1. What is the volume of a cube with volume 27/64 cubic units

We can use the formula for compound interest to calculate the amount of money we will have at the end of 3 years:

A = P(1 + r/n)^(nt)

Where:

A = the amount of money we will have at the end of 3 years

P = the principal (the initial amount we start with)

r = the interest rate (as a decimal)

n = the number of times the interest is compounded per year

t = the number of years

Plugging in the given values, we get:

A = 5000(1 + 0.045/12)^(12×3)

A = 5000(1.00375)^36

A ≈ $5,622.16

Therefore, we will have approximately $5,622.16 at the end of 3 years.

[tex] \:\:\:\:\: \:\:\:\:\:\:\star\longrightarrow \sf y = x^{x}{}^{²}\\[/tex]

Taking the logarithm on both sides -

[tex] \:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf log y = log x^{x}{}^{²}\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf log y = x^2 log x\\[/tex]

[tex]\:\:\: \boxed{\sf\pink{\:\:\: loga^b = blog a }}\\[/tex]

Differentiating with respect to x-

[tex] \:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf \dfrac{d}{dx} logy = \dfrac{d}{dx} x^2 log x \\[/tex]

[tex] \:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf \dfrac{1}{y} \times \dfrac{dy}{dx} = x^2 \dfrac{d}{dx} log x + logx \dfrac{d}{dx} x^2\\[/tex]

[tex] \:\:\:\:\boxed{\sf\pink{\dfrac{d}{dx} logx = \dfrac{1}{x}}} \\[/tex]

[tex] \:\:\:\:\boxed{\sf\pink{\sf\dfrac{d}{dx}\bigg[f(x)\:g(x)\bigg] = f(x) \dfrac{d}{dx} g(x) + g(x) \dfrac{d}{dx} f(x)}}\\[/tex]

[tex] \:\:\:\:\: \:\:\:\:\:\:\longrightarrow \sf \dfrac{d}{dx} = y \bigg[ x^2 \times \dfrac{1}{x} + logx \times 2x \bigg]\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf \dfrac{dy}{dx} = y \bigg[ \cancel{x}\: x \times \dfrac{1}{\cancel{x}} + 2x\:logx \bigg]\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf \underline{\dfrac{dy}{dx} = y \bigg[ x + 2x\:logx \bigg]}\\[/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\:\longrightarrow \sf \underline{\dfrac{dy}{dx} = \boxed{\sf x^{x}{}^{²}\bigg[ x + 2x\:logx \bigg]}}\\[/tex]

Answer:

[tex]\frac{24}{5}[/tex]

Step-by-step explanation:

We Know

The test has 6 questions.

Each question has 5 answers.

What would be the probability of getting at least one question wrong?

Each question can only have one correct answer, so the probability of getting a wrong answer for each question is [tex]\frac{4}{5}[/tex]

There are 6 questions on the test, so we take

[tex]\frac{4}{5}[/tex] x 6 = [tex]\frac{24}{5}[/tex]

So, the probability of getting at least one question wrong is [tex]\frac{24}{5}[/tex]

If the measure of m∠A = 61°, the angle measure m∠B = 29°.

What is an angle?

Since ΔABC is a right-angled triangle with C as the right angle, we can use the trigonometric ratios to find the missing side lengths and angles.

Given that A = 61°, we know that m∠B = 180° - 90° - 61° = 29° (by the angle sum property of a triangle).

Now, we can use the trigonometric ratios to find the side lengths. Let's start with side AC = x.

From the definition of the sine ratio, we have:

sin(A) = opposite/hypotenuse

sin(61°) = z/x

Therefore, we have:

x = z/sin(61°)

Similarly, from the definition of the cosine ratio, we have:

cos(A) = adjacent/hypotenuse

cos(61°) = y/x

Therefore, we have:

x = y/cos(61°)

Since both expressions equal x, we can set them equal to each other and solve for z:

z/sin(61°) = y/cos(61°)

z = y*tan(61°)

Finally, we can use the Pythagorean theorem to find the length of side BC:

y² = x² - z²

y² = (y/cos(61°))² - (y*tan(61°))²

Simplifying, we get:

y = x*cos(61°)

So, the lengths of the sides are:

AC = x = z/sin(61°)

BC = y = x*cos(61°)

And the missing angle is:

B = 29°

What is trigonometric ratio?

In mathematics, a trigonometric ratio is a ratio of the lengths of two sides in a right-angled triangle. The three primary trigonometric ratios are:

Sine (sin) = Opposite / Hypotenuse

Cosine (cos) = Adjacent / Hypotenuse

Tangent (tan) = Opposite / Adjacent

In these ratios, the hypotenuse is the longest side of the triangle, and it is always opposite to the right angle. The opposite side is the side opposite to the angle of interest, and the adjacent side is the side that is adjacent to the angle of interest (but not the hypotenuse).

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Complete question is: If the measure of m∠A = 61°, the angle measure m∠B = 29°.

There will be 16 small circular bubbles.

A circle is a shape formed by all points in a plane that are at a particular distance from the centre. It is the curve sketched out by a point moving in a plane so that its distance from a given point remains constant. The radius is the distance between any two points on a circle and the centre.

The area of a circle is given by the formula A = πr², where A is the area and r is the radius.

The area of the large bubble is A = π(8cm)² = 64π cm².

The area of a small bubble is A = π(2cm)² = 4π cm².

Let's assume that the number of small bubbles is n. Then, the total area of the small bubbles is n times the area of a single small bubble:

n(4π) = 4nπ cm²

According to the problem, the area of the large bubble is equal to the sum of the areas of the small bubbles:

64π = 4nπ

Dividing both sides by 4π, we get:

n = 16

Therefore, there are 16 small bubbles.

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The estimated number of students on the A honor roll who are 8th graders is 126.

Algebra is a branch of mathematics that deals with symbols and the rules for manipulating these symbols. It involves using letters and other symbols to represent numbers and quantities in equations and formulas.

The main goal of algebra is to find the value of an unknown quantity, called a variable, by using known quantities and mathematical operations such as addition, subtraction, multiplication, division, and exponentiation. Algebraic expressions can be solved using various techniques, including simplification, factoring, and solving equations.

The total number of students on the A honor roll is given by adding the number of students in each grade:

Total = 15 (6th grade) + 11 (7th grade) + 14 (8th grade) = 40

To find the proportion of students who are in 8th grade, we can divide the number of 8th graders by the total number of students:

Proportion of 8th graders = 14/40 = 0.35

To estimate the number of students on the A honor roll who are 8th graders, we can multiply the proportion of 8th graders by the total number of students on the A honor roll:

Estimated number of 8th graders = 0.35 x 360 = 126

Therefore, the estimated number of students on the A honor roll who are 8th graders is 126.

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Answer: If 60% of the members are males, then 40% of the members are females. We can calculate the number of males and females as follows:

Number of males = 60% of 200 = 0.6 * 200 = 120

Number of females = 40% of 200 = 0.4 * 200 = 80

To find out how many percent more males there are than females, we can use the following formula:

% more males = (number of males - number of females) / number of females * 100%

Substituting the values we found, we get:

% more males = (120 - 80) / 80 * 100% = 50%

Therefore, there are 50% more males than females in the club.

Step-by-step explanation:

Answer: 30.4

Step-by-step explanation:

Answer:

$8.73 --> 8.73

Step-by-step explanation:

We need to add their costs together to find the total price of the three items.

The cost of Bagels is given as $2.17.

The cost of Cream Cheese is given as $2.82.

The cost of Raisins is given as $3.74.

Adding these three costs together gives us:

$2.17 + $2.82 + $3.74 = $8.73

Therefore, the total price of the three items is $8.73.

The True statement is parallelogram DEFG is the pre-image because it is not the result of the transformation.

What is Transformation?

A point, line, or geometric figure can be transformed in one of four ways, each of which affects the shape and/or location of the object. Pre-Image refers to the object's initial shape, and Image, after transformation, refers to the object's ultimate shape and location.

Given:

Parallelogram DEFG is transformed to parallelogram VSTU.

It changes from parallelogram DEFG to parallelogram VSTU.

According to how it is said, DFEG is the initial parallelogram or pre-image that is changed to create VSTU, VSTU is changed from DEFG.

The following is an accurate statement concerning the transformation:

As the parallelogram DEFG is not the outcome of the transformation, it is the pre-image.

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The correct Question attached here are as follow:

(Q). Parallelogram DEFG is transformed to parallelogram VSTU. Which statement about the transformation is true?

Thus the shaded area of the given rectangular figure is found as : 60 sq. ft.

Area of rectangle = length x width

Complete rectangular area = 12 ft x 7 ft

Complete rectangular area = 84 sq. ft.

Inner rectangular area = 8 ft x 3ft

Inner rectangular area = 24 sq. ft

Shaded area = Complete rectangular area - Inner rectangular area

Shaded area = 84 sq. ft. - 24 sq. ft

Shaded area = 60 sq. ft

Thus the shaded area of the given rectangular figure is found as : 60 sq. ft.

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Complete question:

find the shaded area of the given rectangular figure.

Answer:9

Step-by-step explanation: it’s nine because 6×9 = 54

Answer:

average rate of change = [tex]\frac{1}{2}[/tex]

Step-by-step explanation:

the average rate of change of h(x) in the interval a ≤  x ≤ b , is

[tex]\frac{h(b)-h(a)}{b-a}[/tex]

here the interval is - 2 ≤ x ≤ 2 , then

h(b) = f(2) = [tex]\frac{1}{8}[/tex] (2)³ - 2² = [tex]\frac{1}{8}[/tex] (8) - 4 = 1 - 4 = - 3

h(a) = h(- 2) = [tex]\frac{1}{8}[/tex] (- 2)³ - (- 2)² = [tex]\frac{1}{8}[/tex] (- 8) - 4 = - 1 - 4 = - 5

then average rate of change

= [tex]\frac{-3-(-5)}{2-(-2)}[/tex]

= [tex]\frac{-3+5}{2+2}[/tex]

= [tex]\frac{2}{4}[/tex]

= [tex]\frac{1}{2}[/tex]

Answer: x-3=0

Step-by-step explanation: With the equation it is basic algebra. So right now the equation is x-3=0. You will go plus 3, plus 3 on both sides. That would get rid of your negative 3 and make your 0, 3. So what you should have left is, x=3.

Consider the equation |x-4| = 5. This equation has two solutions since the distance of x from 4 on the number line can be 5 units in either direction, giving x = 9 or x = -1.

What is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.

An absolute value equation is of the form |x| = a, where "a" is a positive number. The absolute value of a number is always non-negative, so the equation |x| = a has two possible solutions, x = a and x = -a.

However, there are three possible cases for how many solutions an absolute value equation could have:

One solution: This occurs when a=0. The only solution is x=0 because |0|=0.

Two solutions: This occurs when a > 0. The two possible solutions are x = a and x = -a, since |a| = a and |-a| = a. For example, the equation |x-3| = 2 has two solutions: x-3 = 2 or x-3 = -2, which gives x = 5 or x = 1.

No solutions: This occurs when a < 0. Since the absolute value of a number is always non-negative, an absolute value equation with a negative number on the right-hand side has no solutions. For example, the equation |x-3| = -2 has no solutions since -2 is negative.

The difference in the number of solutions is due to the nature of absolute values. The absolute value of a number represents the distance of the number from zero on the number line, so an absolute value equation can have two solutions when the distance is equal to a positive number, one solution when the distance is equal to zero, and no solution when the distance is less than zero.

For example, consider the equation |x-4| = 5. This equation has two solutions since the distance of x from 4 on the number line can be 5 units in either direction, giving x = 9 or x = -1.

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Answer: Absolute value equations are important in situations where values cannot be negative, like measuring distance. For example, if you forget which floor your friend lives on and he tells you he's on the fourth floor, and you say you're two floors away, you could be on either the second or sixth floor. Absolute value inequalities are important in determining margins of error or tolerance, especially in manufacturing.

Step-by-step explanation:

When solving an absolute value equation, three possible scenarios could occur. The first scenario is when the absolute value expression equals a positive number. In this case, there will be two solutions, one positive and one negative. The second scenario is when the absolute value expression equals zero. In this case, there will be only one solution, which is zero. The third and final scenario is when the absolute value expression equals a negative number. In this case, there are no solutions, as the absolute value of any number is always non-negative.

The reason there are differences in the number of solutions for each case is due to the nature of absolute value. Absolute value always returns a non-negative value, regardless of the sign of the number inside the absolute value expression. Therefore, when the absolute value expression is positive, there are two possible solutions, one positive and one negative. When the expression equals zero, there is only one solution, which is zero. And when the expression is negative, there are no solutions, as there cannot be a negative absolute value.

Let's assume that Terrell attends x number of classes in a month. Then, the total cost of the first membership plan would be:

Cost of the first membership plan = $30 + $1 * x

Similarly, the total cost of the second membership plan would be:

Cost of the second membership plan = $15 + $4 * x

As per the problem statement, both membership plans cost the same when Terrell attends a certain number of classes in a month. So, we can equate the above two expressions and solve for x:

$30 + $1 * x = $15 + $4 * x

$2 * x = $15

x = 7.5

Since the number of classes cannot be a fraction, we can round up to the nearest integer, which is 8. Therefore, Terrell needs to attend 8 classes per month to make both membership plans cost the same.

To find the total amount, we can substitute x = 8 in either of the above expressions:

Total amount = $30 + $1 * 8 = $38

Therefore, Terrell needs to attend 8 classes per month, and the total amount would be $38.

Angle A is the right angle, so the trigonometric ratio we get is sin(LA) = 8/17, cos(LA) = 15/17, tan(LA) = 8/15, sin(LB) = 15/17, cos(LB) = 8/17, tan(LB) = 15/8

Sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant are the six trigonometric ratios. (sec). A branch of mathematics called trigonometry in geometry works with the sides and angles of a right-angled triangle. Trig ratios are therefore assessed in relation to sides and angles.

The right triangle with sides that are 8, 15, and 17 in length needs to be labeled as follows in order to use trigonometry ratios.

       B

      /|

   17/ |

    /  |

   /___|__

  A    C  15

where the right angle A is. The chart can then be filled out as follows:

angle   opp     adj     hyp     sin     cos     tan

LA      8       15      17      8/17    15/17   8/15

LB      15      8       17      15/17   8/17    15/8

The tangent is opposite/adjacent, the sine is adjacent/hypotenuse, and the cosine is opposite/hypotenuse.

The trigonometry ratios for the right triangle with sides that are 8, 15, and 17 in length are as follows.

sin(LA) = 8/17

cos(LA) = 15/17

tan(LA) = 8/15

sin(LB) = 15/17

cos(LB) = 8/17

tan(LB) = 15/8

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personal experience based .

maths gives us a way to understanding patterns ,define relationships , and predict the future.

One of my friends wanted to host a dinner party at her house, and she asked me to help her plan the menu. She told me that she was expecting around 10 guests, and she wanted to make sure that she had enough food for everyone. The difficult part was that she had a limited budget and wanted to keep the cost of ingredients low.

Mathematical approach:

To help my friend plan the menu, I used math to estimate the amount of food we needed to buy. I researched online to find the average portion sizes for the dishes we were planning to serve and calculated the total amount of ingredients needed based on the number of guests. Then, I compared the cost of the ingredients at different grocery stores to find the best deals and estimated the total cost of the meal.

Outcome:

By using math, we were able to plan a menu that was within my friend's budget and had enough food for all the guests. We were also able to find the best deals on ingredients, which helped us save money.

Approach for next time:

Next time, I would try to involve my friend more in the mathematical calculations to make sure she understands how to plan a meal within her budget. I would also consider making a list of alternative dishes that we could serve in case we were unable to find a certain ingredient or if it was too expensive.

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Farmers Products Inc. should disclose a contingent liability in its 2016 financial statements for the lawsuit filed against them due to a collision caused by one of their delivery truck drivers.

Based on the information provided, it appears that as of the date of the financial statements (March 3, 2017), Farmers Products would need to disclose a contingent liability related to the lawsuit filed against them by the other driver.

A contingent liability is a potential liability that may arise from past events but the outcome is uncertain and will depend on future events. In this case, the lawsuit filed against Farmers Products by the other driver represents a potential liability that may result in damages being awarded against the company.

Under accounting standards, a contingent liability should be disclosed in the notes to the financial statements if it is probable that a liability has been incurred and the amount of the liability can be reasonably estimated. In this case, it is probable that Farmers Products may be liable for damages resulting from the accident and the estimated damages fall within a reasonable range of $6,000 to $10,000.

Therefore, in the notes to its 2016 financial statements, Farmers Products should disclose the existence of the lawsuit and the potential liability that may result. The disclosure should also include an estimate of the potential damages, if any, and any other relevant information about the lawsuit.

The question is incomplete; please see below for the whole question -

On December 4, 2016, Dan Johnson, a Farmers Products Inc. delivery truck driver, ran a stop sign and collided with another vehicle. On January 8, 2017, the driver of the other car filed a lawsuit against Farmers Products for vehicle damages. Damage to this vehicle was estimated to be between $6,000 and $10,000, with no value within that range being more likely than any other. Farmers Products' 2016 financial statements were released on March 3, 2017.

1. Prepare the disclosures and/or journal entries that Farmers Products should include in its financial statements for the fiscal year ending December 31, 2016.2. How would the disclosures and/or journal entries alter if Farmers Products employed IFRS versus US GAAP?

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the gcf of 3, 15, and 35 is 1.

Answer: 1

Step-by-step explanation:

GCF means greatest common factor.

And the greatest common factor of 3, 15 and 35 would be 1 since

no other number is common between them.

3 * 1 = 3

15 * 1 = 15

35 * 1 =35

Answer:

D. -7.2y - 49.5  is the correct answer.

Step-by-step explanation:

Distributing the 3 to the terms inside the parenthesis, we get:

3(-2.4y - 16.5) = -7.2y - 49.5

-2.4 x 3 = -7.2

16.5 x 3 = 49.5

so the expression that is equivalent to 3(-2.4y - 16.5) is -7.2y - 49.5

hope this helps

Answer: 1/3

Step-by-step explanation: To do complex equations like this try using a calculator

Answer:

She needs to win 6 more consecutive tournament games.

Step-by-step explanation:

[tex] \frac{3 + x}{4 + x} = \frac{9}{10} [/tex]

[tex]10(3 + x) = 9(4 + x)[/tex]

[tex]30 + 10x = 36 + 9x[/tex]

[tex]x = 6[/tex]

The inverses of g and h give:

Here we have the function:

g(x) = -2x + 3

If its inverse is g⁻¹(x), then the composition must be equal to the identity, so we can write:

g( g⁻¹(x)) = x

-2*g⁻¹(x) + 3 = x

g⁻¹(x) = (x - 3)/-2

g⁻¹(x) = - (x - 3)/2

Now we also want to get:

(g *g⁻¹)(-7)

That is the product of the two functions evaluated in -7.

(g *g⁻¹)(-7) = (-2*-7 + 3)*-(-7 - 3)/2 = 85

Now for h(x), we want to get h⁻¹(9)

By looking at the table, we can see that h(-7) = 9

Then the inverse is h⁻¹(9) = -7

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The probabilities of Brian and leo  being assigned a window seat on each flight are 1/9

The probability that Brian is assigned a window seat on the flight to his grandmother's house is:

50/150 = 1/3

The probability that LEO is assigned a window seat on the flight home from his grandmother's house is also:

50 window seats/ 150 seats = 1/3

The probability that both Brian and Leo are both assigned window seats on the way to their grandmother's house is:

50 window seats/150 seats  *  49 window seats/  149 seats  = 1/9

Take note that Brian and Leo's chances of getting a window seat on each flight are independent, so we can simply multiply the odds to determine the likelihood of both happening.

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The experimental probability that the card selected was a K or 6 is [tex]3/20[/tex].

The answer is "three over twenty."

The frequency of K and 6 in the table are 8 and 7 respectively. Therefore, the total number of times a K or 6 was drawn is [tex]8 + 7 = 15[/tex].

The total number of draws was 100, so the probability of drawing a K or 6 on any one draw is:

Probability of K or 6 =[tex](Frequency of K + Frequency of 6) / Total number of draws[/tex]

[tex]= (8 + 7) / 100\\= 15 / 100\\= 3 / 20[/tex]

So the experimental probability that the card selected was a K or 6 is [tex]3/20[/tex].

Therefore, the answer is "three over twenty."

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The point-slope form of the equation that represents the data set is y - 56 = -5(x - 6), or y = -5x + 86.

We are given two points: (6,56) and (12,26) from the data set. We can use the point-slope form of a linear equation to find an equation that represents the data set.

y - y1 = m(x - x1)

where (x1, y1) is a point on the line and m is the slope of the line.

To find the slope, we use the two given points:

m = (y2 - y1) / (x2 - x1)

m = (26 - 56) / (12 - 6)

m = -30 / 6

m = -5

Now that we have the slope, we can use one of the given points, say (6, 56), to write the point-slope equation:

y - y1 = m(x - x1)

y - 56 = -5(x - 6)

y - 56 = -5x + 30

y = -5x + 86

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