With a density of 0.875 g/cm³, a sample of 0.60 g of this oil would have a volume V such that
0.875 g/cm³ = (0.60 g)/V ==> V ≈ 0.686 cm³
If the oil is spread out uniformly over the water's surface, then it forms a cylinder whose diameter is equal to that of the dish, 21.6 cm. Then the thickness d of the oil cylinder is such that
V = π ((21.6 cm)/2)² d ==> d ≈ 0.0202 cm
what is a molecule??
Answer:
molecule, a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance
Explanation:
Here are examples of common molecules:
H2O (water)
N2 (nitrogen)
O3 (ozone)
CaO (calcium oxide)
C6H12O6 (glucose, a type of sugar)
NaCl (table salt)
Explanation:
molecule, a group of two or more atoms that form the smallest identifiable unit into which a pure substance can be divided and still retain the composition and chemical properties of that substance
A car has four tires that are each inflated to an absolute pressure of 2.0 x 10^5 Pa. Each tire has an area of 0.024 m^2 in contact with the ground. How much does the car weigh?
a.
1.9 x 10^3 N
b.
2.9 x 10^4 N
c.
1.2 x 10^3 N
d.
1.9 x 10^4 N
Answer:
If u dig a hole 3 feet how big is that hole
Explanation:
It’s about 20 feet
If a horse can trot with an average velocity of 13 km/h, how far can it travel in
8 hours?
A. 2 km
B. 104 km
C. 35 km
D. 78 k
Answer:
104 km
Explanation:
Displacement = Velocity x Time
= 13 x 8
= 104 km
a ball is thrown straight up into the air with an initial speed of 3.1 m/s. a. After 0.24 seconds what is the ball's velocity and b. what is it's acceleration?
a. The ball's velocity after 0.24 s is 0.75 m/s
b. The acceleration of the ball is given by the acceleration due to gravity
a. The ball's velocity can be calculated with the following equation:
[tex] v_{f} = v_{0} - gt [/tex]
Where:
[tex] v_{f} [/tex]: is the final speed =?
[tex]v_{0}[/tex]: is the initial speed = 3.1 m/s
g: is the acceleration due to gravity = 9.81 m/s²
t: is the time = 0.24 s
The minus sign is because the acceleration is in the opposite direction (downward) of the motion of the ball (upward).
The final speed is:
[tex] v_{f} = v_{0} - gt = 3.1 m/s - 9.81 m/s^{2}*0.24 s = 0.75 m/s [/tex]
Hence, the ball's velocity after 0.24 s is 0.75 m/s.
b. The acceleration of the ball is given by the acceleration due to gravity because the ball is thrown straight up (the motion of the ball is in the y-direction). The velocity of the ball in the x-direction is zero so the acceleration in the same direction is also zero.
You can see another example of velocity here: https://brainly.com/question/13388351?referrer=searchResults
I hope it helps you!
Help meh in this question plzzz
The Moment of Inertia of the Disc is represented by [tex]I = \frac{15}{32}\cdot M\cdot R^{2}[/tex]. (Correct answer: A)
Let suppose that the Disk is a Rigid Body whose mass is uniformly distributed. The Moment of Inertia of the element is equal to the Moment of Inertia of the entire Disk minus the Moment of Inertia of the Hole, that is to say:
[tex]I = I_{D} - I_{H}[/tex] (1)
Where:
[tex]I_{D}[/tex] - Moment of inertia of the Disk.[tex]I_{H}[/tex] - Moment of inertia of the Hole.Then, this formula is expanded as follows:
[tex]I = \frac{1}{2}\cdot M\cdot R^{2} - \frac{1}{2}\cdot m\cdot \left(\frac{1}{2}\cdot R^{2} \right)[/tex] (1b)
Dimensionally speaking, Mass is directly proportional to the square of the Radius, then we derive the following expression for the Mass removed by the Hole ([tex]m[/tex]):
[tex]\frac{m}{M} = \frac{R^{2}}{4\cdot R^{2}}[/tex]
[tex]m = \frac{1}{2}\cdot M[/tex]
And the resulting equation is:
[tex]I = \frac{1}{2}\cdot M\cdot R^{2} -\frac{1}{2}\cdot \left(\frac{1}{4}\cdot M \right) \cdot \left(\frac{1}{4}\cdot R^{2} \right)[/tex]
[tex]I = \frac{1}{2} \cdot M\cdot R^{2} - \frac{1}{32}\cdot M\cdot R^{2}[/tex]
[tex]I = \frac{15}{32}\cdot M\cdot R^{2}[/tex]
The moment of inertia of the Disc is represented by [tex]I = \frac{15}{32}\cdot M\cdot R^{2}[/tex]. (Correct answer: A)
Please see this question related to Moments of Inertia: https://brainly.com/question/15246709
Answer:
Help meh in this question
Explanation:
Stella's respiratory system is not working well why is this a problem for her ability to exercise
Explanation:
Her cells will not work well when they have low levels of oxygen.
An astronaut floating in space is trying to use her jetpack to get back to her space station, but she is being pulled away by a nearby planet, as shown in the image below. Her jetpack provides a constant thrust of 165 N. If she angles her jetpack in such a way that it cancels out the vertical force due to the planet's gravity, what is her net horizontal force?
A. 132.6 N toward the space station
B. 53.3 N away from the space station
C. 98.5 N toward the space station
D. 112.8 N away from the space station
Answer:
C. 98.5N toward the space station
Explanation:
Fx= Fjet×cos(20) - Fplanet × cos(45) = 98.5
Because the result is positive so she is going toward the space station
Convert each of the following speed into m/sec:
(i) 72 km/h
(ii) 12.6 km/h
(iii) 23.4 km/h
(iv) 306 km/h
Answer:
(i) 20 m/s
(ii) 3.5 m/s
(iii) 6.5 m/s
(iv) 85 m/s
Explanation:
1(kilometer/hour) = 1000(meters) / 3600(seconds) can also be expressed as 1(kilometer/hour) = 5/18 (meters/second), which is its simplified form. To convert km/h to m/s, directly multiply the given value of speed by the fraction 5/18.
This information is from: https://www.cuemath.com/measurement/km-h-to-m-s/
1. A car moving with a velocity of 10 m s-1 accelerates uniformly at 1 m s-2 until it reaches a velocity of 15 m s-1. Calculate (i) the time taken (ii) the distance traveled during the acceleration (ui) the velocity reached 100 m from the place where the acceleration began. m/sec
A Sling Shot accelerates a 12 g Stone to a velocity of
35m/s within a distance of 5.0cm to what (constant force
is the stone subjected during the acceleration
Answer:
Please mark brainliest
Answer:
[tex]\huge\boxed{\sf F = 147 N}[/tex]
Explanation:
Given:
Mass = m = 12 g = 0.012 kg
Final Velocity = Vf = 35 m/s
Initial Velocity = Vi = 0 m/s
Distance = S = 5 cm = 0.05 m
Required:
Force = F = ?
Formula:
3rd equation of motion
2aS = Vf²-Vi²
Solution:
2aS = Vf²-Vi²
a = (35)²- (0)² / 2S
a = 1225 / 2(0.05)
a = 1225 / 0.1
a = 12250 m/s²
Force = Mass x Acceleration
F = 0.012 x 12250
F = 147 N
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807Peace!the precision of interferometer of wavelength of light 800 nm would be: (a) 200 nm (b) 100 nm (c) 400 nm (d) 800 nm
Answer:
Explanation:
Did this come with a Picture?
should money be used for space travel when there are so many serious problems on Earth to be addressed? explain your answer.
Answer:
Anyway, space exploration absolutely does give us a direct benefit. When space technology has advanced far enough, we will be able to leave this planet in large numbers and live among the stars. This will solve our population/environment/resource/energy problems for a long, long time. Even a fraction of the money spent annually on space exploration could save millions of people in poverty-stricken countries, and improve living conditions for future generations. The foundations of the world we live in are largely based on science and it is indeed vital to extend our knowledge of the universe.
Thank You
Please mark me brainliest
Encontrar el peso de un elefante cuya masa es de 4500kg. Recordar que la gravedad es de 9.8m/s2
la respuesta es 459.183673 kg s2 / m
Answer:
44,100 N
Explanation:
4500(9.8) = 44,100
do humans have the right to alter and colonize unique environments on another planet? explain your answer.
Answer:
We may have people making habitats on asteroids ... I know that humans will colonize the solar system and one day go beyond. Richard Gott has estimated that the human race could survive for another 7.8 million years, but it is not likely to ever colonize other planets.
To be sure there are many daunting challenges facing prospective space colonists such as protection from exposure to deadly radiation levels, the impact on the human body while living and working in cramped, low-gravity environments for extended periods of time and the psychological toll of isolation and confinement.
According to me we can't colonize other planets which is against humanity
□: the action of an object spinning around on its □
Answer:
head gyxicjcurgcugxgox6r
The speed of light will be minimum while passing through
A) water
B) vaccum
C) air
D) glass
Answer:
The correct choice is option D. glass
Glass's optical density is very great. Which is why speed of light will be minimum when passing glass.
Answer:
glass
Explanation:
i think, sana makatulong
differentiate between air pressure and liquid pressure in table .
Air pressure or atmospheric pressure is the pressure as the force exerted by the collisions of particles in the air.
The key difference between air pressure and liquid pressure is that air pressure allows the gaseous state of matter to be compressible, whereas liquid pressure makes a liquid incompressible
Answer:
Air pressureAtmospheric pressure, also known as barometric pressure, is the pressure within the atmosphere of Earth. The standard atmosphere is a unit of pressure defined as 101,325 Pa, which is equivalent to 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.
Liquid pressureLiquid pressure is the increase in pressure at increasing depths in a liquid. This pressure increases because the liquid at lower depths has to support all of the water above it. We calculate liquid pressure using the equation liquid pressure = mass x acceleration due to g density x depth in fluid.
What are two benefits of scientists using a diagram to model the water cycle?
A. It can show changes that occur in many different parts of Earth at
the same time.
B. It can be used to show how the parts of the cycle relate to one
another.
C. It can be used to show as much detail as is present in the actual
water cycle.
OD. Only a few factors in the water cycle can be shown on the
diagram.
Explanation:
it can be used to show how the parts of the cycle relate to one another
An eccentric emu runs 20 m/s for 5 minutes for the first part of his trip to Hollywood. Once tired, the emu runs slower speed for the next hour. The average velocity of the emu is 15 m/s. what speed was the emu running when he was tired?
Answer:
14.6 m/s
Explanation:
The total run time was 5 + 60 = 65 minute or 65(60) = 3900 s
At his average velocity, emu ran 15 m/s(3900 s) = 58,500 m
Which is a heck of a running distance for ANY emu.
In the first 5 minutes the emu traveled 20 m/s(5 min)(60 s/min) = 6000 m
So in the last hour (3600 s) the emu traveled 58,500 - 6000 = 52,500 m
at a speed of 52,500 m /3600 s = 14.583333333... m/s
The emu was running at a speed of 14.58 m/s when he was tired.
To solve this question, we'll begin by calculating the distance travelled in the first part of the trip. This can be obtained as follow:
Time (t₁) = 5 min = 5 × 60 = 300 s
Speed 1 (S₁) = 20 m/s
Distance 1 (d₁) =?Speed = distance / time
S₁ = d₁ / t₁
20 = d₁ / 300
Cross multiply
d₁ = 20 × 300
Distance 1 (d₁) = 6000 mNext, we shall determine the total distance travelled by the emu.
Average speed = 15 m/s
Time 1 (t₁) = 300 s
Time 2 (t₂) = 1 h = 60 mins = 60 × 60 = 3600 s
Total time (T) = t₁ + t₂ = 300 + 3600 = 3900 s
Total distance (D) =?Average speed = Total distance / total time
15 = D / 3900
Cross multiply
D = 15 × 3900
Total distance (D) = 58500 mNext, we shall determine the distance travelled in the second part (i.e when he was tired) of the trip.
Total distance (D) = 58500 m
Distance 1 (d₁) = 6000 m
Distance 2 (d₂) =?D = d₁ + d₂
58500 = 6000 + d₂
Collect like terms
58500 – 6000 = d₂
Distance 2 (d₂) = 52500 mFinally, we shall determine the speed of the emu in the second part of the trip.
Distance 2 (d₂) = 52500 m
Time 2 (t₂) = 3600 s
Speed 2 (S₂) =?Speed = distance / time
S₂ = 52500 / 3600
S₂ = 14.58 m/sTherefore, the emu was running at a speed of 14.58 m/s when he was tired.
Learn more: https://brainly.com/question/24502267
Hey any physicist or engineer around. am giving brainliest to anyone who will answer this question.
Answer:
N = 167 Newtons
R = 727 Newtons
Explanation:
i) For static equilibrium, moments about any convenient point must sum to zero.
A moment is the product of a force and a moment arm length. Only the force acting perpendicular to a moment arm passing through the pivot point makes a moment.
ii) I will ASSUME the two moment arms are 0.05m and 0.15 m
CCW moments about the fulcrum are
190 N(0.2 m) + 280 N(0.05 m) = 52 N•m
CW moments are (N)N(0.15 m + 90 N(0.3 m) = 27 + 0.15N N•m
For static equilibrium, these must be equal
27 + 0.15N = 52
0.15N = 25
N = 166.6666666...
Sum moments about N to zero
(Same as saying CW and CCW moments must balance)
190(0.2 + 0.15) + 280(0.05 + 0.15) - R(0.15) - 90(0.3 - 0.15) = 0
R = 726.6666666...
We could verify this by summing vertical forces to zero.
R - 190 - 280 - 166.666666 - 90 = 0
R = 726.6666666...
If Leslie has a hang time of 0.2 seconds, what distance did she jump?
Answer:
um.......I don't know soory
Consider the mass-on-a-spring system as shown in the figure below. The spring has a spring constant of 1.81e+3 N/m, and the block has a mass of 0.988 kg. There is a constant force of kinetic friction between the mass and the floor of 1.79 N. Starting with the spring compressed by 0.172 m from its equilibrium position, how far will the block travel once it leaves the spring? (Assume that block leaves the spring at at the spring's equilibrium position, marked x=0 in the figure.
K1Answer:
s= 6.5cm
Explanation:
Point 1: just right before the block leaves the spring
Point 2: the block has v2=0 (stops moving)
Apply Kinetic-Work Theorem:
K1 + U1 + Wother = K2 + U2
K1=0
U1= 1/2×k×x² (k= 1.81e+3 N/m and x= -0.172 m)
Wother = F×s= 1.79×s
K2=0
U2=0
=> s= 6.5cm
This is my attempt to solve. Let me know if this isn't right
the value of mass of a body is everywhere
Explanation:
The value of mass of a body is not same everywhere.
Because it depends on gravity and the gravity isn't same at every places.
Answer:
Mass is the quantity of matter contained in a body, while weight is the force by which the body is pulled to the earth's center. Mass is an intrinsic property of a body, as it remains the same everywhere in the universe. Weight is variable due to change in the magnitude of the gravitational force applied by the earth.
A pulse has a speed of 5cm.s^-1. How far does it travel in 2,5s?
Answer:
12.5
Explanation:
Its 5m per second times 2.5 seconds so it's 12.5m
Answer:
[tex]\boxed {\boxed {\sf 12.5 \ centimeters}}[/tex]
Explanation:
We are asked to find how far a pulse travels or the distance. Distance is the product of speed and time.
[tex]d= s \times t[/tex]
The speed of the plus is 5 centimeters per second and the time is 2.5 seconds.
s= 5 cm/s t= 2.5 sSubstitute the values into the formula.
[tex]d= 5 \ cm/s \times 2.5 \ s[/tex]
Multiply. Note that the units of seconds will cancel each other out.
[tex]d= 12.5 \ cm[/tex]
The pulse travels 12.5 centimeters.
multiples and submultiples of kg
Answer:
Submultiples of kilogram are decagram ,centigram etc. And multiples of kilogram is megagram(1 tonne) , gigagram etc.
hope this helps you:)
Two long straight parallel wires seperated by 20cm apart carry current of 20A and 1OA in opposite directions. What is the magnitude of the force on 1m length of the 20A wire
Answer:
Force is 2 × 10^-4 N
Explanation:
[tex]{ \bf{F = \frac{ \gamma_{o} I _{1} I _{2} l}{2\pi r} }}[/tex]
F is force
I is current
r is separation distance
gamma is a constant
l is wire length
[tex]F = \frac{(4\pi \times {10}^{ - 7}) \times (20) \times (10) \times 1 }{2\pi \times 0.2} \\ \\ F = 2 \times {10}^{ - 4} \: \: newtons[/tex]
The magnitude of the force on 1m length of the 20A wire is 2×10⁻⁴N.
To determine the answer, we need to know about magnetic field due to a current carrying wire and magnetic force.
What is the magnetic field produced due to a straight current carrying wire of current I₁?The magnetic field due to a straight wire having current I₁ at a perpendicular distance (say) 'd' is μ₀I₁ / 2[tex]\pi[/tex]d.
What is the magnetic force experienced by a straight wire of current I₂?Magnetic force on a current carrying wire of length 'L' and having current I₂ is I₂(L×B). Where B is the magnetic field at that wire.
What is the magnetic field on 20A wire due to 10A wire?d= 0.2m and I₁= 10AB= μ₀I₁ / 2[tex]\pi[/tex]d = 4[tex]\pi[/tex] ×10⁻⁷× 10/ 2[tex]\pi \\[/tex]×0.2 = 10⁻⁵ TWhat is the force on 20A wire?Current (I₂) = 20A, B = 10⁻⁵T and L= 1mMagnitude of force on the 20 A wire of length 1m = I₂×L×B( Here L and B are perpenicular to each other so L×B= L·B)
= 20×1×10⁻⁵
=2×10⁻⁴N
Thus, we can conclude that the magnitude of the force on 1m length of the 20A wire is 2×10⁻⁴N.
Learn more about magnetic force here:
https://brainly.com/question/25932320
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of a ball traveling 24 m in 0.6 seconds.
A baseball pitcher throws a fastball across home plate. Calculate the speed of a
baseball that takes 0.01 seconds to travel 0.30 meters across the entire length of home
plate.
Answer:
Below
Explanation:
To find the speed of an object you can use this formula
speed = displacement / elapsed time
For the first one
24 m / 0.6 seconds = 40 m/s
For the second one
0.3 m / 0.01 seconds = 30 m/s
Hope that helped
calculate the volume that 42g of nitrogen gas (N2)occupies at standard temperature and pressure.
Nitrogen gas has a molar mass of about 28.0134 g/mol. Then we have a starting amount of
(42 g) / (28.0134 g/mol) ≈ 1.4993 mol
of N₂.
At standard temperature and pressure, one mole of an ideal gas occupies a volume of about 22.4 L. Then 42 g, or 1.4993 mol, of N₂ takes up
(1.4993 mol) × (22.4 L/mol) ≈ 33.6 L
A plane leaves Houston and flies 400 km north to Dallas. The pilot realizes he has forgotten his
golf clubs and returns to Houston to pick them up on the way back to Houston, the plane runs
out of gas and is forced to land in Huntsville, 100 km North of Houston. The trip from Houston to
Dallas took 120 min and the trip from Dallas to Huntsville took 70 min.
A. What is the total distance (in meters) covered by the airplane?
B. What is the plane's total displacement (in meters)?
C What is the average velocity for: 190 MM
i Houston to Dallas
ii. Dallas to Huntsville
(A) The total distance covered by the plane is 500,000 m
(B) The plane's total displacement is 300,000 m
(C) The average velocity of the plane is 100 m/s
The given parameters:
initial displacement of the plane = 400 km Dallas
final displacement of the train = 100 km Huntsville
the time taken for the initial displacement = 120 min
final time for the second trip = 70 min
A sketch of the plane's trip is as follows:
Dallas
400 km ↑ ↓
↑ ↓ Huntsville 100 km
↑
↑
Houston
(A) The total distance covered by the plane:
The total distance is the total path travelled by the plane.
Total distance = 400 km + 100 km = 500 km, = 500,000 m
(B) The plane's total displacement:
The total displacement is the change in the position of the plane.
The displacement = 400 km - 100 km = 300 km = 300,000 m
(C) The average velocity of the plane
[tex]Average \ velocity = \frac{change \ in \ displacement }{change \ in \ time} \\\\Average \ velocity = \frac{400 \ km - 100 \ km}{120 \ \min - \ 70 \ \min} \\\\Average \ velocity =\frac{300 \ km}{2\ hr - 1.167 \ hr} \\\\Average \ velocity = \frac{300 \ km}{0.833 \ hr} \\\\Average \ velocity = 360.14 \ km/hr\\\\Average \ velocity = \frac{360.14 \ km/h}{3.6 \times \frac{km/hr}{m/s} } = 100 \ m/s[/tex]
Learn more here: https://brainly.com/question/12409152
Water is flowing in a pipe with a varying cross-sectional area, and at all points the water completely fills the pipe. At point 1 the cross-sectional area of the pipe is 0.070 m^2, and the magnitude of the fluid velocity is 3.50 m/s.
Required:
a. What is the fluid speed at point in the pipe where the cross-sectional area is 0.105m^2?
b. What is the fluid speed at point in the pipe where the cross-sectional area is 0.047m^2?
c. Calculate the volume of water discharged from the open end of the pipe in 1.00hour.
Answer:
b
Explanation: