6. The unit circle with center at the origin is a relation but not a function.
Find the two functions which are semicircles of the unit circle, and determin
e
their domains and ranges?
b. Are these functions onto functions? Justify.
c. Find the two functions which are lie in one of the semicircle in part a, and
determine their domains and ranges?
d. Are these functions one to one correspondence functions? Justify.
Whi​

Answers

Answer 1

Answer:

Step-by-step explanation:


Related Questions

The points (a,b) and (c,d) form a segment, and the points (d,e) and (d,f) form a segment. Create an equation assuming the segments are congruent

Answers

If the segments are congurent they are of equal length.

So constructing an equation will not be hard.

Take for example [tex]y=x[/tex] and limit x to be between and including 0 and 1 for the first segment. In this case our segment is [tex](a,b)\to(c,d)=(0,0)\to(1,1)[/tex].

Now, d has been fixated to the value of 1 and we need to construct a segment from [tex](1,e)\to(1,f)[/tex].

Since both x coordinates of the endpoints of the segment are fixed to be 1, we cannot run anymore, that is, we fixated our run. But on the rise (y-axis direction) we can still move one unit up.

Let e be 1 and f be 2. The distance between [tex](1,1)[/tex] and [tex](1,2)[/tex] is 1 which is also the distance between [tex](0,0)[/tex] and [tex](1,1)[/tex].

Now we are asked to find the equation of both segments.

First segment is described by [tex]y=x[/tex] with limited domain of [tex]0\leq x\leq1[/tex].

Second segment is described by [tex]x=2[/tex] with again limited domain of [tex]1\leq y\leq2[/tex].

Hope this helps :)

The length, l of a segment with points (x₁, y₁), and (x₂, y₂) is presented as follows; [tex]l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}[/tex]

An equation that can be created given that the segment with points (a, b) and (c, d), and the segment with points (d, e), and (d, f) are congruent is presented as follows;

√((d - b)² + (c - a)²) = f - e

The reason the above equation is correct is presented as follows;

Given that the segments are congruent, therefore;

Length of (a, b) and (c, d) = Length of (d, e) and (d, f)

Length of (a, b) and (c, d) = √((d - b)² + (c - a)²)

Length of (d, e) and (d, f) = √((f - e)² + (d - d)²) = f - e

Which gives the equation;

√((d - b)² + (c - a)²) = f - e

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A rectangular plastic tub is 70 centimetres long, 30 centimetres wide, and 30 centimetres tall. How many litres of water will it hold?

Answers

V = a*b*c
a=70
b=30
c=30
V = 70*30*30
V = 63,000 Cm^3
And in litres we will need to divide by 1000,
1 litres = 1000Cm^3
So:
V =63,000/1000
V= 63 litres

Don Simón repartió 60 canicas entre sus dos
hijos, de modo que el mayor recibió tres veces lo
que el menor. ¿Cuántas canicas recibió el hijo
mayor?

Answers

Un sistema de ecuaciones es un conjunto de ecuaciones que operan con el mismo conjunto de variables, de tal forma que buscamos solucionar ambas ecuaciones al mismo tiempo.

En este problema querremos encontrar un sistema de ecuaciones para poder encontrar la cantidad de canicas que recibe el hijo mayor.

Encontraremos que recibe 45 canicas

La información que se nos da es:

"Don simón repartió 60 canicas entre ambos hijos"

"El hijo mayor recibe 3 veces la que el menor"

Definamos las variables:

x = cantidad que recibe el hijo mayor

y = cantidad que recibe el hijo menor.

Como sabemos que la cantidad total de canicas es 60, entonces tenemos:

x + y = 60

Como tambien sabemos que el mayor recibe 3 veces lo que el menor, podemos escribir:

x = 3*y

Entonces tenemos 2 equaciones, las cuales podemos combinar en un sistema de ecuaciones.

x + y = 60

x = 3*y

Para resolver este sistema, el primer paso sería aislar una de las variables en una de las ecuaciones. Como queremos resolverlo para x, debemos aislar la otra variable.

Podemos hacerlo en la segunda ecuación:

x/3 = y

Ahora podemos reemplazar esto en la primer ecuación:

x + y = 60

x + x/3 = 60

(4/3)*x = 60

x = (3/4)*60 = 45

x = 45

Podemos concluir que el mayor recibe 45 canicas.

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Plz help me with these with steps

Answers

Answer: There are 100 blue marbles.

Step-by-step explanation:

252 x 2/7 = 72

72 is the number of the red marbles.

(252-72) x 4/9 = 80

80 is the number of the green marbles.

252-72-80 = 100

There are 100 blue marbles.

find the slop of the line passing
through A (-5,1) and B (3,-2)?

Answers

Answer:

-3/8

Step-by-step explanation:

(Y1 - Y2)/(X1 - X2) = SLOPE

(1 - -2)/(-5 - 3) = 3/-8

There is another bag of red and yellow footballs with a ratio of 4:3. If there are 20 red footballs in the bag, how many footballs are there in total?

Answers

Answer:

35

Step-by-step explanation:

take no. of red footballs be 4x and yellow footballs be 3x

4x=20,   x=5

=> 3(5)= 15

total no. of footballs= 20+15= 35

Help plsssssssssssssssssssssss

Answers

Answer:

Step-by-step explanation:

let Garrett orders x stickersfrom each company.

then

30+0.80x=14+1.20x

draw a number line and represent the following rational number 5 upon 4


plz help me in this question
class 7



i will mark brainliest​

Answers

Answer:

First we need to convert this fraction number to decimal then only we caan mark that on a number line

[tex]\frac{5}{4}[/tex] divide

You will get 1.25

Now mark 1.25 on number line

a square playground measures 2500 ft^2 what is the distance around the edge of the playground?​

Answers

Answer:

20000

Step-by-step explanation:

The histogram below shows the number of hours per month students in Mr. Carter's class watch television. How many students watch television between 1 and 10 hours per month?​

Answers

(A) The first column show that 3 students watched between 1-10 hours of television per month.


Mark bought 8 boxes a week later half of all his boxes were destroyed in a fire there are now only 20 boxes left with how many did he start?

Let it b represent how many boxes he started with

Equation or inequality:

Mark began with:

Answers

9514 1404 393

Answer:

equation: 1/2(s +8) = 20Mark began with 32 boxes

Step-by-step explanation:

Let s represent the number Mark started with. After buying 8 more, he then had s+8. After the fire, he had ...

  (1/2)(s +8) = 20

This equation can be solved by multiplying by 2, then subtracting 8.

  s +8 = 40

  s = 32

Mark began with 32 boxes.

Please help I will mark brai list if u are right

Answers

Answer:

Umm I'm only in middle school umm I think it's A bc there pointing in the same line

2/3 divided by 3/10

Thanks

Answers

Answer:

[tex] \frac{20}{9} [/tex]

Step-by-step explanation:

[tex] \frac{2}{3} \div \frac{3}{10} [/tex]

➡️ [tex] \frac{2}{3} \times \frac{10}{3} [/tex]

➡️ [tex] = \frac{20}{9} [/tex] ✅


When y=35 evaluate -(y+5) and -y-5 to show that -(y+5)=-y-5

Answers

Step-by-step explanation:

for y = 35 we get

-(y + 5) = -(35 + 5) = -(40) = -40

-y - 5 = -35 - 5 = -40

both deliver the same result.

A glucose molecule is the

smallest type of protein
monomer of starch and cellulose
largest of the carbohydrate polymers
fundamental unit of genetic material

Answers

A glucose molecule is the smallest type of protein monomer of starch and cellulose largest of the carbohydrate polymers fundamental unit of genetic material.

A glucose molecule is the monomer of starch and cellulose.

Step-by-step explanation:

Glucose is an organic molecule composed of carbon atoms, oxygen atoms, and hydrogen atoms.It has a molecular formula of [tex]C_6H_{12}O_6[/tex]It is a monosaccharide sugar, carbohydrateAn important source of an energy in living organisms.Glucose gives two different natural polymers named: starch and cellulose. This polymer is formed by linking small units of glucose molecules with each other. And this small unit which repeats in the structure of its polymer is known as a monomer.Glucose in the monomer in its natural polymer that was starch and cellulose.

So from this, we can conclude that A glucose molecule is the monomer of starch and cellulose.

Learn more about glucose here:

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simplify -(2a -2) -(a + b)+(a-6+b)​

Answers

Step-by-step explanation:

-2a-2-a-b+a-6+b

-2a-a+a-b+b-2-6

-2a+0-8

-2a-8

Answer:

-2a-8

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Which equation does not have the same solution as the others

×/3 =3
X + 9 = 12
11 x= 33
X - 2 = 1

Answers

Answer:

the first cuz in

x/3 = 3

x = 9

and in others x = 3

...............

Answer:

x/3=3

Step-by-step explanation:

because is undiferned because x can not be x/3=3

Which set of ordered pairs represents a function?

{(9,–7), (1, -3), (6, 7), (6, -6)}

{(-7,7), (5,3), (-7, -7),(1, -9)}

{(8,-6), (-9,2), (-9, -8), (-3,4)}

{(-5, -5),(-9,0),(-8,5), (-6,5)}

Answers

Answer:

{(-5, -5),(-9,0),(-8,5), (-6,5)}

Step-by-step explanation:

A function cannot have a domain that is assigned to multiple values (range).

The first set has 6 assigned to both 7 and -6.

The second set has -7 assigned to both 7 and -7.

The third set has -9 assigned to both 2 and -8.

10. If I is the midpoint of SU, find x.
8x + 11
12x – 1
S
U
8x+1=RX-1

Answers

Answer:

x = 3

Step-by-step explanation:

[tex]8x + 11 = 12x - 1 \\ 8x - 12x = - 1 - 11 \\ - 4x = - 12 \\ x = 3[/tex]

......
......
.....
...​

Answers

A) 2x+t
B) 5x+6
C) 7a+3
D)9-5a
E)10m-9
F) 15-7n
G)10a+6b
H) 9a-8b
I) 3p2+4q2
J) 5a2+2b2
K) 3x2+5xy
L) 3x2-4x+5
M) 3ab+bc-1
N) 4abc+2ab+5a
(Mark my the brainliest)

Answer:

x+3 and x+ 2

=3x(x) 2x

=6x

A trapezoid has one base measuring 12', and the other measuring 13'8". What is the area in square feet if the height of the trapezoid is 9'4"?

(Remember for trapezoids A= (b1 + b2)/2 x h

Answers

Answer:

Step-by-step explanation:

buzhou一=12212+13。8.12+13.8=25.8          25.8x9.4=?242.52242.522

The area of the trapezoid is given by A = 121.26 feet²

What is a trapezoid?

The Trapezoid is a 4 sided polygon. Two sides of the shape are parallel to each other and they are termed as the bases of the trapezoid. The non-parallel sides are known as the legs or lateral sides of a trapezoid.

There are three types of trapezoids , and those are given below:

a) Isosceles Trapezoid

b) Scalene Trapezoid

c) Right Trapezoid

The area of the Trapezoid is given by

Area of Trapezoid = ( ( a + b ) h ) / 2

where , a = shorter base of trapezium

b = longer base of trapezium

h = height of trapezium

Given data ,

Let the area of the trapezoid be represented as A

Now , the equation will be

Let the height of the trapezium be H = 9.4 feet

The shorter base of the trapezium a = 12 feet

The longer base of the trapezium b = 13.8 feet

Now , Area of Trapezoid = ( ( a + b ) h ) / 2

On simplifying the equation , we get

Area of Trapezium A = ( ( 13.8 + 12 ) 9.4 ) / 2

Area of Trapezium A = 121.26 feet²

Hence , the area of trapezium is 121.26 feet²

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1 121 12321 1234321.......56th​

Answers

Answer:

Bro it is too hard to find . Hope you understand me

in the number 58, the value of the digit 8 is ----
and the value of the digit 5 is __ ?​

Answers

Answer:

8 is one's. 5 is tens.

Step-by-step explanation:

the 5 is in the tens place, and the 8 is in the ones place.

Find the opposite of: - 4x2 - 4x + 2

Answers

Answer:

4x² + 4x - 2

Step-by-step explanation:

The opposite is the negative value

The opposite of - 4x² - 4x + 2 is

- (- 4x² - 4x + 2) ← distribute parenthesis by - 1

= 4x² + 4x - 2

Solve if x measure of AOC = 7x-2 measure of AOB = 2x+8 measure of BOC = 3x+14.

Answers

Answer:

x=3[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

im assuming this a triangle if so all angles add up to 180 so combine all equations and make it so it equals 180

7x-2+2x+8+3x+14=180

Combine Like Terms: 12x+20=180

12x+20-20=180-20

12x=160

12x/12=160/12

x=13[tex]\frac{1}{3}[/tex]

An x measure of AOC = 7x-2 measure of AOB = 2x+8 measure of BOC = 3x+14 value of x is 28.33.

A three angles, AOC, AOB, and BOC, and you're given their measures in terms of x. The problem is likely asking you to find the value of x. Since these angles are in a circle, they must add up to 360 degrees.

The sum of the measures of the angles around a point is 360 degrees:

Angle AOC + Angle AOB + Angle BOC = 360

Substitute the given expressions for the angle measures:

(7x - 2) + (2x + 8) + (3x + 14) = 360

Combine like terms:

12x + 20 = 360

Now, subtract 20 from both sides:

12x = 340

Finally, divide by 12:

x = 340 / 12

x = 28.33

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PLEASE HELP

-10+7/4p=-38

Show your work in details if you can, I have a hard time understanding this.

Answers

Answer: p=-16

hope this helps

Help please! What shape is it?

Answers

Answer:

kite

Step-by-step explanation:

a kite is a quadrilateral. two adjacent sides are congruent and the other two adjacent sides are congruent

I think It is a kite

II
Find the area of the right triangle.
Area =
I sa
square units
1 unit
Ya

Answers

Answer:

A = 6 units ^2

Step-by-step explanation:

The area of a triangle is found by

A = 1/2 bh where b is the base length and h is the height

A = 1/2 ( 2) * (6)

A = 6 units ^2

Answer:

6 square unit is correct answer

Is x^3x^3x^3 equivalent to x^3^3^3

Answers

Answer:

No they aren't equivalent.

Step-by-step explanation:

x^3x^3x^3=x^3^3^3

[tex](x)^{3x^{3x^3[/tex]=[tex]x^{3^{3^3[/tex]

[tex]x^{3x^{9x}[/tex]=[tex]x^{3^{9}[/tex]

[tex]x^{27x^{2} }[/tex]=[tex]x^{27}[/tex]

Apply log on both sides

27[tex]x^{2}[/tex]logx=27logx

27[tex]x^{2}[/tex]logx/27logx=1

[tex]x^{2}[/tex]=1

This is true if x=1 , -1.

The values are equivalent if x=1 and -1 , otherwise no they aren't equivalent.

A radio telescope has a parabolic surface, as shown below.

A parabola opening up with vertex at the origin is graphed on the coordinate plane. The height of the parabola from top to bottom is 9 meters and its width from left to right is 12 meters.

If the telescope is 9 m deep and 12 m wide, how far is the focus from the vertex?

Answers

OK, so the graph is a parabola, with points x=0,y=0; x=6,y=-9; and x=12,y=0

Because the roots of the equation are 0 and 12, we know the formula is therefore of the form

y = ax(x - 12), for some a

So put in x = 6

-9 = 6a(-6)

9 = 36a

a = 1/4

So the parabola has a curve y = x(x-12) / 4, which can also be written y = 0.25x² - 3x

The gradient of this is dy/dx = 0.5x - 3

The key property of a parabolic dish is that it focuses radio waves travelling parallel to the y axis to a single point. So we should arrive at the same focal point no matter what point we chose to look at. So we can pick any point we like - e.g. the point x = 4, y = -8

Gradient of the parabolic mirror at x = 4 is -1

So the gradient of the normal to the mirror at x = 4 is therefore 1.

Radio waves initially travelling vertically downwards are reflected about the normal - which has a gradient of 1, so they're reflected so that they are travelling horizontally. So they arrive parallel to the y axis, and leave parallel to the x axis.

So the focal point is at y = -8, i.e. 1 metre above the back of the dish.
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