A webmaster makes $24 an hour for the first 38 hours she works during a
week and $31 an hour for each hour worked over 38 hours. Which piecewise
equation models her total weekly pay y in dollars as it relates to the number
of hours x that she has worked during the week?
24x
O A. e=1
OSXS38
x > 38
(31x+912
0 [24x
O B. y = {31(x – 38) +912 x > 38
S24x
(31x
C. y =
OSXS 38
X> 38
(24x
OSX 38
D. y = {31(x-38)
x > 38

Answer:

[tex](f+g)(x)=x^2-x-3[/tex]

Step-by-step explanation:

We have [tex]f(x)=2x-1[/tex] and [tex]g(x)=x^2-3x-2[/tex]

Recall that [tex]f+g[/tex] is defined by [tex](f+g)(x)=f(x)+g(x)[/tex], therefore

[tex](f+g)(x)=f(x)+g(x)=2x-1+x^2-3x-2=x^2-x-3[/tex]

Answer: 8.EB and F: yes

9.DB and FC:no

10.AC and ED:yes

11.AE and DC:yes

12.F,A,B and C:yes

13.F,A,B and D:no

14.plane Q and EC:yes

15.FB and BD:yes

Step-by-step explanation:

hope this helps have a good day!

Answer: no

Step-by-step explanation:

9514 1404 393

Answer:

Step-by-step explanation:

The given sides will form a right triangle when ...

  (4x +2)² = (4x -2)² +(x +6)² . . . . . the Pythagorean theorem is satisfied

  16x² +16x +4 = 16x² -16x +4 +x² +12x +36 . . . . eliminate parentheses

  x² -20x +36 = 0 . . . . . simplify to standard form

  (x -2)(x -18) = 0 . . . . . . factor

  x = 2 or 18 . . . . . . . . values of x that make the factors zero

There are two triangles.

For x = 2

  hypotenuse = 4(2) +2 = 10

  leg1 = 4(2) -2 = 6

  leg2 = 2 +6 = 8

  dimensions are 6 m by 8 m with hypotenuse 10 m.

For x = 18

  hypotenuse = 4(18) +2 = 74

  leg1 = 4(18) -2 = 70

  leg2 = 18 +6 = 24

  dimensions are 24 m by 70 m with hypotenuse 74 m.

Answer:

a variable

Step-by-step explanation:

The answer is a variable because it's a letter that stands in place of a number

Answer:

simply refers to the type of Latin and Arabic characters representing the numbers 0 - 9, the letters A - Z

Answer:

11

Step-by-step explanation:

Add:

26 + 19 + 43

^       ^

   45 + 43

       88

Divide:

88 / 8 = 11

So, each tank has 11 fish.

Hope this helped.

Answer:

common ratio=0.5, a1= 0.08

Step-by-step explanation:

r=a3/a2

r=a4/a3

compare both we get:

a3/a2=a4/a3

subtitute a2=0.04 and a4=1

a3/0.04=1/a3

(a3)^2=0.04*1

(a3)^2=0.04

taking square root in both sides

a3=0.02

For r, r=a3/a2

subtitute a3 and a2 above

r=0.02/0.04

r=0.5 common ratio

For a1

r=a2/a1

0.5=0.04/a1

a1=0.04/0.5

a1=0.08

A geometric sequence is a sequence of numbers in which the ratio between consecutive terms is constant.

The first term of the geometric sequence is 0.08.

The common ratio of the geometric sequence is 1/0.02.

A geometric sequence is a sequence of numbers in which the ratio between consecutive terms is constant.

We have,

Geometric sequence:

The second term = 0.04

The fourth term = 1

In a geometric sequence the nth term is given as:

[tex]a_{n}[/tex] = [tex]a_1 r^{n-1}[/tex]

Second term = 0.04

[tex]a_2[/tex] = 0.04

[tex]a_1 r^1 = 0.04[/tex]

[tex]a_1r[/tex] = 0.04 _____(1)

Fourth term = 1

[tex]a_4 = 1[/tex]

[tex]a_1 r^3[/tex] = 1 _____(2)

From (1) and (2) we get,

0.04/r = 1/r³

r³ = r / 0.04

r² = 1/0.04

r = 1/0.02 ____(3)

Putting (3) in (1) we get

[tex]a_1[/tex] = 0.04 x 0.02 = 0.08

Thus,

The first term of the geometric sequence is 0.08.

The common ratio of the geometric sequence is 1/0.02.

Learn more about geometric sequence here:

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Answer:

50¢

Step-by-step explanation:

$18.00=1800.

3*12=36

1800/36=50

Answer:

Step-by-step explanation:

the price of per inch is $2

Answer:

Both of them drew the parallelogram right.

Step-by-step explanation:

In Raquel's drawing we can see that the parallelogram is shorter and smaller but both the opposite lines are congruent to each other and match the scale size to the original drawing. And it Felipe's drawing the parallelogram is longer and bigger than the original drawing but the opposite line are also congruent to each other and match the scale size to the original drawing!!

I hope you get it right! :)

Answer:

22/5

Step-by-step explanation:

4 [tex]\frac{2}{5}[/tex]

new numerator for improper fraction = (4 x 5) + 2 = 20 + 2 = 22  

=> 22/5

Answer:

a = 6

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2+b^2 = c^2  where a and b are the legs and c is the hypotenuse

a^2 + 8^2 = 10 ^2

a^2 +64 = 100

a^2 = 100 -64

a^2 = 36

Take the square root of each side

sqrt(a^2) = sqrt(36)

a = 6

Answer:

ethethe

Step-by-step explanation:

thethetht

The required simplified value of the given expression is 16x¹². Option B is correct.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
=(2x³)⁴

As we know that,
[xᵃ]ᵇ = xᵃˣᵇ

So,
(2x³)⁴ = 2⁴x³ˣ⁴
        = 16x¹²

Thus, the required simplified value of the given expression is 16x¹².

Learn more about simplification here:

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Answers:

The logarithmic function f(x) = ln(x) is the natural logarithmic function and has base  e  

=======================================

Explanation:

The ln(x) or Ln(x) is the natural log function. The order of L and n is backwards compared to "natural log", but you can think of it "log that is natural" or something along those lines.

The Ln(x) function is of the form [tex]\log_b(x)[/tex] where the base b is the special constant e = 2.718... (this constant is similar to pi = 3.14...)

Recall some limit properties…

• limits distribute over sums:

[tex]\displaystyle \lim_{x\to c}(f(x)+g(x)) = \lim_{x\to c}f(x)+\lim_{x\to c}g(x)[/tex]

• limits distribute over products:

[tex]\displaystyle \lim_{x\to c}(f(x)\times g(x)) = \lim_{x\to c}f(x)\times\lim_{x\to c}g(x)[/tex]

• limits distribute over quotients, provided that the denominator doesn't approach 0 :

[tex]\displaystyle\lim_{x\to c}\frac{f(x)}{g(x)} = \frac{\displaystyle\lim_{x\to c}f(x)}{\displaystyle\lim_{x\to c}g(x)}[/tex]

• if f(x) is continuous at x = c, then the limit "passes through" a composition:

[tex]\displaystyle \lim_{x\to c}f(g(x)) = f\left(\lim_{x\to c}g(x)\right)[/tex]

# # #

(a) This limit is 2. At x = 2, we have f (2) = 1, but from either side of x = 2, we see f(x) approaching the point (2, 2). So

[tex]\displaystyle \lim_{x\to 2}(f(x)+g(x)) = \lim_{x\to2}f(x)+\lim_{x\to2}g(x) = 2+0 = 2[/tex]

(b) This limit does not exist. We would have

[tex]\displaystyle \lim_{x\to1}(2f(x)-3g(x)) = 2\lim_{x\to1}f(x)-3\lim_{x\to1}g(x)[/tex]

but g(x) approaches 2 from the left of x = 1, and g(x) approaches 1 from the right of x = 1. The one-sided limits don't match, so the two-sided limit doesn't exist.

(c) This limit is 0. It looks like f(x) passes through the origin, while g(x) ≈ 3/2 at x = 0. So

[tex]\displaystyle\lim_{x\to0}f(x)g(x) = \lim_{x\to0}f(x)\times\lim_{x\to0}g(x)=0\times\frac32 = 0[/tex]

(d) This limit does not exist since

[tex]\displaystyle \lim_{x\to-1}g(x)=0[/tex]

(e) This limit is 16. Nothing tricky here, just use the same property as in (c).

[tex]\displaystyle\lim_{x\to2}x^3f(x) = \lim_{x\to2}x^3\times\lim_{x\to2}f(x) = 8\times2=16[/tex]

(f) This limit is 1. f(x) is continuous at x = 1, while g(x) approaches 2 from the left.

[tex]\displaystyle\lim_{x\to1^-}f(g(x)) = f\left(\lim_{x\to1^-}g(x)\right) = f(2) = 1[/tex]

Answer:

30 caps can be bought

Step-by-step explanation:

[tex]{ \sf{Rs.800 = (10 \times 12) \: caps}} \\ { \sf{Rs.200 = ( \frac{200 \times 10 \times 12}{800}) \: caps}} \\ \\ { \sf{ = 30 \: caps}}[/tex]

Answer:

5x5= 25

Step-by-step explanation:

5+5+5+5+5= 25

Answer:

402. 5

Step-by-step explanation:

This is your answer hope this helps

And also pls mark me brainliest

Step-by-step explanation:

that means the expression is the result of a multiplication with (x-0.5) being one factor.

so, we divide the whole expression by this and then deal with the remaining quadratic equation.

6x³ - 13x² + x + 2 / x - 0.5 = 6x² - 10x - 4

- 6x³ - 3x²

----------------------------

- 10x² + x + 2

- - 10x² + 5x

----------------------------

- 4x + 2

- - 4x + 2

----------------------------

finished. 0

so, the whole expression is also

P(x) = (x-0.5)×(6x² - 10x - 4)

now we need to find the 2 zero points of the quadratic part.

the general solution to a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

a = 6

b = -10

c = -4

x = (10 ± sqrt(100 - 4×6×-4))/12 =

= (10 ± sqrt(100 + 96))/12 = (10 ± sqrt(196))/12 =

= (10 ± 14)/12

x1 = (10+14)/12 = 24/12 = 2

x2 = (10-14)/12 = -4/12 = -1/3

168

this is the full process

Answer: The answer is

25 Units

Answer:

36 units

please mark me brainleast

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]6525\text{cm.}^3[/tex]

Keep in mind that this is APPROXIMATE.

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Volume of a Sphere Is:}}\\\\V = \frac{4}{3} \pi r^3\\----------------\\\rightarrow \text{We are given the radius of } 11.6\text{ cm.}\\----------------\\V = \frac{4}{3}(3.14) (11.6)^3\\\\V = \frac{4}{3}(3.14) 1560.896\\\\V \approx 6534.95125\text{cm.}^3\\\\\boxed{V \approx 6535\text{cm.}^3}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer:

[tex] \frac{1 - 2 \sqrt{x} + x }{1 - x} [/tex]

Step-by-step explanation:

[tex] \frac{1 - \sqrt{x} }{1 + \sqrt{x} } [/tex]

Rationalize the denominator by multiplying by it conjugate.

[tex] \frac{1 - \sqrt{x} }{1 + \sqrt{x} } \times \frac{1 - \sqrt{x} }{1 - \sqrt{x} } = \frac{1 - 2 \sqrt{x} + x}{1 - x} [/tex]

Answer:

H = (n/4v) - c

Step-by-step explanation:

I ASSUME the equation is

v = n/(4(c + H))

multiply by (c + H)

v(c + H) = n/4

divide by v

c + H = n/4v

subtract c

H = (n/4v) - c

If the equation is v = (n/4)(c + H)

Then

H = (4v/n) - c

Answer:

[tex]3 \times (4 + 7) =( 3 \times 4) + (3 \times 7) \\ thank \: you[/tex]