2. Based on the following balanced equation:
2 NH3 + 202 N2O + 3 H2O
a. How many moles of O2 are required to react completely with 3.00 moles of NH3?
1.00 1.50 2.00 2.50 3.00 3.50 4.00 4.50 5.00
b. How many moles of H20 are produced after complete reaction of 3.00 moles of NH3?
1.00
1.50 2.00 2.50 3.00
3.50 4.00 4.50 5.00
c. How many moles of N O are produced after complete reaction of 3.00 moles of NH3?
1.00 1.50 2.00 2.50 3.00
3.50
4.00 4.50 500

Answer:

16

Explanation:

1) in the given equation CH₄+2O₂⇒ 2H₂O+CO₂;

M(CH₄)=12+4=16 (g/mol); M(O₂)=32 (g/mol);

2) if m(O₂)=125 gr., then ν(O₂)=m(O₂)/M(O₂)=125/32≈3.90625 (moles);

3) if in the given equation 'ν' of O₂ is 2, then the 'ν' of CH₄ is 1;

4) m(CH₄)=ν(CH₄)*M(CH₄)=1*16=16 (gr.).

The property altered during a chemical change that is not altered during a physical change is composition of the matter.

A physical change is one in which no new substance is formed and it is easily reversible.

A chemical change is one that is not easily reversible and no new substance is formed. It may be accompanied by absorption or evolution of heat.

The composition of a substance changes during a chemical change  because bonds between atoms break and new bonds are formed. This does not occur during a physical change.

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Answer:

A dehydrogenase is an enzyme .

Explanation:

Hope it helps

Mark me as Brainliest plz.

:DD

Answer:

Step 1

1 of 2

V = m / D; V (nugget of gold) = 50 g / 5.0 g / cm 3 = 10 cm3; V (nugget of iron pyrite) = 50 g / 19 g / cm3 = 2.63 cm 3

Result

2 of 2

Due to these results you can conclude that nugget of gold which volume is 10 cm3 is bigger than volume of nugget of iron pyrite which is 2.63 cm3.

Explanation:

Answer:

(b)The air trapped between the layers of newspaper is a bad conductor of heat.Thus the layers of newspaper helped the beggar to keep himself warm

Hey there!

I believe your answer would be "Air trapped between the layers of newspaper is a bad conductor of heat."

Hope this helps!

Have a great day!

You are stowing items and come across an aerosol bottle of hairspray. W should you do? Please choose all that apply. Stow the hairspray Raise an Andon Remove it and secure it with bubble wrap Place a Flammable sticker on the bottle Submit

Answer:

Vanadium (V) is the best conductor of thermal energy in this list

Answer:

[tex]\boxed {\boxed {\sf37,467.72 \ Joules }}[/tex]

Explanation:

We are asked to find how much heat a sample of water absorbed. Since we are given the mass, temperature, and specific heat, we will use the following formula.

[tex]q=mc \Delta T[/tex]

The mass (m) of the sample is 112.5 grams. The specific heat capacity of water (c) is 4.184 Joules per gram degree Celsius. The difference in temperature (ΔT) is found by subtracting the initial temperature from the final temperature.

The water was heated from 12.5 degrees Celsius to 92.1 degrees Celsius.

Now we know three variables and can substitute them into the formula,

[tex]q= (112.5 \ g )(4.184 \ J/g \textdegree C)(79.6 \textdegree C)[/tex]

Multiply the first 2 numbers. Note the units of grams cancel.

[tex]q= (112.5 \ g *4.184 \ J/g \textdegree C)(79.6 \textdegree C)[/tex]

[tex]q= (112.5 *4.184 \ J/ \textdegree C)(79.6 \textdegree C)[/tex]

[tex]q= (470.7 \ J/ \textdegree C)(79.6 \textdegree C)[/tex]

Multiply again. This time the units of degrees Celsius cancel.

[tex]q= (470.7 \ J/ \textdegree C *79.6 \textdegree C)[/tex]

[tex]q= (470.7 \ J *79.6 )[/tex]

[tex]q= 37467.72 \ J[/tex]

37, 467.72 Joules of heat are absorbed by the sample fo water.

Answer:

its d

. . . . . . . .. . . . . . . . .. .

Answer:

b

Explanation:

watch u know bout rolling down in the deep...

Answer:

Density other dude is incorrect

Explanation:

Density is an intensive, rather than an extensive property of matter.

WHAT ARE INTENSIVE AND EXTENSIVE PROPERTIES?

Therefore, density is an intensive, rather than an extensive property of matter.

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Answer:

The vast majority of the volume in an atom consists of the electron orbitals with electrons that have too little mass to deflect the alpha particles.  So most pass right through the foil.  Only the ones hitting the nucleus are deflected.

Explanation:

The whole reason Rutherford and his students conducted this experiment was to test the then current hypothesis that an atom consists of a homogeneous blend of atomic particles, known as the "plum pudding" model.  If so, there should be no, or minimal, deflection of particles.  That's not what they found.  Since particles were found to be deflected, the group concluded that atoms must contain a large object, which became known as the nucleus.

Answer:B

Explanation:

Answer:

B. a graduated cylinder

The element is Magnesium

it has electronic configuration

[tex]\\ \sf\longmapsto 2,8,2[/tex]

or

[tex]\\ \sf\longmapsto 1s^22s^22p^63s^2[/tex]

In valence cell it has 2 electrons and therefore its valency is 2

Answer:

Science is related only to sense-experience, and reason based on the former. It is an accumulation of systematic and verifiable knowledge. The scientific method is one and the same in all branches of knowledge. The unity of science, according to him, consists in its method, not in its material alone.

Explanation:

Answer:

Explanation:

The equation is not correctly written, so let's start with that.

4Al + 3O2 ====> 2Al2O3?

Totally correct, including the balance numbers, would be

4moles aluminum + 3 moles Oxygen ===> 2 moles of Aluminum Oxide

Anything else is incomplete.

Answer:

aluminum reacts with oxygen to produce aluminum oxide.

I hope this helps

Answer:

HELL NO!

THAT'S MY CHILDHOOD GAME!

I LOVE THAT GAME!

IT SHOULD NOT BE DEAD!

IT SHOULD LIVE ON FOREVER!

#GemoteryDashShouldLiveOnForever!

[tex]AnimeVines[/tex]

Answer:

37.5 mL of HCl will be required for complete neutralization with magnesium hydroxide

Explanation:

[tex]{ \bf{2HCl _{(aq)} + Mg(OH)_{2(s)}→ MgCl_{2(s)} + 2H _{2} O_{(l)}}}[/tex]

we've to first get moles of magnesium hydroxide in 50.0 ml :

[tex]{ \sf{1 \: l \: of \: hydroxide \: contains \: 0.12 \: moles}} \\ { \sf{0.05 \: l \: of \: hydroxide \: contain \: (0.05 \times 0.12) \: moles}} \\ = { \underline{0.006 \: moles}}[/tex]

for complete neutralization:

[tex]{ \sf{1 \: moles \: of \: hydroxide\: react \: with \: 2 \: moles \: of \: acid}} \\ { \sf{0.006 \: moles \: react \: with \: \{0.006 \times 2 \}} \: moles} \\ = { \underline{0.012 \: moles \: of \: acid}}[/tex]

compare with acid molarity:

[tex]{ \sf{0.32 \: moles \: of \: acid \: occupy \: 1 \: litre}} \\ { \sf{0.012 \: moles \: of \: acid \: occupy \: ( \frac{0.012}{0.32}) \: litres }} \\ { \underline{ = 0.0375 \: litre \: \: = \: \: 37.5 \: ml}}[/tex]

Answer:

[tex]2.5\; \rm g[/tex] of [tex]\rm CaCO_{3}[/tex] would contain:

Explanation:

Look up the Avogadro constant: [tex]N_{\rm A} \approx 6.022 \times 10^{23}\; \rm mol^{-1}[/tex].

For example, "[tex]1\; \rm mol[/tex] of carbon atoms" would contain [tex]N_{\rm A}[/tex] carbon atoms (approximately [tex]6.022\times 10^{23}[/tex]) by definition.

Look up the relative atomic mass of carbon, calcium, and oxygen on a modern periodic table:

In other words, the mass of [tex]1\; \rm mol[/tex] of calcium atoms would be [tex]40.078\; \rm g[/tex]. The mass of [tex]1\; \rm mol\![/tex] of carbon atoms would be [tex]12.011\; \rm g[/tex], and the mass of [tex]1\; \rm mol \!\![/tex] of oxygen atoms would be [tex]15.999\; \rm g[/tex].

As the formula [tex]\rm CaCO_{3}[/tex] suggests, every formula unit of this ionic compound includes one calcium atom, one carbon atom, and three oxygen atoms. The formula mass of [tex]\rm CaCO_{3}\![/tex] would give the mass of every mole of [tex]\rm CaCO_{3}\!\![/tex] formula units.

Calculate the formula mass of [tex]\rm CaCO_{3}[/tex] from the relative atomic mass data:

[tex]\begin{aligned} & M({\rm CaCO_{3}}) \\ =\; & 40.078\; \rm g \cdot mol^{-1} \\ & + 12.011\; \rm g \cdot mol^{-1} \\ & + 3 \times (15.999\; \rm g \cdot mol^{-1}) \\ =\; & 100.086\; \rm g \cdot mol^{-1}\end{aligned}[/tex].

Calculate the number of [tex]\rm CaCO_{3}[/tex] formula units in that [tex]2.5\; \rm g[/tex] of this compound:

[tex]\begin{aligned}& n({\rm CaCO_{3}}) \\ =\; & \frac{m({\rm CaCO_{3}})}{M({\rm CaCO_{3}})} \\ =\; & \frac{2.5\; \rm g}{100.086\; \rm g \cdot mol^{-1}} \\ \approx\; & 0.025\; \rm mol\end{aligned}[/tex].

In other words, [tex]2.5\; \rm g[/tex] of [tex]\rm CaCO_{3}[/tex] would contain approximately [tex]0.025\; \rm mol[/tex] [tex]\rm CaCO_{3}\![/tex] formula units.

Again, there are one calcium atom, one carbon atom, and one oxygen atom in every [tex]\rm CaCO_{3}[/tex] formula unit. That approximately [tex]0.025\; \rm mol[/tex] [tex]\rm CaCO_{3}\![/tex] formula units would thus contain:

Make use of the Avogadro constant to convert the numbers.

For example, the number of calcium atoms in that approximately [tex]0.025\; \rm mol[/tex] of calcium atoms would be:

[tex]\begin{aligned} & N({\text{calcium}) \\ = \; & n({\text{calcium}) \cdot N_{\rm A} \\ \approx \; & 0.025\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 1.5 \times 10^{22} \end{aligned}[/tex].

Likewise, the number of carbon atoms in that approximately [tex]0.025\; \rm mol[/tex] of carbon atoms would be:

[tex]\begin{aligned} & N({\text{carbon}) \\ = \; & n({\text{carbon}) \cdot N_{\rm A} \\ \approx \; & 0.025\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 1.5 \times 10^{22} \end{aligned}[/tex].

The number of oxygen atoms in that approximately [tex]0.075\; \rm mol[/tex] of oxygen atoms would be:

[tex]\begin{aligned} & N({\text{oxygen}) \\ = \; & n({\text{oxygen}) \cdot N_{\rm A} \\ \approx \; & 0.075\; \rm mol \times 6.022\times 10^{23} \cdot mol^{-1} \\ \approx \; & 4.5 \times 10^{22} \end{aligned}[/tex].

Convert temperatures to Kelvin

[tex]\\ \sf\longmapsto 50+273=323K[/tex]

[tex]\\ \sf\longmapsto 30+273=303K[/tex]

Using Charles law

[tex]\\ \sf\longmapsto \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

[tex]\\ \sf\longmapsto \dfrac{15}{323}=\dfrac{V_2}{303}[/tex]

[tex]\\ \sf\longmapsto V_2=\dfrac{15(303)}{323}[/tex]

[tex]\\ \sf\longmapsto V_2=\dfrac{4545}{323}[/tex]

[tex]\\ \sf\longmapsto V_2=14.07L[/tex]

Answer:

[tex]at \: low \: pressure \: high \: temparature \\ thank \: you[/tex]

Answer:

John Dalton based his partial pressures theory on the idea that only like atoms repel one another, Whereas unlike atoms appear to react indifferently. This notion was erroneous, but it helped to explain why each gas in a mixture behaved independently, serving the purpose of showing that atoms of all kinds are not alike.

Ionic substances are formed by exchange of valencies between the ions that make up the substance.

The ion [tex]Al^3+[/tex] has a valency of +3. It exchanges this valency with other ions as it forms ionic substances.

In the case of OH- which has a valency of 1, the compound Al(OH)3 is formed.

In the case of [tex]S^2-[/tex] which has a valency of 2, the compound Al2S3 is formed.

In the case of [tex]PO4^3-[/tex] which has a valency of 3, the compound AlPO4 is formed.

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Answer:

MECHANISM:

1) The lone pair on oxygen attacks the H-Br molecule forming a hydronium ion.

2) Formation of carbocation.

3) Attack of Nucleophile Br  −  .

Explanation:

Answer:

DISPLACEMENT REACTION

COMBINATION REACTION

DOUBLE DISPLACEMENT REACTION

DECOMPOSITION REACTION