Aristotle said that if you dropped a large object and a smaller object that the larger
object would hit the ground first.
We now know that that is___
not true.
true

(B) 1.58×10³ V

Explanation:

If you divide the input voltage by the number of turns in the primary coil, the result will be equal to the output voltage divided by the number of turns in the secondary coil:

Ui/Np = Uo/Ns

83/250 = Uo/4750 multiply both sides by 4750

394250/250 = Uo

Uo = 1577 = 1.58×10³ V

Answer:

Answer:

C) 3/2 I

Explanation:

Initial condition

I = m(2d)² + 2m(d²)

I = 4md² + 2md² = 6md²

swap masses

I' = 2m(2d)² + m(d²)

I' = 8md² + md² = 9md²

I'/I = 9md²/6md² = 3/2

I' = 3/2I

Answer:

Dissolving sugar in water is an example of a physical change .

.......

Answer:

Explanation:

This is going to sound like an absurd answer, but sometimes physics can be a little strange.

This answer is weird because of the definition of displacement. It means the distance from the starting point to the ending point, disregarding what happened in between. The point is that the astronaut is at the starting point of his orbit. By definition the starting and ending points are the same. His displacement is 0.

So the answer is you have the greater displacement when you walked one way to school.  The starting point and the ending point are different. You have gone further.

However just to make things a little nasty, when you walk home again, your displacement will be the same as the astronaut's -- 0 meters because you will be right back where you started from.

You that just traveled from home to school has greater displacement than the astronaut.

Displacement is defined as the change in the position of an object.

An astronaut who completed an orbit of the earth, has moved from an initial position x₁ and returned to the same position x₁ because Earth is assumed to be spherical. To complete an orbit of the Earth, the astronaut must return to his initial position since he will move round the Earth.

The displacement of the astronaut is zero because x₁ - x₁ = 0

For you that have just traveled from home to school, BUT haven't returned, your displacement is greater,.

Let's say the distance from your home to school = y

Your initial position at your home = 0

your displacement = y - 0 = y

Thus, you that just traveled from home to school has greater displacement than the astronaut.

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Answer:

gravitational force

Explanation:

since they seem like they are falling, gravity usually pulls them down

i think its gravitational force

fundamental UNIT AND DERIVED UNIT

Explanation:

THERE ARE TWO TYPE OF UNIT

1 FUNDAMENTAL UNIT = THE UNIT OF PHYSICAL QUANTITY LIKE METRE SECOND ETC IS FUNDAMENTAL UNIT.

2 DERIVED UNIT=THE UNIT OF DERIVED PHYSICAL QUANTITY LIKE PASCAL ,NEWTON ETC IS DERIVED UNIT

Answer:what is your Question

Explanation:

Answer:

2Kg

first you find the total mass of both the person und skateboard

f = m*a

30 = m* 0.5

m= 30/ 0.5

m= 60 kg

then you subtract the mass of the person from the total mass

m1 - m2

60 - 58

= 2 kg

Taking into account the Newton's second law, the mass of the skateboard is 2 kg.

Newton's Second Law establishes the relationship between the forces acting on an object and the acceleration it experiences. This law says that the acceleration that an object experiences when subjected to a net force (force applied to the body) is proportional to that force.

Mathematically, Newton's second law is expressed as:

F= m×a

where:

In this case, you know:

Replacing:

30 N= m× 0.5 m/s²

Solving:

m= 30 N÷0.5 m/s²

m= 60 kg

The mass of the sistem is the sum of the mass of the skateboard and the mass of the mass of your body:

Mass= mass of the skateboard + mass of your body

In this case:

60 kg= mass of the skateboard + 58 kg

Solving:

mass of the skateboard= 60 kg - 58 kg

mass of the skateboard= 2 kg

Finally, the mass of the skateboard is 2 kg.

Learn more about the Newton's second law:

Answer:

Wagon weight 366.41314(9.81) = 3,594.5129 = 3590 N

Load weight 349.9245(9.81) = 3,432.75982 = 3430 N

Explanation:

Let's assume the surface and the applied force are horizontal.

At constant motion, the friction force must balance the applied force

(from F = ma)

Ff = 77.3

μΝ = 77.3

μmg = 77.3

m = 77.3 / (0.011(9.81))

m = 716.3376... kg

Let M be the mass of the wagon

M + 0.955M = 716.3376

M(1.955) = 716.3376

M = 366.41314...kg

0.955 M = 349.9245... kg

round to the three significant digits of the question numerals.

[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \sf\longmapsto Force=Pressure(Area)[/tex]

[tex]\\ \sf\longmapsto Force=200(0.2)[/tex]

[tex]\\ \sf\longmapsto Force=40N[/tex]

Answer:

Explanation:

ai. com=(67*0+179*1.25)/(179+67)=0.91m

ii. com=(67*2.5+179*1.25)/(179+67)=1.59m

b. 0.91=(67(2.5-d)+179(1.25-d))/(179+67)

   d=0.68m

c. 1.5=(67*-3+67*-4+179*v)/(67+67+179)

    v=5.24m/s

The answers to your question are ;

A) Location of the center of the mass of system when origin of coordinate system is

i) On the original location of man = 0.91 m

ii) On back end of boat = 1.59 m

B) The boat is displaced by = 0.68 m

C) speed of boat after their jump ( V ) = 5.24 m/s

Given data :

mass of man = 67 kg

mass of boat = 179 kg

length of boat = 2.5 m

assumptions : No friction/drag force

Solutions

A) determine location of center of mass

i) On the man's original location = 0

= ( mass of man * 0 + mass * 1.25 ) / ( mass of boat + mass of man)

=  ( 0 + 179 * 1.25 ) /  ( 179 + 67 )

= ( 0 + 223.75 ) / ( 246 ) = 0.9096  ≈ 0.91 m

ii) On the back end of the boat

= ( mass of man * length of boat + mass of boat * 1.25 ) / ( mass of boat + mass of man )

= (  67 * 2.5 + 179 * 1.25 ) / ( 179 + 67 )

= ( 167.5 + 223.75 ) / ( 246 ) = 1.590 m

B) By How much is the boat displaced ( d )

0.91 ( location of center of mass from man's original location )

0.91  = (  67 *  (2.5 - d) +  179 (  1.25 - d ) ) / ( 179 + 67 )

        = ( 67 * ( 2.5 - d ) + 223.75 - 179d )) / ( 246 )

∴ d ≈ 0.68 m

C) Determine speed of boat after the jump

Initial speed of boat = 1.5 m/s

hence speed after the jump ( v )

speed of first man = 3 m/s

speed of second man = 4 m/s

1.5 m/s = ( 67 * -3 + 67 * -4 + 179 * v ) / ( 67 + 67 + 179 )

           = ( - 201 + -268 + 179v ) / ( 313 )

∴ v ≈ 5.24 m/s

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Explanation:

Time= Distance÷Velocity

Time= 1800÷90

Time= 20 hr

20×60= 1200 min

Answer:

I believe it's A

Explanation:

........

Teniendo en cuenta la definición de media, mediana y moda:

La media (también llamada promedio o media aritmética) de un conjunto de datos es una medida de posición central cuyo valor se obtiene al dividir la suma de todos los números entre la cantidad de ellos. Entonces, en este caso, el promedio de las lecturas obtenidas se calcula como:

[tex]Promedio=\frac{5+1+3+3+6+2+6+4+5+2+1+2+5+3+2+6+1+4+4}{19}[/tex]

Resolviendo:

Promedio= 3,42

El promedio de las lecturas obtenidas es 3,42.

Por otro lado, la moda de un conjunto de números es el número que aparece más a menudo dentro del grupo de datos.

En este caso, podes observar que la cantidad de veces que aparece cada número es:

Debido a que el 2 es el número con mayor cantidad de repeticiones, la tirada que más se repite es 2.

Por último, la mediana es valor que se encuentra en la mitad justa entre los valores máximo y mínimo de los datos con los que se está trabajando; es decir, que al ordenar los número de menor a mayor, éste se encuentra justamente en medio de los valores.

En este caso, ordenando de menor a mayor las lecturas del dado:

1,1,1,2,2,2,2,3,3,3,4,4,4,5,5,5,6,6,6

se observa que el valor el mayor valor intermedio de todas las lecturas es 3.

Aprende más con estos ejemplos:

Answer:

The standard (metric) units that would be discussed at primary school would include: grams and kilograms, centimetres, metres and kilometres, millilitres and litres (though children also learn about imperial units in Year 5 maths).

Answer:

Standard units are commonly used units of measurement. For an example; grams and kilograms, centimetres.

Answer:

Due to interia of motion

We know

[tex]\boxed{\sf K.E=\dfrac{1}{2}mv^2}[/tex]

For Rotational motion

[tex]\boxed{\sf v=r\omega}[/tex].

Putting value

[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m(r\omega)^2[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}mr^2\omega^2[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m\left(\dfrac{R_o}{2}\right)^2v_o^2[/tex]

[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{4}mv_o^2[/tex]

Answer:

0.04569 W/m^2

Explanation:

I=150cos^2(89.0)

=0.04569W/m^2

Explanation:

the answer is in picture

Let v be the object's volume. The object displaces 0.4v cm³ of water, which, at a density of about 0.997 g/cm³, has a weight of

b = (0.000997 kg/cm³) (0.4 v cm³) g ≈ 0.000391v N

(and b is also the magnitude of the buoyant force). Then the net force on the object while it's floating in water is

∑ F = b - mg = 0

so that b = mg, where mg is the object's weight. This weight never changes, so the object feels the same buoyant force in each liquid.

(a) In methanol, we have

b = 0.000391v N = (0.00079 kg/cm³) (pv cm³) g

where p is the fraction of the object's volume that is submerged. Solving for p gives

p = (0.000391 N) / ((0.00079 kg/cm³) g) ≈ 0.0505 ≈ 5.05%

(b) In carbon tetrachloride, we have

b = 0.000391v N = (0.00158 kg/cm³) (pv cm³) g

==>   p ≈ 0.0253 ≈ 2.53%

Answer:

An object in a motion when it is continuously changing its position based on a reference point and observed by a person or a device.

Explanation:

Kinetic energy (J) = 2j

mass= 250g

velocity=?

1kg=1000g

mass= 250/1000

mass=0.25kg

Kinetic energy (J) = ½ x mass (kg) x [velocity]² (m/s)

2=1/2 × 0.25× [velocity]²

2=0.125× [velocity]²

[velocity]² = 2/0.125

[velocity]²=16

velocity= (16)^1/2

velocity= 4 m/s

(b)

Explanation:

Energy levels farther from the nucleus represent higher energies. Therefore, in order for the electrons to reach these levels, they must absorb additional energies first before they can make the jump.

Answer:

ोोञककतकषगकषषमषघ

Explanation:

zzjjjfkgkzgkggkkkammmmmmatAllzy##pglCsg

Explanation:

Please mark me as brainlyest

Answer:

- Measurement is a comparison of an unknown quantity with a known fixed quantity of the same kind. The value obtained on measuring a quantity is called its magnitude. Magnitude of a quantity is expressed as numbers in its units.

- Measurements play an important role in daily life because they are useful to do basic tasks, such as take a child's temperature with a thermometer, make time estimations, measure out medicine and find weights, areas and volumes of different materials or substances.

- Electrical Parameter Measuring Unit Unit/Symbol

Voltage                               Volt                    V or E

Resistance                       Ohm                    R or Ω

Current                               Ampere             I or i

Capacitance                       Farad              C

Explanation:

I'm not sure but hope it helps.

dnxjjc cjgnjgjnffjnfkfmgkcknsmksjs dmxmcmfkcnfjcnfjfnfjf in jfnfifnfifnf

Answer:

Electroplating is the method of depositing one metal over another in the presence of a metal salt (in aqueous solution). The water molecule is released as the final product in this process. As a consequence, electroplating is based on the theory of hydrolysis.

Answer:

I believe it is True

Explanation:

Answer:hola puto

Explanation:cabroné

Successive resonances/harmonics are observed to occur at 129, 215 and 301 Hz (Note: 129 Hz is not necessarily the fundamental frequency). the speed of sound is 76 added to 129 is 215

The pitch of the sound is a major property where the frequency of sound occur by human ear within the range of human hearing.

It is higher than the frequency of the sound where the higher is its pitch and a lower frequency means a lower pitch.

The loudness of sound is another property which can be determined by amplitude of the sound is a measure of the magnitude of the maximum disturbance of sound.

The speed is another property can be detrained as  the sound waves which can travel through the medium is called the speed of sound and it is different for different mediums, travels fastest in solids.

For more details  sound, visit

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