After we planted flowers in 2/5 of our garden, 24m squared remained unplanted. How many square meters is this garden in total? if the total area of the garden is 1 the proportion of the remaining area is?

An effective visual representation of a function or a mapping between two sets is a mapping diagram. It consists of two vertical columns, one of which represents the domain set items and the other of which represents the range set elements. The items in the range set that match to those in the domain set are listed in the right column, and vice versa.

I assume you are given a mapping rule that relates elements in a set to other elements in another set, and you are asked to complete a mapping diagram based on this rule.

If the mapping rule is not specified, we cannot determine the values of a and b. However, assuming that the mapping rule is such that each element (x, y) in the set R is mapped to [tex](x + a, y + b)[/tex], we can complete the mapping diagram as follows:

The given set R is:

R = {(-3, -2), (-3, 0), (-1, 2), (1, 2)}

If we apply the mapping rule to each element in R, we get:

(-3, -2) → (-3 + a, -2 + b)

(-3, 0) → (-3 + a, 0 + b)

(-1, 2) → (-1 + a, 2 + b)

(1, 2) → (1 + a, 2 + b)

To complete the mapping diagram, we need to find the values of a and b such that each mapped element is in the set R. That is, we need to find a and b such that:

(-3 + a, -2 + b) ∈ R

(-3 + a, 0 + b) ∈ R

(-1 + a, 2 + b) ∈ R

(1 + a, 2 + b) ∈ R

Substituting the values of R into each of these equations, we get:

(-3 + a, -2 + b) = (-3, -2), which gives a = 0 and b = 0

(-3 + a, 0 + b) = (-3, 0), which gives a = 0 and b = 0

(-1 + a, 2 + b) = (-1, 2), which gives a = 0 and b = 0

(1 + a, 2 + b) = (1, 2), which gives a = 0 and b = 0

Therefore, the values of a and b that complete the mapping diagram are a = 0 and b = 0.

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For the given analogous polygons, in exercise 37 x = 32, y = 18, and in exercise 38, x = 5, y = 166 °.

A polygon is an unrestricted polygonal chain made up of line parts that are connected to produce an area plane figure in figure. The borders or sides of an unrestricted polygonal chain are the individual pieces. The polygon's vertices or corners are the places where two lines meet. A solid polygon's body is its Centre. A polygon is a geometric object with two confines and a limited number of sides. A polygon's sides are made up of pieces of straight lines that are joined end to end. As a result, a polygon's line pieces are appertained to as its sides or edges. Vertex or angles relate to the crossroad of two-line parts, where an angle is created. Having three edges makes a triangle apolygon.What's a commen surable relationship? Proportional connections are connections between two variables where their rates are original. Another way to suppose about them is that, in a commensurable relationship, one variable is always a constant value times the other. That constant is known as the" constant of proportionality".

In the given question.

for exercise 37,[tex]39/(x-6)=27/y=24/1839/(x-6) =24/18=3/2[/tex]

on solving,[tex]3x-18= 78x=3227/y=3/23x=54y=18[/tex]

For exercise 38on comparing,[tex]x=5y-73=360-(61+116+90)y-73=93y=166degree[/tex]

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Answer:

If 15% of the dice were red, then the proportion of red dice is 0.15.

To find out how many red dice are in the pack, we can multiply this proportion by the total number of dice:

0.15 x 20 = 3

Therefore, there are 3 red dice in the variety pack.

Step-by-step explanation:

If 15% of the dice in the variety-pack are red, then the proportion of red dice to total dice is 0.15.

Let's represent the number of red dice as "x".

We know that the total number of dice in the pack is 20. Therefore, the number of non-red dice must be 20 - x.

We can set up an equation using the proportion of red dice:

x/20 = 0.15

To solve for x, we can multiply both sides by 20:

x = 20 * 0.15

x = 3

Therefore, there are 3 red dice in the pack.

The evaluations of the composite functions expressions and operations are presented as follows;

1. (f + g)(x) = 2·x² + 7·x + 3

(f - g)(x) = 7·x + 21

(f · g)(x) = x⁴ + 7·x³ + 3·x² - 63·x - 108

(f/g)(x) = f(x)/g(x) = (x² + 7·x + 12)/(x² - 9)

2. (f + x)(x) = 3·x - 2

(f - g)(x) = x + 4

(f · g)(x) = f(x) × g(x) = (2·x + 1) × (x - 3) = x⁴ + 7·x³ + 3·x² - 63·x - 108

(f/g)(x) = (2·x + 1)/(x - 3)

3. f[h(-9)] = 25

4. h[f(4)] = 20

5. g[h(-2)] = 10

6. The composite function that converts inches into miles is; n/63360

Composite function is a function that is applied to the result of another function.

Part 1: Operations of Functions

1. f(x) = x² + 7·x + 12 and g(x) = x² - 9, therefore;

(f + g)(x) = f(x) + g(x) = (x² + 7·x + 12) + (x² - 9) = 2·x² + 7·x + 3

(f - g)(x) = f(x) - g(x) = (x² + 7·x + 12) - (x² - 9) = 7·x + 21

(f · g)(x) = f(x) × g(x) = (x² + 7·x + 12) × (x² - 9) = x⁴ + 7·x³ + 3·x² - 63·x - 108

(f/g)(x) = f(x)/(g(x)) = (x² + 7·x + 12)/(x² - 9)

2. f(x) = 2·x + 1 and g(x) = x - 3

(f + g)(x) = f(x) + g(x) = 2·x + 1 + (x - 3) = 3·x - 2

(f - g)(x) = f(x) - g(x) = 2·x + 1 - (x - 3) = x + 4

(f · g)(x) = f(x) × g(x) = (2·x + 1)·(x - 3) = 2·x² - x - 3

(f/g)(x) = f(x)/(g(x)) = (2·x + 1)/(x - 3)

Part 2; 3. f(x) = x², g(x) = 5·x, and h(x) = x + 4

f[h(-9)] = (h(-9))² = (-9 + 4)² = 25

4. f(x) = x², g(x) = 5·x, and h(x) = x + 4

h[f(4)] = (f(4) + 4) = (16 + 4) = 20

5. f(x) = x², g(x) = 5·x, and h(x) = x + 4

g[h(-2)] = (h(-2) × 5) = (-2 + 4) × 5 = 10

6. The formula F = n/12 converts n inches into feet f, and m = f/5280 converts feet to miles m.

Let F(N) represent the function that converts inches to feet and let G(F) represent the function that converts feet to miles. Then the composition function that converts inches to miles is G(F(N))

G(F(N)) = G(n/12) = (n/12)×(1/5280) = n/63360

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The simple regression equation assumes that while the error is not observable, it has a distribution with a mean equal to 0 and a constant variance.

A simple regression equation describes how a single variable relates to another variable. It is one of the most widely used statistical tools. Simple regression is used when one predictor variable, often referred to as an independent variable, is used to explain the variance in a dependent variable.There are two types of simple regression equations, linear and nonlinear.

A linear regression equation is a straight line with a constant slope that represents the relationship between two variables, while a nonlinear regression equation is a curve that represents the relationship between two variables.According to the simple regression equation, while the error is not observable, it has a distribution with a mean equal to 0 and a constant variance. The error is the difference between the actual and predicted values of the dependent variable, and it measures the accuracy of the regression equation's predictions.

The mean of the error is zero, which indicates that the predicted values are equal to the actual values on average. The variance of the error is constant, which indicates that the error is distributed evenly throughout the dataset.

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Answer:

They are congruent by AA- because the only thing they have in common is the 65 degree angles but the sides are all different

Step-by-step explanation:

The area of the half-dollar coin with a diameter of 1.2 inches is greater.

Both the given objects have a circular shape with a different diameter.

One of the objects is made up of two separate quarters of a circle, each with a diameter of 1 inch.

On the other hand, the second object is one half-dollar coin with a diameter of 1.2 inches.

We will use the formula of the area of a circle that is : A = πr²

Where A is the area of the circle.

π is the constant value (3.14)

r is the radius of the circle.

Let's calculate the area of 2 quarters each with a diameter of 1 inch.

The radius will be half of the diameter.

So, the radius is 1/2 inch for each quarter of the circle.

A = πr²A = π × (1/2)²A = π × 1/4A = 0.7854 square inches.

The total area of both quarters will be = 2 × 0.7854 square inches

The total area of both quarters = 1.5708 square inches

Now, let's calculate the area of the half-dollar coin with a diameter of 1.2 inches.

The radius will be half of the diameter.

The radius of the half-dollar coin = 1.2 / 2 = 0.6 inch

A = πr²A

  = π × 0.6²A

  = π × 0.36A

  = 1.1318 square inches

The half-dollar coin has a greater area as compared to the two quarters of a circle.

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As the two triangles are congruent by AAS congruence rule, the segments AB is equivalent to FG.

If two triangles are the same size and shape, they are said to be congruent.

To establish that two triangles are congruent, not all six matching elements of either triangle must be located.There are five requirements for two triangles to be congruent, according to studies and trials.

The congruence properties are SSS, SAS, ASA, AAS, and RHS.

Now in the given figure,

D is the midpoint, so CE = BG.

∠ABC ≅ ∠FGE

That gives us, AB ≈ FG as sides corresponding to equivalent sides are also equivalent to each other.

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The analysis of the data to obtain the best fit line equations that model the data, indicates;

5. a. Quadratic

b. y = -0.1179·x² + 2.1124·x + 4.215

c. Please find the completed chart showing the predicted values and the  in the residuals in the following section.

6. a. A linear model may not be appropriate for the data in the residual plot

b. 4

c. 5

4. a. The exponential model of the function is; y = 100·e^(-0.124·t)

b. The weight after 8 weeks is about 37.1 grams

c. The sample will be 4 grams in about 26 weeks

5. a. The equation is; y = 22.703·x + 2.5733

b. The predicted y-value at x = 10 is; y = 229.60

c. The first time is about x ≈ 3.54

The best fit line is a line that is drawn through a set of data points in such a way that it minimizes the sum of squared errors of the data.

5. The best fit model can be obtained by plotting a scatter plot of the graph, which indicates that the best fit line resembles the shape of a parabola.

Therefore;

a. The best fit equation is; Quadratic

b. The best fit equation, obtained using technology is; y = -0.1179·x² + 2.1124·x + 4.215

The square of the correlation coefficient is; R² = 0.9584

The chart can be filled with the best fit equation as follows;

[tex]\begin{tabular}{ | c | c | c | c | c | }\cline{1-4}Distance (foot) & Height (foot) & Predicted Value &Residual \\ \cline{1-4}0 & 4 & 4.215 & -0.215 \\\cline{1-4}2 & 8.4 & 8.16588 & 0.23412 \\\cline{1-4}6 & 12.1 & 13.23804 & -1.13804 \\\cline{1-4}9 & 14.2 & 14.56626 & -0.36626\\\cline{1-4}12 & 13.2 & 13.77228 & -0.57228 \\\cline{1-4}13 & 10.5 & 13.03602 & -2.53602 \\\cline{1-4}15 & 9.8 & 10.8561 & -1.0561 \\\cline{1-4}\end{tabular}[/tex]

The predicted value are obtained by plugging in the x-value into the best fit equation and the residuals is the difference between the actual value and the predicted value.

6. a. A residual plot can be used to as assessment with regards to meeting the assumptions of a linear regression model.

A residual plot that is randomly scattered about zero indicates that a linear model is appropriate for the data.

The data points in the residual plot are not expressed as being randomly scattered around zero.

The pattern that exists in the residual plot indicates that the values are positive for x-values that are either low or high, and the middle x-values have a negative residuals. Therefr;

b. The number of positive residuals = 4

c. The number of negative residuals = 5

4. The general form of the exponential model of a function, y = A × e^(-k·t)  can be used to find the function for the data as follows;

A = The initial amount = The value at 0 = 100

y = The amount of radioactive material at a given time t

e = Euler's number = 2.71828

The datapoints in the table indicates;

88.3 = 100 × e^(-k × 1)

k = -㏑(0.883) ≈ 0.124

The exponential model is therefore; y = 100 × e^(-0.124·t)

b. The weight of the sample after 8 weeks can be obtained by plugging in t = 8 in the exponential function for the weight of the radioactive substance as follows;

y = 100 × e^(-0.124 × 8) ≈ 37.1

The weight of the sample after 8 weeks is about 37.1 grams

c. When the sample is 4 grams we get;

y = 4

4 = 100 × e^(-0.124 × t)

e^(-0.124 × t)  = 4/100 = 1/25

-0.124 × t = ln(1/25) = -ln(25)

t = ln(25)/0.124 ≈ 26

t ≈ 26 weeks

Therefore; The weight will be 4 grams after approximately 26 weeks

5. A linear regression can be performed using MS Excel to obtain the equation that models the data as follows;

y = 22.703·x + 2.5733

The square of the regression coefficient is; R² = 0.9995

a. The most appropriate equation to model the data in the table is; y = 22.703·x + 2.5733

b. The y-value when x = 10 can be predicted by plugging in x = 10 into the  model equation for the data as follows;

y = 22.703 * 10 + 2.5733 ≈ 229.60

Therefore;

c. The first time the y-value is 83, can be found by setting y = 83 in the equation and solve for x as follows;

83 = 22.703·x + 2.5733

22.703·x = (83 - 2.5733)

x = (83 - 2.5733)/22.703 ≈ 3.54

Therefore, the first time the y-value is 83 is when x is approximately 3.54

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Answer:

slope of 3/4 = line C

undefined slope = line A

Step-by-step explanation:

remember that slope is [tex]\frac{rise}{run}[/tex]. Pick any two points on the graph and count up and over to find the rise/run.

OR

use the slope formula [tex]m=\frac{y_{2} -y_{1} }{x_{2}-x_{1} }[/tex] to plug the two points into and find the slope.

- vertical lines are always undefined.

- horizontal lines have a slope of 0

Answer:

To calculate a percentage decrease, first, work out the difference (decrease) between the two numbers you are comparing. Next, divide the decrease by the original number and multiply the answer by 100. The result expresses the change as a percentage—i.e., the percentage change.

we can estimate that about 440 patients in the medical office are in the age range 13-21.  The experimental probability of finding a patient in the age range 13-21 is 40%, which means that for every 10 patients in the medical office, 4 are in the age range 13-21.

To estimate how many patients are in the age range 13-21, we can use the proportion of the sample in the age range 13-21 and apply it to the entire population. In this case, we can use the proportion of patients in the age range 13-21 in the sample to estimate the number of patients in the age range 13-21 in the population.

The sample size is not given in the problem, but we are told that there are 1,100 patients in the medical office. Let's assume that the sample size is large enough to make a reasonable estimate.

So, if 40% of the sample is in the age range 13-21, then we can estimate that about 40% of the total population of 1,100 patients are also in the age range 13-21.

To calculate this, we can use the following formula:

estimated number of patients in the age range 13-21 = proportion in sample x total population

= 0.40 x 1,100

= 440

Therefore, we can estimate that about 440 patients in the medical office are in the age range 13-21.

It's important to note that this is just an estimate based on the experimental probability from the sample. The actual number of patients in the age range 13-21 may vary from this estimate due to sampling error or other factors. However, this estimate can still provide a useful approximation for planning and decision-making purposes.

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Answer:

A

Step-by-step explanation:

Since both the x and y coordinates changed signs, this is a reflection over the origin. A reflection over the origin is a reflection across both axes.

Answer: A

The periodic rate is the annual percentage rate (APR) divided by the number of periods per year. The periodic rate is 1.1867%

The finance charge is the cost of borrowing money, and it is typically expressed as a percentage of the outstanding balance. In the given scenario, the finance charge is the interest that is charged on the unpaid balance.

10) The unpaid balance is the previous balance minus the payment, which is:

Unpaid balance = Previous balance - Payment

                           = $678.98 - $150

                           = $528.98

Therefore, the unpaid balance is $528.98.

11) The periodic rate is the annual percentage rate (APR) divided by the number of periods per year. Since the period is monthly, we divide the APR by 12. The periodic rate is:

Periodic rate = APR / 12

                     = 14.24% / 12

                     = 1.1867%

Therefore, the periodic rate is 1.1867%.

12) The finance charge is the unpaid balance multiplied by the periodic rate. The finance charge is:

Financial charge = Unpaid balance times the periodic rate

                            = $528.98 × 1.1867%

                            = $6.28 (rounded to the nearest cent)

Therefore, the finance charge is $6.28.

13) The new balance is the sum of the unpaid balance, the finance charge, and the purchases. The new balance is:

New balance = Unpaid balance + Finance charge + Purchases

                      = $528.98 + $6.28 + $147.20

                      = $682.46

Therefore, the new balance is $682.46.

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Answer:

multiply the length of the rectangle by the width of the rectangle.

Step-by-step explanation:

I'm tired for this

According to the given information EF = 8 and DF = 7.

A triangle is a three-sided polygon made up of three line segments that connect at three endpoints, called vertices. The study of triangles is an important part of geometry, and it has applications in various fields such as engineering, architecture, physics, and computer graphics.

Since triangle ABC and triangle DEF are similar, their corresponding sides are proportional. That is:

AB/DE = BC/EF = AC/DF

We are given AB = 40, BC = 64, AC = 56, and DE = 5. We can use the ratio AB/DE = BC/EF to find EF:

AB/DE = BC/EF

40/5 = 64/EF

8 = 64/EF

EF = 64/8

EF = 8

So EF = 8.

Similarly, we can use the ratio AC/DF to find DF:

AC/DF = AB/DE

56/DF = 40/5

56/DF = 8

DF = 56/8

DF = 7

So DF = 7.

Therefore,according to the given information EF = 8 and DF = 7.

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Answer:

let W =with of field (M)

L=length of field=(7/5)×W

P=perimeter of field =2×(L+W) =240m

substiting L as fungtion of w in last equation:

2×(7/5)×W+W=240m

(12/5×w=120m

W=(5×+20m)/12=50m

L=(7/5×50m)=70m

Odd coefficients of the polynomial are obtained by multiplying both odd integers.

Even coefficients of the polynomial are obtained by multiplying both even integers.

Even and odd coefficients of the polynomial are obtained by multiplying both odd integers.

Lets take two integer m and n,

If both 'm' and 'n' are odd integers, then the coefficients of the polynomial obtained by multiplying out will be odd.

If both 'm' and 'n' are even integers, then the coefficients of the polynomial obtained by multiplying out will be even.

If one of 'm' and 'n' is even and the other is odd, then the coefficients of the polynomial obtained by multiplying out will be even and odd.

There are no other cases.

The general form of the polynomial obtained by multiplying out a binomial is:

[tex](a+b)^n = nC_0a^n + nC_1a^{(n-1)}b + nC_2a^{(n-2)}b^2 + .....+ nC_n-1ab^{(n-1)} + nC_nb^n[/tex]

where [tex]nC_k[/tex] is a binomial coefficient.

In general, for a polynomial [tex](a+b)^n[/tex], the coefficient of the term of degree k is [tex]nC_k[/tex].

The binomial coefficients are defined as:  [tex]nC_k = n! / (k!\times(n-k)!)[/tex]

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The probability that their two sons will both have hemophilia is 0%.

Hemophilia is a sex-linked recessive disorder, which means that it is passed from mother to son. Since the woman does not have the disorder, she does not carry the gene for it and therefore her sons would not be affected by the disorder.

However, her daughters could be carriers of the disorder and could pass it on to their sons.

In order for a son to be affected by hemophilia, his mother must carry the gene for the disorder and the father must also have the gene. If the father does not have the gene, then the son will not have hemophilia.

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The best approximation of the volume of a cylinder with a radius of 10 mm, and a height of 5 mm using 3.14 for pi is 1,570 cubic millimeters.

The formula for calculating the volume of a cylinder is as follows:

V = πr²h

Where V is the volume, r is the radius of the cylinder, and h is the height of the cylinder.

Substituting the values given in the formula, we have :

V = πr²hV = 3.14 × (10 mm)² × (5 mm)V = 3.14 × 100 mm² × 5 mm

V = 1,570 cubic millimeters.

Therefore, the best approximation of the volume of a cylinder with a radius of 10 mm, and a height of 5 mm using 3.14 for pi is 1,570 cubic millimeters.

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Answer:

Assuming that g(x) represents the transformed function, the rule for g can be obtained by applying the translation and reflection operations in the correct order.

To translate the graph of f(x) down by 2 units, we need to subtract 2 from the function. This gives us:

h(x) = f(x) - 2 = 5^x - 2

Next, we need to reflect the graph of h(x) in the y-axis. To do this, we replace x with -x in the function. This gives us:

g(x) = h(-x) = 5^(-x) - 2

Therefore, the rule for g(x) that represents a translation 2 units down, followed by a reflection in the y-axis of the graph of

f(x) = 5^x is:g(x) = 5^(-x) - 2

Answer: His car was $415.18 in total

Step-by-step explanation: The calculation of the present value of a cash flow or other income stream that produces $1 in income over so many periods of time.

Amount borrowed = $12,500

Annual interest rate = 12.00%

Monthly interest rate = 1.00%

Period = 36 months

Let monthly payment be x

12,500 = x/1.01 + x/1.01^2 + x/1.01^3  … + x/1.01^35 + x/1.01^36

12,500 = x * (1 - (1/1.01)^36) / 0.01

12,500 = x * 30.107505

x = 12,500/30.107505  

x = 415.18

So, the monthly payment is $415.18

The value of x in the given linear equation of 4x = 28 is determined as 7.

To find the value of x in the linear equation 4x = 28, we need to isolate x on one side of the equation.

We can do this by dividing both sides of the equation by 4:

4x/4 = 28/4

Simplifying:

x = 7

Thus, identify the equation and the variable: In this case, the equation is 4x = 28, and the variable we want to solve for is x. Also simplify the linear equation by dividing both sides by 4, we get x = 7, which is the solution.

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The complete question is below:

4x = 28

find the value of x

The amount of work (in foot-pounds) done in stretching a spring from its natural length to 0.8 feet beyond its natural length is 24.

so we have W=6lbs*(0.8ft-0.6ft)

=6lbs*0.2ft

=24ft-lbs.

Work is the measure of the amount of energy required to move an object over a certain distance, so to stretch the spring 0.8 feet beyond its natural length, 24 foot-pounds of work is done.

This can also be understood as the product of the force (6lbs) and the displacement (0.2ft). Work is a scalar quantity, meaning it only has magnitude and not direction.

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Answer:

Give me time to figure this out hold on

Step-by-step explanation:

12

A. The equation of the line that passes through the point (4,3) and has a slope of -5/2 is y = (-5/2)x + 13.

B. The x-intercept of the equation is x = 26/5 or 5.2

A. To find the equation of a line that passes through the point (4,3) and has a slope of -5/2, we can use the point-slope form of a linear equation:

y - y1 = m(x - x1)

where m is the slope, and (x1, y1) is the given point.

Substituting the values, we get:

y - 3 = (-5/2)(x - 4)

Expanding the right side:

y - 3 = (-5/2)x + 10

Adding 3 to both sides:

y = (-5/2)x + 13

B. To find the x-intercept of this equation, we need to set y = 0 and solve for x:

0 = (-5/2)x + 13

Multiplying both sides by -2/5:

0 = x - (26/5)

Adding (26/5) to both sides:

x = 26/5

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The value of the interquartile range for the given subsample is 8.

The interquartile range (IQR) is a measure of the dispersion of a set of observations. It is defined as the difference between the third quartile and the first quartile (Q3-Q1). The subsample data is as follows: 24, 27, 35, 31, 21, 22, 28, 18, 25, 24, 36, 20. The interquartile range for the subsample data can be computed as follows:

Step 1: Arrange the data in ascending order: 18, 20, 21, 22, 24, 24, 25, 27, 28, 31, 35, 36.

Step 2: Find the median of the lower half of the data, which is called the first quartile, Q1. Here, the lower half of the data is 18, 20, 21, 22, 24, and 24. Hence, the median of the lower half of the data is the average of the two middle values, which is Q1 = (22 + 21)/2 = 21.5.

Step 3: Find the median of the upper half of the data, which is called the third quartile, Q3. Here, the upper half of the data is 24, 25, 27, 28, 31, 35, and 36. Hence, the median of the upper half of the data is the average of the two middle values, which is Q3 = (28 + 31)/2 = 29.5.

Step 4: Calculate the interquartile range as the difference between the third quartile and the first quartile: IQR = Q3 - Q1 = 29.5 - 21.5 = 8.

Therefore, the value of the interquartile range for the given subsample is 8.

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The water level is rising at a rate of 32 ft/min when the water is 6 inches deep.

How to solve rise of water level?

Let's first draw a diagram to better understand the problem:

            /|\

           / | \

          /  |  \

         /   |h \

        /    |   \

       /     |    \

      /      |     \

     /       |      \

    /        |       \

   /         |        \

  /_________|

       b

where h is the height of the water, b is the width of the trough at water level, and 10 is the length of the trough.

Since the trough is being filled at a rate of 12 ft³/min, the volume of water in the trough is increasing at a rate of 12 ft³/min. Let's use this to find the rate at which the water level is rising.

The volume of water in the trough is given by the formula:

V = (1/2)bh²

where b is the width of the trough at water level, h is the height of the water, and 1/2 is the area of the triangular cross-section of the trough. We want to find the rate at which h is changing when h = 6 inches = 0.5 ft.

Differentiating both sides of the formula with respect to time t, we get:

dV/dt = (1/2)(db/dt)(h^2) + (1/2)(b)(2h)(dh/dt)

where db/dt is the rate at which the width of the trough at water level is changing, and dh/dt is the rate at which the water level is changing (i.e., the rate we want to find).

We know that dV/dt = 12 ft³/min and h = 0.5 ft. We also know that the width of the trough at the water level is 3 ft. To find db/dt, we need to use similar triangles. The triangle formed by the water and the sides of the trough is similar to the isosceles triangle at the end of the trough. Therefore, the ratio of the width of the trough at the water level to the height of the water is constant:

b/h = 3/1

Solving for b, we get:

b = 3h

on diffrentiating

db/dt = 3(dh/dt)

Substituting the values we know into the formula for dV/dt, we get:

12 = (1/2)(3h)(h²) + (1/2)(3h)(2h)(dh/dt)

12 = (3/2)h³+ 3h²(dh/dt)

4 = h²(dh/dt)

Solving for dh/dt, we get:

Therefore, the water level is rising at a rate of 32 ft/min when the water is 6 inches deep.

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it takes Sheela to run the second leg of the race: Ascertain the total or contrast: x = 13.83.

In view of the given circumstances, plan:: 14.06+ x = 27.89

Modify variables to the left half of the situation: x = 27.89 - 14.06

Ascertain the total or contrast: x = 13.83

Speed = Distance/Time - This lets us know how slow or quick an article moves. It portrays the distance voyaged partitioned when taken to cover the distance.

Speed is straightforwardly Relative to Distance and Conversely corresponding to Time. Thus,

Distance = Speed X Time, and

Time = Distance/Speed, as the speed builds the time taken will diminish as well as the other way around.

Utilizing these recipes any fundamental issues can be settled. Nonetheless, the right utilization of units is additionally something essential to consider while utilizing equations.

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In the expression D) -1 and -10 are both extraneous solutions.

What is expression?

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation. Unknown variables, integers, and arithmetic operators are the components of an algebraic expression. There are no symbols for equality or inequality in it.

The given logarithmic expression is

=> log(-x)+log(x+11) = 1 .

Here the given expression solution is -1 and -10.

Now put x=-1 into given expression then,

=> log(-(-1))+log(-1+11) =1

=> log(1)+log(10) =1

=> 0+1=1

=> 1=1

Then -1 is extraneous solution.

Now put x=-10 then,

=> log(-1(-10))+log(-10+11)=1

=> log(10)+log(1)=1

=> 1+0=1

=> 1=1

Then x=-10 is also extraneous solution.

Hence the correct option is D) -1 and -10 are both extraneous solutions.

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