3(4x+1)=15? X=
What is the solution?

Answer:

100

Step-by-step explanation:

anything lower then 4 stays anythiing 5 or higher is rounded

so this also works with 40 50 400 500 4000 5000, you gte the point

oodluck on your test or homework! :)

I'll get 32 jelly beans

Amount of jelly beans shared = 56

My fraction = 4/(4+3) = 4/7

My sister's fraction = 3/(4+3) = 3/7

The number of jelly beans that I'll get will then be:

= My fraction × Number of jelly beans

= 4/7 × 56

= 4 × 8

= 32

Therefore, I'll get 32 jelly beans

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Answer:

[tex]take \: the \: number = x \\ thenx \times 6 = 2 \times 19 \\ \\ 6x = 38 \\ x = \frac{38}{6} \\ x = 6.33 \\ thank \: you[/tex]

Answer:

» B. 3- (+22) and C. 3 + (-22)

» A. 3- (-22) and E. 22 + 3

» D. 22 - 3 and H. 22 +(-3)

Step-by-step explanation:

[tex].[/tex]

Answer:

3 - (+22)

3 + (-22)

-22 + 3

Step-by-step explanation:

Answer:

5^6

Step-by-step explanation:

This is because the exponent is how many numbers are in the multiplication equation, in this case, five. Because there are six five's being multiplied together, our exponent is six.

Answer:

tero bau ko tauko got it sjdhhrurjrbr

Answer:

LHS=6x/12x=6/12=1/2

RHS=1/2

LHS=RHS

9514 1404 393

Answer:

  a) see attached

  b) Each successive figure has one more tile at the end of each leg.

  c) 201, the number of tiles is 2n+1 for figure n.

Step-by-step explanation:

a) The attachment shows the next two figures

__

b) The pattern adds one more tile at the end of each leg than the previous figure had. This rule matches the figures shown.

__

c) The rule found in part B means that Figure N will have 2N+1 tiles, the N tiles in each leg plus the one where the legs meet.

Figure 100 will have 2(100) +1 = 201 tiles

Answer:

i dont know that well but i do know 1 meter is roughly 2ft, so id say about 25.5 inches

0.01 inch is the  length of a meter stick.

To find the length of a meter stick in inches, we can use the conversion factor:

1 meter = 100 centimeters

1 inch = 2.54 centimeters

We can set up the proportion:

1 meter / 100 centimeters = x inches / 1 inch

Cross-multiplying:

1 meter × 1 inch = 100 centimeters × x inches

x = (1 meter × 1 inch) / (100 centimeters)

x = 1 inch / 100

x = 0.01 inch

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Answer:

7/60 acres

Step-by-step explanation:

60 pounds of seed = 7 acres

We want to find acres per pound of seed, so we want to make one side of the equation equal to 1 pound of seed. To do this, we can divide both sides by 60, as anything divided by itself equals 1. We thus have

60/60 pounds of seed = 7/60 acres

1 pound of seed = 7/60 acres

Step-by-step explanation:

No of Student in Debre Berhan University - 80 students

No of students good in mathematics and English -15

no of student good in mathematics -45+15+13

therefore no of student good in math is 75 .

pls mark me branilest

Answer:

703.7168 ft²

Step-by-step explanation:

Use the sector area formula, a = 1/2r²θ

If the diameter is 32 feet, then the radius is 16 feet.

Plug in the radius and angle measure into the formula, and solve:

a = 1/2r²θ

a = 1/2(16)²(7[tex]\pi[/tex]/4)

a = 703.7168

So, the area of the sector is 703.7168 ft²

Answer:

R = 6S/T

Step-by-step explanation:

R ∝ S/ T

》R = kS/ T

》k = RT/ S

If R = 8 when S = 4 and T = 3

then, k = (8 × 3)/ 4

k = 6

∴ R = (6 × S)/ T

Answer:

-5,-4,-3,-2,-1,0,1,2,3,4,5

-5 देखि+5सम्म 11 पुर्ण सङ्ख्याहरु छन्

mark me as brainliest

Answer:

640 dm

Step-by-step explanation:

200+40+400=640dm

9514 1404 393

Answer:

  76

Step-by-step explanation:

For some common difference d, the terms of the progression are ...

  k = 3 +d

  w = k +d = 3 +2d

  18 = w +d = 3 +3d

Solving for d, we get ...

  15 = 3d . . . . subtract 3

  5 = d . . . . . . divide by 3

Now, we can find ...

  3k +4w = 3(3 +d) +4(3 +2d) = 9 +3d +12 +8d = 21 +11d

  3k +4w = 21 +11(5) . . . . substitute for d

  3k +4w = 76

Answer:

1/4

Step-by-step explanation:

Answer:

38.75

Step-by-step explanation:

perimeter = 2(15.6+3.8) =38.8

lower bound = the smallest value that would round up to the estimated value =38.75

Answer:  40 lb of Type A

Step-by-step explanation:3 pounds of Type B and 1 pound of Type A will give 4 pounds of mix at a cost of ...  3($4.65) +($5.95) = $19.90Then $796 is the cost equivalent of 796/19.90 = 40 times that 4-lb mix. Since each instance of that 4-lb mix has 1 lb of Type A, $796 worth of blend has 40 lb of Type A coffee._____Additional commentIf you'd like to do this using a variable, you can let 'a' represent the amount of Type A coffee used. Then (3a) is the amount of Type B, and the total cost is ...  5.95a +4.65(3a) = 796  19.90a = 796 . . . . . . . . simplify  a = 796/19.90 = 40 . . . as above___There will be 120 lb of Type B coffee in that amount of blend.

The amount of Type A coffee that were used is 40 pounds.

Word problems in Algebra can be solved by correctly identifying the parameters given and the one(s) meant to be solved with the appropriate use of arithmetic operations.

From the given information;

For this month, the equation can be expressed as:

Thus;

Therefore, we can conclude that the amount of pounds of type A coffee that were used is 40 pounds.

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Step-by-step explanation:

1. 3cm, 5cm, 7cm

2. 7cm, 7cm, 12cm

Answer:

x=8

Step-by-step explanation:

4 ^(1/2x) = 256

Rewriting 256 as a power of 4

4 ^(1/2x) = 4^4

Since the bases are the same, the exponents are the same

1/2x = 4

Multiply each side by 2

1/2x *2 = 4*2

x=8

Answer: (10,5) and (0,5)

Step-by-step explanation:

Answer:

Step-by-step explanation:

Can we get the Answer's to see. Thanks.

Answer:

perfect square

Step-by-step explanation:

A perfect square is a number multiplied by itself:

16 = 4^2 = 4 * 4

Johannesburg's sister is 54cm tall

Explanation:

3/5 = 0.6

0.6 * 90 = 54

54 is 3/5 of 90, therefore Johannesburg's sister is 54cm tall

Answer:

[tex]29[/tex]

Step-by-step explanation:

Let x be the original price.

( 1 - 20% ) x = 23.2

[tex] 0.8x = 23.2[/tex]

[tex] \frac{0.8x}{0.8} = \frac{23.2}{0.8} [/tex]

[tex] x = 29[/tex]

Given

[tex]\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k[/tex]

the curl of [tex]\vec v[/tex] is

[tex]\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k[/tex]

[tex]\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k[/tex]

[tex]\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k[/tex]