1[/tex] as [tex]x\to0[/tex], so [tex]\ln\left(\dfrac x{\tan(x)}\right)\to0[/tex] and [tex]\tan^2(x)\to0[/tex]. Apply L'Hopital's rule:

[tex]\displaystyle M = \lim_{x\to0}\dfrac{\ln\left(\dfrac{x}{\tan(x)}\right)}{\tan^2(x)} \\\\ M = \lim_{x\to0}\dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)}[/tex]

Simplify and rewrite this in terms of sin and cos :

[tex]\displaystyle M = \lim_{x\to0} \dfrac{\dfrac{\tan(x)-x\sec^2(x)}{\tan^2(x)}\times\dfrac{\tan(x)}{x}}{2\tan(x)\sec^2(x)} \\\\ M= \lim_{x\to0}\dfrac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)}[/tex]

As [tex]x\to0[/tex], we get another 0/0 indeterminate form. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(x)\cos^3(x) - x\cos^2(x)}{2x\sin^2(x)} \\\\ M = \lim_{x\to0} \frac{\cos^4(x) - 3\sin^2(x)\cos^2(x) - \cos^2(x) + 2x\cos(x)\sin(x)}{2\sin^2(x)+4x\sin(x)\cos(x)}[/tex]

Recall the double angle identity for sin:

sin(2x) = 2 sin(x) cos(x)

Also, in the numerator we have

cos⁴(x) - cos²(x) = cos²(x) (cos²(x) - 1) = - cos²(x) sin²(x) = -1/4 sin²(2x)

So we can simplify M as

[tex]\displaystyle M = \lim_{x\to0} \frac{x\sin(2x) - \sin^2(2x)}{2\sin^2(x)+2x\sin(2x)}[/tex]

This again yields 0/0. Apply L'Hopital's rule again:

[tex]\displaystyle M = \lim_{x\to0} \frac{\sin(2x)+2x\cos(2x)-4\sin(2x)\cos(2x)}{2\sin(2x)+4x\cos(2x)+4\sin(x)\cos(x)} \\\\ M = \lim_{x\to0} \frac{\sin(2x) + 2x\cos(2x) - 2\sin(4x)}{4\sin(2x)+4x\cos(2x)}[/tex]

Once again, this gives 0/0. Apply L'Hopital's rule one last time:

[tex]\displaystyle M = \lim_{x\to0}\frac{2\cos(2x)+2\cos(2x)-4x\sin(2x)-8\cos(4x)}{8\cos(2x)+4\cos(2x)-8x\sin(2x)} \\\\ M = \lim_{x\to0} \frac{4\cos(2x)-4x\sin(2x)-8\cos(4x)}{12\cos(2x)-8x\sin(2x)}[/tex]

Now as [tex]x\to0[/tex], the terms containing x and sin(nx) all go to 0, and we're left with

[tex]M = \dfrac{4-8}{12} = -\dfrac13[/tex]

Then the original limit is

[tex]L = \exp(M) = e^{-1/3} = \boxed{\dfrac1{\sqrt[3]{e}}}[/tex]

Answer:

10cm

Step-by-step explanation:

78,5=pi.r^2

Answer5:

Step-by-step explanation: