a resistor is connected to a 3.0 v battery; the power dissipated in the resistor is 1.0 w. the battery is now traded for a 6.0 v battery. the power dissipated by the resistor is now:
A resistor is connected to a 3.0 V battery and the power dissipated in the resistor is 1.0 W. If the battery is now traded for a 6.0 V battery, the power dissipated by the resistor is now 4.0 W.
The power dissipated by a resistor is given by the formula:
P = V²/R
Rearranging this formula we get:
R = V²/P
Power is directly proportional to the square of voltage.
Hence, if the voltage is doubled, the power will be quadrupled.
Therefore, the power dissipated by the resistor will be four times the original power when the battery is traded for a 6.0 V battery.
Thus, the power dissipated by the resistor is 4.0 W now.
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how is a wave changed by reflection?
Answer: Reflection involves a change in direction of waves when they bounce off a barrier.
Explanation: Refraction of waves involves a change in the direction of waves as they pass from one medium to another. Refraction, or the bending of the path of the waves, is accompanied by a change in speed and wavelength of the waves.
If we traveled at 50,000 km/hr, how long will it take us to get to Proxima Centauri in a space ship?
Therefore, it would take approximately 2.88 million seconds, or around 32.5 days, to travel to Proxima Centauri at a speed of 50,000 km/hr.
How much time would it take for a spacecraft to reach Alpha Centauri?Nearly 40 trillion kilometers, or 4.4 light-years, separate us from Alpha Centauri. The NASA-Germany Helios probes, the fastest spacecraft to date to be propelled into orbit, travelled at a speed of 250,000 kilometres per hour.
We need to convert this speed to a more useful measure, such as kilometres per second (km/s), to find the time it would take a spacecraft travelling at 50,000 km/hr to reach Proxima Centauri.
1 hour = 60 minutes
1 minute = 60 seconds
Therefore, 1 hour = 60 x 60 = 3600 seconds
So, 50,000 km/hr = (50,000 km / 3600 sec) = 13.89 km/s
We must know the distance in kilometres in order to determine the estimated travel duration to Proxima Centauri. The distance to Proxima Centauri is calculated as follows given that 1 light-year is equal to roughly 9.46 trillion kilometres:
4.24 light-years x 9.46 trillion km/light-year = 40.003 trillion km
Using the formula
time = distance / speed
we can calculate the travel time:
time = 40.003 trillion km / 13.89 km/s = 2.88 million seconds
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go to the sources group and select the sine wave block and replace the step with this. this means vm is a sinusoid. set the amplitude to 5 and frequency to 2*pi*3 (3 hz). run the simulation and obtain the omega l(t) trace. does the output make sense and why?
In RLC circuit the output omega L(t) represents the instantaneous energy stored in the inductor. It will be a function of time.
If a sinusoidal voltage is applied to the circuit, the energy stored in the inductor start to oscillates. It will start oscillating at the same frequency as the voltage.
The amplitude of the energy oscillations depends on the parameters of circuit and amplitude of the voltage. These parameters includes resistance, inductance, and capacitance.
So we can say that the output omega L(t) shows sinusoidal oscillations at a frequency of 3 Hz and an amplitude of 5. Now it would make sense for the given circuit parameters and voltage amplitude.
The waveform shape and the amplitude will depend on the specific circuit parameters. Also depend on the initial conditions.
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two electromagnetic waves have different frequencies but equal amplitudes. the one with higher frequency has the group of answer choices longer wavelength. greater energy. none of these. greater speed. all of these.
Explanation:
The correct answer is: none of these.
The frequency of an electromagnetic wave is inversely proportional to its wavelength and directly proportional to its energy. Therefore, two electromagnetic waves with different frequencies will have different wavelengths and energies. The amplitude of an electromagnetic wave, on the other hand, refers to the maximum displacement of the wave from its equilibrium position and is not related to its frequency, wavelength, or energy.
Therefore, we cannot determine whether the electromagnetic wave with higher frequency has a longer wavelength, greater energy, greater speed, or any combination of these, based solely on the information given in the question.
When two electromagnetic waves have different frequencies but equal amplitudes, the one with a higher frequency has greater energy.
What are electromagnetic waves?Electromagnetic waves are a type of wave that travels through space. They are a combination of electric and magnetic fields that move at right angles to each other and at right angles to the direction of wave propagation. The sun, light, radio waves, and microwaves are all examples of electromagnetic waves.
The formula that explains the relationship between energy and frequency of electromagnetic waves is E=hv where E is energy, v is frequency, and h is Planck's constant. The energy of electromagnetic radiation is proportional to its frequency.
Therefore, When two electromagnetic waves have different frequencies but equal amplitudes, the one with a higher frequency has greater energy.
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a small hockey puck slides without friction over the icy hill shown in the figure and lands 7 m from the foot of the cliff with no air resistance. what was its speed v0 at the bottom of the hill?
Using conservation of energy, the initial velocity of the puck at the bottom of the hill is 19.6 m/s.
Expecting the slope is a smooth bend, we can utilize preservation of energy to track down the underlying speed of the puck. Since there is no grating or air obstruction, the main powers following up on the puck are gravity and the typical power. Thusly, the absolute mechanical energy of the puck is saved.At the highest point of the slope, the puck has gravitational possible energy, which is changed over into active energy as it slides down the slope. At the lower part of the slope, the gravitational potential energy has been all changed over into motor energy, so we can compose:
mgh = (1/2)mv0^2
where m is the mass of the puck, g is the speed increase because of gravity, h is the level of the slope, and v0 is the underlying speed of the puck at the lower part of the slope.
Tackling for v0, we get:
v0 = sqrt(2gh)
Where sqrt addresses the square root capability.We can utilize the given distance of 7 m to track down the level of the slope:d = sqrt(h^2 + 49)
where d is the distance the puck lands from the foot of the bluff. Settling for h, we get:
h = sqrt(d^2 - 49)
Subbing this articulation for h into the situation for v0, we get:
v0 = sqrt(2g(sqrt(d^2 - 49)))
Where g is the speed increase because of gravity.Connecting the upsides of g = 9.8 m/s^2 and d = 7 m, we get:
v0 = sqrt(2 x 9.8 x sqrt(7^2 - 49)) = 19.6 m/s
In this way, the underlying speed of the puck at the lower part of the slope was 19.6 m/s.
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2. How far (in meters) will you travel in 220 seconds running at a rate of 5.4 m/s?
Answer:
Explanation: Given: Time=220 seconds
Speed=5.4m/s
To find: Distance covered
Solution:
->The distance covered will be rate of running×time taken
Distance covered=5.4×220
->1188 metres
->Therefore, the distance covered will be 1188 metres.
Which energy type is missing in the windmill energy transformation? kinetic (wind) > ________ > electrical
Answer: mechanical?
Explanation:
Model B was accepted as the structure of the Universe for over 1,000 years. However, it had a major flaw that couldn't be explained. What was that flaw?
Model B is the Heliocentric Theory which cannot explain retrograde.
Model B is the Geocentric Theory which cannot explain retrograde.
Model B is the Heliocentric Theory which cannot explain the Law of Universal Gravitation.
Model B is the Geocentric Theory which cannot explain the Law of Universal Gravitation.
The Geocentric Theory, which cannot explain backward, is Model B.
Why didn't the heliocentric paradigm gain traction?Because its proponents were unable to explain why the relative positions of the stars appeared to stay the same despite the Earth's changing perspectives as it rotated around the Sun, The solar system's heliocentric, or Sun-centered, model was never generally accepted.
Why is the heliocentric paradigm more popular than the geocentric model?Instead of Earth, as was previously thought to be the case according to the geocentric model, the heliocentric model puts the Sun at the core of the solar system. Our greater knowledge of astronomy was built on this advancement, which brought us closer to the true nature of the solar system and the universe.
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astronomers have used observations from the hubble space telescope to measure the rate at which the universe is expanding, and have estimated the age of the universe from that measured rate. suppose the expansion turns out to be faster than current measurements indicate. in that case, our new estimate for the age of the universe would be group of answer choices younger (less time between now and the big bang). unaffected. older (more time between now and the big bang).
If the expansion of the universe turns out to be faster than current measurements indicate, it would mean that the universe is expanding at a greater rate than previously thought. This would imply that the universe has been expanding for a shorter period of time, as the same amount of expansion could be achieved in less time at a faster rate.
The new estimate for the age of the universe would be younger, with less time between now and the big bang. This would have significant implications for our understanding of the early universe, as a younger age would mean that there was less time for galaxies and structures to form.
It would also have implications for other cosmological models, as the age of the universe is a fundamental parameter in many theories of cosmology. However, it is important to note that this is still a hypothetical scenario, and further observations and measurements are needed to confirm or refute this possibility.
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Two concrete spans of a 370 m long bridge are
placed end to end so that no room is allowed
for expansion. 370 mT T + 20◦Cy
If the temperature increases by 20◦C, what
is the height to which the spans rise when
they buckle? Assume the thermal coefficient
of expansion is 1.2 × 10−5(◦C)−1
Answer in units of m.
The height to which the spans rise when they buckle is 0.0222 m.
A high thermal coefficient: what does that imply?A material will expand more as a result of being heated if its coefficient of thermal expansion is larger.
What does the thermal expansion law mean?The phenomena known as thermal expansion can be seen in solids, liquids, and gases. In this procedure, the application of heat causes an object or body to expand (temperature). The term "thermal expansion" refers to an object's propensity to change its dimensions as a result of heat, including length, density, area, and volume.
The following formula can be used to determine the height to which the spans rise when they buckle:
ΔL = LαΔT
where ΔL = change in length,
L = original length,
α = coefficient of thermal expansion,
ΔT = change in temperature
the length of the bridge = 370 m,
the coefficient of thermal expansion = 1.2 × 10^-5 (°C)^-1,
the change in temperature = 20°C.
The change in length of each span is,
ΔL = LαΔT = (370/2)(1.2 × 10^-5)(20)
= 0.0444 m
Since there are two spans, the total change in length is 0.0888 m.
h = ΔL/2 = 0.0444/2
= 0.0222 m
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2. find the angular velocity of a 40 cm radius wheel that is moving at 20 m/s. how many times will this wheel rotate in 5 seconds? what is the centripetal acceleration of the wheel?
The angular velocity of the wheel is 50 rad/s. The centripetal acceleration of the wheel is 1000 m/s^2.
The angular velocity of a wheel is given by the formula:
ω = v / r
where ω is the angular velocity, v is the linear velocity, and r is the radius of the wheel.
Substituting the given values, we have:
ω = 20 m/s / 0.4 m = 50 rad/s
Therefore, the angular velocity of the wheel is 50 rad/s.
To find the number of rotations the wheel makes in 5 seconds, we can use the formula:
θ = ω * t
where θ is the angular displacement, ω is the angular velocity, and t is the time. Since the wheel rotates 2π radians in one full revolution, we can find the number of rotations by dividing the angular displacement by 2π. Substituting the given values, we have:
θ = 50 rad/s * 5 s
= 250 rad
Number of rotations = θ / 2π
= 250 rad / 2π rad/rev ≈ 39.79 rev
Therefore, the wheel will rotate approximately 39.79 times in 5 seconds.
To find the centripetal acceleration of the wheel, we can use the formula:
a = v^2 / r
where a is the centripetal acceleration, v is the linear velocity, and r is the radius of the wheel. Substituting the given values, we have:
a = (20 m/s)^2 / 0.4 m
= 1000 m/s^2
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if a 4kg crate is being pulled to the right with a force of 20 n and it experiences a friction force of 5n what is its acceleration
If a 4kg crate is being pulled to the right with a force of 20 n and it experiences a friction force of 5n. The acceleration of the crate is 3.75 m/s².
The net force acting on the 4kg crate can be calculated by subtracting the friction force from the applied force:
20N - 5N = 15N.
To find the acceleration, use Newton's second law, F = ma.
Rearranging the equation to solve for acceleration:
a = F/m.
In this case,
a = 15N / 4kg
a = 3.75 m/s².
So, the acceleration of the crate is 3.75 m/s² to the right.
The rate at which an object's velocity varies over time is called accelaration. It is, in other words, the change in velocity per unit time. Acceleration occurs when an item accelerates, decelerates, or changes direction.
In the International System of Units, acceleration is typically measured in metres per second squared (m/s^2) (SI).
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when will a new moon appear
Answer:on april 20th at aproximately 12: 12 a.m
a heat pump is used to heat a house. it have a desired output of heat at a rate of 10 kw, and it accepts 5 kw of work. determine the cop of the heat pump.
The COP of the heat pump is 2. The coefficient of performance (COP) is a measure of the efficiency of a heat pump, defined as the ratio of the desired output of heat to the input of work.
In this case, the desired output of heat is 10 kW and the input of work is 5 kW, so the COP of the heat pump is: COP = desired output / input of work COP = 10 kW / 5 kW COP = 2
which means that for every unit of work input, the heat pump produces two units of desired output heat. This is a measure of the efficiency of the heat pump, with higher COP values indicating better efficiency.
Heat pumps are a popular and efficient way to heat homes, as they can extract heat from the outside air or ground, and use it to heat the indoor air. The COP of a heat pump can vary depending on factors such as the temperature difference between the inside and outside, and the efficiency of the components used in the system.
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An airplane flies at 120km/h relative to air. There is a wind blowing at 90km/h relative to the ground. Calculate the speed of the airplane relative to the ground if.
a) they have opposite direction
b) perpendicular.
Explanation:
a) if theya re OPPOSITE then the wind speed subtracts from the airplane's speed ( a headwind) sooooo 120 - 90 = 30 km/hr
b) if the two speeds are perpendicular , you can use Pythagorean theorem:
R^2 = 120^2 + 90^2
R = 150 km/hr
When warm air rises in a convection current, what happens next?
Please I need help!
Answer:
cool air flows toward the ground
Explanation:
Answer:
it brings heat
Explanation:
or it can lead you to death when warm air rises
what is the maximum torque that can be obtained with the same total length of wire carrying the same current in this magnetic field?
This τmax = N(IL²/16)B torque is proportional to the number of turns in the loop, the current in the wire, the area of the loop, and the magnetic field. So to maximize the torque.
The maximum torque that can be obtained in a magnetic field is when the loop is perpendicular to the magnetic field. In this case, the torque is given by:
τ = NABsinθ
where N is the number of turns in the loop, A is the area of the loop, B is the magnetic field, and θ is the angle between the normal to the loop and the direction of the magnetic field.
The total length of the wire is used to make the loop, so the length of each side of the loop is L/4, where L is the total length of the wire. The area of the loop is then:
A = (L/4)² = L²/16
The current in the wire is I, and the magnetic field is B, so the torque can be written as:
τ = N(IL²/16)Bsinθ
To maximize the torque, we want sinθ to be 1, so the loop should be perpendicular to the magnetic field.
Thus, the maximum torque is: τmax = N(IL²/16)B
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Why does 250 N not push an object when frictional force is 188 N while 251 N is pushing with fast acceleration.
Due to the difference in net force delivered to the item in each situation, 250 N cannot push an object while the frictional force is 188 N, whereas 251 N may push the identical thing with rapid acceleration.
When there is friction, what happens to acceleration?When friction is present, an object may continue to travel at a steady speed despite the application of an external force. The friction force simply balances the applied force in this scenario. There is no acceleration since there is no net force.
Does friction increase as you go faster?No, acceleration has no impact on the kinetic friction coefficient. The type of surfaces that make contact with one other and not the speed at which they are travelling determine the coefficient of kinetic friction, which is constant.
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the objective and the eyepiece of a microscope have focal lengths of 4.00 mm and 25.0 mm, respectively. the objective produces a real image 30 times the size of the object. the final image is viewed at infinity, and the near point of the microscope user is at 25.0 cm. what is the distance between the object and the focal point of the objective? question 2 options: 0.13 mm 0.18 mm 0.23 mm 0.28 mm 0.33 mm
The distance between the object and the focal point of the objective is 0.18 mm. Option 2 is correct.
To solve this problem, we can use the thin lens equation:
[tex]\frac{1}{f} = \frac{1}{do} +\frac{1}{di}[/tex]
where f is the focal length of the lens, do is the distance between the object and the lens, and di is the distance between the lens and the image.
We know that the focal length of the objective is 4.00 mm, and the focal length of the eyepiece is 25.0 mm. We also know that the image produced by the objective is 30 times the size of the object. Finally, we know that the final image is viewed at infinity, and the near point of the microscope user is at 25.0 cm.
Using these values and some algebra, we can solve for do:
1/4 = 1/do + 1/(30*25)
1/do = 0.0008 - 0.00133
1/do = -0.00053
do = -1.89 mm
Since the object is located in front of the lens, we know that the distance between the object and the focal point of the objective is positive. Therefore, we can use the relationship do = f/(1 - m) to find the distance:
do = 4.00 mm / (1 - 30)
do = 0.18 mm
As a result, the distance between the object and the objective's focus point is 0.18 mm. Option 2 is correct.
The complete question is
The objective and the eyepiece of a microscope have focal lengths of 4.00 mm and 25.0 mm, respectively. the objective produces a real image 30 times the size of the object. the final image is viewed at infinity, and the near point of the microscope user is at 25.0 cm. what is the distance between the object and the focal point of the objective?
Options:
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A runner covers the last straight stretch of a race in 4s During the time he speeds up from 5m/s to 9ms. What is the runners acceleration in this part of the race?
Answer: 1m/s^2
Explanation: The formula to find acceleration is:
a = (vf - vi) / t
where:
a= acceleration
vf= final velocity
vi= intial velocity
t= time
By substituting these values in the acceleration equation, we obtain:
a = (9 m/s - 5 m/s) / 4 s
we get:
a = 1 m/s^2
a roller coaster needs to complete a vertical loop that has radius 10 m what must its minimum speed be at top of loop ?
Answer:
9.90 m/s.Explanation:
In order for the roller coaster to complete a vertical loop of radius 10 m, it must have enough speed at the top of the loop to overcome the force of gravity and maintain contact with the track. At the top of the loop, the roller coaster is momentarily at rest (i.e., its speed is zero), and the only force acting on it is gravity. Therefore, we can use the following equation to find the minimum speed required:
Centripetal force = Weight of the roller coasterwhere m is the mass of the roller coaster, v is its speed at the top of the loop, r is the radius of the loop, and g is the acceleration due to gravity.
Solving for v, we get:
v = √(gr)Substituting in the given values, we get:
v = √(9.81 m/s^2 * 10 m)v = 9.90 m/sTherefore, the minimum speed that the roller coaster must have at the top of the loop is 9.90 m/s.The roller coaster's minimum speed at the top of the loop should be approximately 9.90 m/s that has radius 10 m.
To complete a vertical loop without falling off at the top, the roller coaster must have sufficient speed to counteract gravity.
At the top of the loop, the minimum speed required can be found using the concept of centripetal force.
At the top of the loop, the centripetal force (provided by the roller coaster's speed) must equal the force due to gravity. This can be expressed as:
[tex]mv^2[/tex]/ r = mg
Where m is the mass of the roller coaster, v is its speed, r is the radius of the loop, and g is the acceleration due to gravity
(approximately 9.81 [tex]m/s^{2}[/tex]).
Solving for v:
[tex]v^2 = rg[/tex]
v = [tex]\sqrt{(10 m * 9.81 m/s^{2} )[/tex] ≈ [tex]\sqrt{(98.1 m^{2} /s^{2} )[/tex] ≈ 9.90 m/s
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Can omeone help me with 1 and two
Answer: f = 0.6 per sec
54 cycles in 90 sec
Explanation:
a simple point-and-shoot camera uses 35 mm film (actually 36 mm wide and 24 mm tall). what is the required focal length of the camera in order that it has a horizontal angle of view of 52o? use the fact that the maximum image size that the film can capture occurs when the image height is equal to half the width of the film.
The required focal length of the camera in order to have a horizontal angle of view of 52° is approximately 27.2 mm.
To find the required focal length of the camera, we need to use the given information and the formula for angle of view. Here's a step-by-step explanation:
1. The maximum image size on the film occurs when the image height is equal to half the width of the film. So, the image height is 36 mm / 2 = 18 mm.
2. Since the image dimensions are 36 mm wide and 18 mm tall, we will focus on the horizontal angle of view, which is 52°.
3. The formula for the angle of view (α) is given by:
α = 2 * arctan (d / (2 * f))
where α is the angle of view, d is the image width, and f is the focal length.
4. We want to find the focal length (f) using the given angle of view (α) and the image width (d).
Rearrange the formula:
f = d / (2 * tan(α/2))
5. Plug in the values: α = 52° and d = 36 mm:
f = 36 / (2 * tan(52°/2))
6. Calculate the result:
f ≈ 27.2 mm
The required focal length of the camera in order to have a horizontal angle of view of 52° is approximately 27.2 mm.
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if two bodies contact one another without slipping, and the points in contact move along different paths, the tangential components of acceleration will be
When two bodies contact each other without slipping and the points in contact move along different paths, the tangential components of acceleration will be different. This means that the bodies will have different accelerations along the tangential direction.
Tangential acceleration refers to the component of an object's acceleration that is parallel to the object's velocity vector. As an object moves, its velocity vector changes in direction, and thus the direction of its acceleration vector also changes.
The tangential acceleration is the part of this vector that is parallel to the velocity vector. It is also referred to as the longitudinal acceleration.
When two bodies make non-slip contact and the points of contact travel along distinct routes, the tangential components of acceleration diverge. This indicates that the bodies' accelerations will differ along the tangential direction.
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suppose a 200-mm focal length telephoto lens is being used to photograph mountains 9.5 km away. show answer no attempt 50% part (a) what is image distance, in meters, for this lens?
Suppose a 200-mm focal length telephoto lens is being used to photograph mountains 9.5 km away, The image distance for this lens is approximately 0.200 m (200 mm).
To calculate the image distance for a 200-mm focal length telephoto lens photographing mountains 9.5 km away, we can use the lens formula:
1/f = 1/do + 1/di
where f is the focal length (200 mm), do is the object distance (9.5 km), and di is the image distance we want to find.
Step 1: Convert distances to the same units (meters).
Focal length: 200 mm = 0.2 m
Object distance: 9.5 km = 9500 m
Step 2: Plug the values into the lens formula.
1/0.2 = 1/9500 + 1/di
Step 3: Rearrange the formula to solve for di.
1/di = 1/0.2 - 1/9500
Step 4: Calculate the value of 1/di.
1/di = 5 - 0.00010526
1/di = 4.99989474
Step 5: Find the value of di by taking the reciprocal of the previous result.
di = 1/4.99989474
di ≈ 0.200021 m
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what are the two correct answers to this question
Answer:
Most probably mass and volume
Explanation:
i dont think you can really measure it from its color i dont think measurements work that way lol. temperature cant be the option because all of them are likely to be in the same condition and time is just an absurd way to measure a object
For the solar cooker project, the two measurements that students should make to determine the dependent variable are: temperature and time.
What are the measurement that student should make to determine the dependent variable?Two measurements that students should make to determine the dependent variable are :
Temperature: The students should measure the temperature of the food being cooked at different times of day and under different conditions, such as with or without insulation, with or without reflective materials, and so on. The temperature would be dependent variable because it is directly related to the rate of cooking. The higher the temperature, then faster the food will cook.
Time: The students should measure the time it takes to cook the food under different conditions. The time would be a secondary dependent variable because it is also directly related to rate of cooking. The faster the food cooks, the shorter the cooking time will be.
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X moves at a speed of 65km/hrs while Y who is behind X moves at a speed of 80km/hrs. What is the relative velocity of X with respect to X
They both go in the same direction, thus their velocities will cancel out as they move in the same direction. then it would be calculated by subtracting the speed of X from the speed of Y, which would be 15km/hrs.
Which formula represents relative velocity?This is possible to calculate it by using a middle frame. The possible combination of a speeds is one way to put this into words. As stated, vAB = si le - visual basic is the angular acceleration equation.
Demonstrate relative velocity using a example.A scalar difference between the velocities for two bodies is the concept of relative velocity. the speed of a body in relation to another that is thought to be at rest – compare relative motion. For instance, if a vehicle is moving in a righteous line at a consistent speed, it is possible toss & grab an object in movement.
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when soot lands on snow and ice, the absorption of thermal energy increases because there is a decrease in
Soot is a dark-colored substance made up of tiny particles of carbon. When soot lands on snow and ice, it darkens the surfaces and decreases the albedo, or reflectivity, of that surface.
This means that less sunlight is reflected back into the atmosphere, and more is absorbed by the snow and ice. This absorption of thermal energy causes the snow and ice to melt more quickly.
Additionally, the soot particles act like tiny heat absorbers and further increase the temperature of the snow and ice. This can further speed up the melting process and contribute to a decrease in global snow and ice cover. In turn, this can have serious environmental consequences, such as sea level rise and increased global temperatures.
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a bungee jumper jumps from a platform and is decelerated by an elastic bungee cord, as shown. at which part of the jump are all three types of energy non-zero?
At the part of the bungee jump where all three types of energy (potential energy, kinetic energy, and elastic potential energy) are non-zero is when the jumper is falling and the bungee cord starts to stretch but has not yet reached its maximum extension.
1. The jumper starts with potential energy (height) and zero kinetic energy (not moving) and zero elastic potential energy (cord not stretched).
2. As the jumper falls, the potential energy decreases, and kinetic energy increases (due to acceleration), while the elastic potential energy is still zero (cord not stretched yet).
3. When the bungee cord starts to stretch, all three types of energy are non-zero: potential energy (some height remains), kinetic energy (still moving), and elastic potential energy (cord stretching).
4. At the maximum extension of the cord, kinetic energy becomes zero (momentarily stopped), potential energy is still non-zero (height), and elastic potential energy is at its maximum (cord fully stretched).
Therefore, the three types of energy are potential energy, kinetic energy, and elastic potential energy.
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