A bag contains 3 red balls and 5 green balls. What is the probability of picking a red ball from the bag AND getting heads upon flipping a fair coin

Answer:

the probability would be 3/8

Step-by-step explanation:

Since there are 3 red and 5 green, there is a total of 8 balls in the bag making it a chance of 3/8 to get a red ball. You're Welcome :) <3

Probability of picking a red ball is  [tex]\frac{3}{8}[/tex]

Probability of getting head coin is  [tex]\frac{1}{2}[/tex]

"Probability is the possibility or chance of an event to occur." Ratio of number of favorable outcomes and total number of favorable outcomes is called probability.

We have,

Red balls = 3

Green balls =5

Formula for probability

 [tex]\frac{Number of Favorable Outcomes}{Total Number of Favorable Outcomes}[/tex]

Total number of outcomes n(S) = 8

Number of favorable outcomes for getting a red ball n(E) = 3

Probability of picking a red ball

= [tex]\frac{Number of Favorable Outcomes}{Total number of Favorable Outcomes}[/tex]

= [tex]\frac{3}{8}[/tex]

We have a fair coin,

Total number of outcomes n(S) = 2

Number of favorable outcomes for getting head n(E) = 1

Probability of getting head coin

= [tex]\frac{Number of Favorable Outcomes}{Total Number of Favorable Outcomes}[/tex]

= [tex]\frac{1}{2}[/tex]

Hence, Probability of picking a red ball is  [tex]\frac{3}{8}[/tex]

Probability of getting head coin is  [tex]\frac{1}{2}[/tex].

Learn more about probability here

https://brainly.com/question/15052059

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