4 mg string streched and spring constant 20cm what force constant​

Answer:

75%

Step-by-step explanation:

You turn the information into a fraction which is 15/20.

20x 5= 100, and everything you do in the bottom you have to do the top and 15 times 5 is 75.

Hope it helps

The algebraic expression [tex]x^{10/3}[/tex] is equivalent to the algebraic expression [tex]x^{3}\cdot \sqrt[3]{x}[/tex]. Thus, the right choice is option D.

In this question we must apply the following set of algebraic properties to simplify a given expression:

[tex]x^{m/n} = \sqrt[n]{x^{m}} = \left(\sqrt[n]{x}\right)^{m}[/tex]   (1)

[tex]x^{m+n} = x^{m}\cdot x^{n}[/tex]   (2)

[tex]x^{m\cdot n} = \left(x^{m}\right)^{n} = \left(x^{n}\right)^{m}[/tex]   (3)

Where:

And also by apply the definition of power.

If we know that the given expression is [tex]x^{10/3}[/tex], then the equivalent expression is:

[tex]x^{10/3} = \sqrt[3]{x^{10}} = \sqrt[3]{x^{9}\cdot x} = \sqrt[3]{x^{9}}\cdot \sqrt[3]{x} = x^{3}\cdot \sqrt[3]{x}[/tex]

The algebraic expression [tex]x^{10/3}[/tex] is equivalent to the algebraic expression [tex]x^{3}\cdot \sqrt[3]{x}[/tex]. Thus, the right choice is option D.

To learn more on roots, we kindly invite to check this verified question: https://brainly.com/question/1527773

Answer:

x = -3

y = -2

(-3, -2)

Step-by-step explanation:

x - 7y = 11

5x + 4y = -23

-----------------------

-5 (x - 7y = 11)

-5x + 35y = -55

--------------------------

-5x + 35y = -55

5x + 4y = -23

       39y = -78

     ÷39     ÷39

        y = -2

-----------------------------

x - 7y = 11

x -7(-2) = 11

x + 14 = 11

   -14    -14

x = -3

I hope this helps!

Answer:

option d

Step-by-step explanation:

(-3)²=9

(-3)²≠(-9)

Answer:

If you meant acute angle, an acute angle is an angle less than 90 degrees, normally greater than or equal to 15 degrees. Acute angles come in many forms.

__________________________________________________________

Ask in comments.

Answer:

an acute is a type of angle I am learning acute in a 12:15 class

Step-by-step explanation:

#1

#2

#3

Answer:

d). (2m-1)(5m+3)

e). (2x-5)(2x-5)

f). (6n-4)(n+5)

Step-by-step explanation:

Solving by factorisation...

d). 10²+m-3

=> 10m²+6m-5m-3

=> 2m(5m+3)-1(5m+3)

=> (2m-1)(5m+3)

e). 4x²-20x+25

=> 4x²-10x-10x+25

=> 2x(2x-5) -5(2x-5)

=> (2x-5)(2x-5)

f). 6n²-20+26n

=> 6n²+26n-20

=> 6n²+30n-4n-20

=> 6n(n+5)-4(n+5)

=> (6n-4)(n+5)

Answer:

100

Step-by-step explanation:

If x is 6 and y is 2 the new equation would look like this: 5(3x6 + 2). 3 times 6 is 18 and add 2 is 20. Therefore you would get 20 times 5. 20x5 is 100

Answer:

9pi

Step-by-step explanation: The formula for circumference of a circle is 2*pi*r or the diameter times pi. Since you have the diameter, you can use diameter times pi and simply get 9pi

The maximum profit that the considered company can get is 142,400 bucks. That profit is earned when input x  (the number of items produced) is 380

To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.

Putting those values of x in the second rate of function, if results in negative output, then at that point, there is maxima. If the output is positive then its minima and if its 0, then we will have to find the third derivative (if it exists) and so on.

The missing part of question is:

" [tex]C(x)=2000+70x[/tex], [tex]R(x)=830x-x^2[/tex]

A. Determine the maximum profit of the company.

B. Determine the number of items that must be produced and sold to obtain the maximum profit"

The profit is the difference between the revenue and the cost, so we get:

[tex]P(x) = R(x) - C(x) = 760x - x^2 - 2000[/tex]

Finding its first and second rate with respect to x:

[tex]P'(x) = 760 -2x\\P''(x) = -2[/tex]

Equating first rate to 0 to get the critical values:

[tex]P'(x) = 0 \implies 760 = 2x \implies x = 380[/tex]

The second rate is < 0 for any x, x = 380 is minima, and x = 380 being only critical value, it is global maximum.

At x = 380, the profit evaluates to:

[tex]P(x) = 760x - x^2 - 2000\\P(380) = 760(380) - (380)^2 - 2000 = (380)^2 - 2000\\P(380) = 142400[/tex]

Thus, the maximum profit that the considered company can get is 142,400 bucks. That profit is earned when input x  (the number of items produced) is 380

Learn more about maxima and minima of a function here:

https://brainly.com/question/13333267

Answer:

it will be an exponet

Step-by-step explanation:

2 over 8

Answer:

[tex]\displaystyle \cos x \left(\csc x + \tan x\right) = \cot x + \sin x[/tex]

Step-by-step explanation:

We want to simplify:

[tex]\displaystyle \cos x \left(\csc x + \tan x\right)[/tex]

Recall that csc x = 1 / sin x and tan x = sin x / cos x. Substitute:

[tex]\displaystyle = \cos x \left(\frac{1}{\sin x} + \frac{\sin x }{\cos x}\right)[/tex]

Distribute:
[tex]\displaystyle = \frac{\cos x}{\sin x} + \frac{\cos x \sin x}{\cos x} \\ \\ \\ = \frac{\cos x}{\sin x} + \sin x[/tex]

Recall that cot x = cos x / sin x. Hence:

[tex]\displaystyle = \cot x + \sin x[/tex]

In conclusion:

[tex]\displaystyle \cos x \left(\csc x + \tan x\right) = \cot x + \sin x[/tex]

Answer:

| Drink (x ml) |   200 |       100 |    500|   1000|  

| Sugar (y g)  | 20      |  10       |    50   |  100   |

Step-by-step explanation:

Formula :  y=k/x

Solve:

Before we find the answer chart =

| Drink (x ml) |   200 |       100 |    500|   1000|  

| Sugar (y g)  | 20     |      ?        |    ?     |      ?      |

20 = ? / 200

? = 10

Thus,

100/10 = 10

500/10 = 50

1000/10 = 100

So the chart now is:

| Drink (x ml) |   200 |       100 |    500|   1000|  

| Sugar (y g)  | 20      |  10       |    50   |  100   |

~lenvy~

Answer:

Option C, There are about 3.75 times as many people as pet dogs

Step-by-step explanation:

Step 1:  Determine the ratio

[tex](Amount\ of\ People) / (Amount\ of\ Dogs)[/tex]

[tex](3 * 10^8) / (8 * 10^7)[/tex]

[tex]3.75[/tex]

Answer: Option C, There are about 3.75 times as many people as pet dogs

Answer:

Hope that helps

Step-by-step explanation:

Brainliest would be much appreciated

Answer:

[tex]\fbox{length= 10 \: in}

[/tex]

Step-by-step explanation:

Given:

Length to Width Ratio = 2:3

Area of Rectangle= 150 in²

To find:

Length of rectangle=?

Solution:

Assume the length of rectangle is 2x

and the width of rectangle is 3x

Now,

we know that,

[tex]\sf\: Area \: of \: Rectangle = Length \times Width \\ \sf \: 150 = 2x \: \times 3x \\ \sf \: 150 =6 {x}^{2} \\ \sf \: {x}^{2} = \frac{150}{6} \\ \sf {x}^{2} = \cancel\frac{150}{6} \\\sf {x}^{2} = 25 \\\sf \sqrt{ {x}^{2} } = \sqrt{ {25} } \\ \sf \sqrt{ {x}^{2} } = \sqrt{ {5}^{2} } \\ \sf \: \fbox{x = 5 \: in}[/tex]

Substituting the value of x in assumption,

[tex] \sf \: length= 2x \\ \sf \: length= 2 \times 5 \\ \sf \: \fbox{length= 10 \: in}

[/tex]

Thanks for joining brainly community!

Answer:

Step-by-step explanation:

Given relation

a)

Find its zero's

b)

The vertex of qudratic function is determined at x = - b/(2a)

Applied to this relation, the x- coordinate of vertex is

Find its y- coordinate

The vertex is (- 3, - 75)

Zeros:-

#Vertex

Multiply 3 which we deduced

Vertex (-3,-75)

Using proportions, it is found that Gene's speed was of 25 miles per hour, as he was 30 miles faster over a period of 6 hours.

A proportion is a fraction of a total amount.

At 8 a.m. Anne left Austin and headed south at 20 mph, hence when Gene left at 10 a.m., she was 40 mph ahead.

At 4 p.m., that is, 6 hours after Gene left, the distance was of 10 miles, that is, Gene was 30 miles faster in 6 hours, so the difference in the speeds is given by:

d = 30/6 = 5 mph.

Since Anne's speed is of 20 mph, Gene's is given by:

v = 20 + 5 = 25 mph.

More can be learned about proportions at https://brainly.com/question/24372153

#SPJ1

Answer:

0 ones + 18 tenths + 3 hundredths

Step-by-step explanation:

Answer:

yes it's O ones + 18 tenths + 3 hundredths

Step-by-step explanation:

I took the test

If reflected over y = x

then use

[tex]\left[\begin{array}{ccc}0&1\\1&0\end{array}\right][/tex]

=====================

[tex]\left[\begin{array}{ccc}0&1\\1&0\end{array}\right] \left[\begin{array}{ccc}3&6&3\\-3&3&3\end{array}\right][/tex]

similar as (x, y) → (y, x)

multiply the matrixes to get the final answer

[tex]\left[\begin{array}{ccc}(3*0+1*-3)&(6*0+1*3)&(3*0+1*3)\\(3*1+(-3*0)&(1*6+0*3)&(1*3+0*3)\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}-3&3&3\\3&6&3\end{array}\right][/tex]

Answer:

[3,-3,-3] [-3,-6,3]

Step-by-step explanation:

jus got it right

Answer:

Explanation:

So you want to start by finding the area of the big square.

We know the width of the big square is 60cm. The length of the big square is

19

+

24

+

13

=

56

Big square

A

r

e

a

=

L

⋅

W

=

56

⋅

60

=

3360

Now let’s find the little square inside the bigger square. We see from the picture that the width is 34 and the length is 24cm. Using the same formula, we can find the area of the little square.

Little square

A

r

e

a

=

L

⋅

W

=

24

⋅

34

=

816

The area enclosed in the area of the big square minus the area of the little square.

3360

−

816

=

2544

So the area enclosed is

2544

c

m

2

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

4*5-(2-2) =

(Make sure to use BODMAS to solve correctley in order)

4*5=

20

Answer:

C: [tex]-7ab \sqrt[3]{3ab^{2} }[/tex]

Step-by-step explanation:

Simplify or expand:

[tex]2ab\sqrt[3]{192ab^{2} } - 5\sqrt[3]{81a^{4} b^{5} }[/tex]

Transform the expression:

[tex]2ab\sqrt[3]{4^{3}*3ab^{2} }[/tex] - [tex]5\sqrt[3]{3^{3}*3a*ab^{3} b^{2} }[/tex]

Re-write

Multiply

Combine like terms.

Answer:

53.3 somewhere like that

Step-by-step explanation:

Answer:

Извини, чувак, но я написал это на русском, чтобы тратить твое время.

Step-by-step explanation:

Извини, чувак, но я написал это на русском, чтобы тратить твое время.

Answer:

234

Step-by-step explanation: