Answer:
A. is any species that donates a proton.Explanation:
A Bronsted-Lowry acid is a chemical species that donates one or more hydrogen ions in a reaction.
In contrast, a Bronsted-Lowry base accepts hydrogen ions.
Iron ore is converted to iron metal in a reaction with carbon. If 1.07 moles of are used, what amount of is needed and what amounts of and , in moles, are produced
Answer:
information is missing
Explanation:
chemical equation is needed
Calculate the amount of heat required to melt 2108 g of water. The enthalpy of fusion of water is ΔHfus=6.010 kJ/mol.
since the unit for the heat of fusion is kJ/mol, you're going to have to convert the grams into moles in order to cancel out the unit. After that, you can solve like normal.
Specific heat capacity of a substance is the amount of heat required to raise the temperature by one degree Celsius of one gram of a substance. Therefore, the amount of heat required to melt 2108 g of water is 703.7kJ.
What is Enthalpy?Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances.
Mathematically,
q = n ×ΔH
where
q = amount of heat=?
ΔH = enthalpy=6.010 kJ/mol
n = no of moles
n = w / M.M
w = given mass
M.M = molar mass
moles of water=2108 g ÷18g/mol
=117.1 mol
substituting all the given values in the above equation, we get
q =6.010 kJ/mol ×117.1 mol
=703.7kJ
Therefore, the amount of heat required to melt 2108 g of water is 703.7kJ.
To know more about enthalpy, here:
brainly.com/question/24170335
#SPJ2
Doping Se with P would produce a(n) ________ semiconductor with ____________ conductivity compared to pure Se.
The orbit of a planet is an ellipse with the sunat one of the foci.. This is Kepler's........ second law third law first law
Answer:
its keplers first law
Explanation:
answer from gauth math
What are precautions to be taken when doing titrations? A-Make sure to always vigorously shake that flask after every drop if the end point is still unknown. It may be that the remaining volume of the titrant needed to reach the end point is just adhering on the wall. This is to ensure accuracy. B-The amounts of solid and liquid should be weighed and pipetted with high accurac This is because all the data that will be produced will mainly depend on this. C- If the end point is unknown, dropwise addition of the titrant is recommended. D- Always make sure that the indicator is added. E- All of the above
Answer:
E
Explanation:
This is because all steps from A-D are important to obtain an accurate result
D
Question 3
1 pts
In olden times, apothecaries used to dispense medicine using their own system of measurements
that are listed below. Use these conversions to determine how many milligrams would be in a
sample of 1.250 scruples.
1 apothecary pound = 12 ounces
1 ounce = 8 drams
3 scruples = 1 dram
1.2153 apothecary pound = 1 English pound
1 kg = 2.205 English pounds
Enter your answer to the correct number of significant digits. Do not include the units.
Changing 1.250 scruples to milligrams.
To convert from a unit to another, First write the conversion guide
then cross multiply in such a way that the unit both top and bottom
cancel out each other together with dividing or multiplying the values associated with them.
To get to the answer we have to wor it out step by step.
First step
3 scruples = 1 dram
1.250 scruples=
= [tex]\frac{1.250 scruples x 1 dram}{3scruples}[/tex] = 0.41667dram
2nd step
8 drams=1 ounce
0.41667drams =
[tex]\frac{0.41667drams x 1}{8 drams }[/tex] =0.05208 ounces
3rd step
1 apothecary pound = 12 ounces
?apothecary pound =0.05208 ounces
[tex]\frac{0.05208 ounces x 1apothecary pound }{12 ounces}[/tex] =0.00434 apothecary pound
4th step
1.2153 apothecary pound = 1 English pound
0.00434 apothecary pound =
[tex]\frac{0.00434 apothecary pound x 1 English pound}{1.2153 apothecary pound }[/tex]
==0.003571 English pound
5th step
1 kg = 2.205 English pounds
??kg =0.003571 English pound
[tex]\frac{0.003571 English pound x 1kg }{2.205 English pounds}[/tex]
=0.00161950kg
6th step
1kg =0.00161950kg
0.00161950kg=
[tex]\frac{0.00161950kg x 0.00161950kg}{1kg}[/tex]
=1,619.50mg
Therefore, 1.250 scruples=1,619.50mg
See related type of question here:
https://brainly.com/question/21946442
calculate the density of the object that has a mass of 5.0 g and occupies the volume of 10.0 cm3
How many centimeters are there in 5.44 meters?
Answer:
544 cm!
I hope this helped.
Answer:
The answer of your question is 544 cm
Explanation:
5.44 × 100
544 cm
The Scanning Electron Microscope, or SEM, uses beams of_______
residue from bullets or ink from a ransom note.
Electricity
Protons
Neutrons
Electrons
Answer:
Electrons.
Hope it helps.
Where did you put H an He? What are your reasoning for placement?
Answer:
On the placement of hydrogen and helium in the periodic system
H1=1
He2=2
The procedure was applied to a new sample of 9.00 milliliters of the liquid mixture to extract component C. Due to the loss of volume from the procedure, the extracted volume of component C was only 90.0% of the original volume of this component. What was the extracted volume of component C, in milliliters
Percentage volume of substance in a mixture can be obtained by the following equation:
[tex]Percentage volume = \frac{Volume of sub.}{Total Volume} * 100\\\\[/tex]
Considering the question given above, the following data were obtained:
Total volume of mixture = 9 mL
Percentage of C extracted = 90%
Volume of C extracted =?
[tex]Percentage of C = \frac{Volume of C }{Total Volume} \\\\90 percent = \frac{Volume of C}{9}[/tex]
Cross multiply
Volume of C = 90% × 9
Volume C = 0.9 × 9
Volume of C = 8.1 mLTherefore, the volume of C extracted is 8.1 mL
Learn more: https://brainly.com/question/13111079